Chapter 11: Problem 7
Let \(\mathbf{u}=\langle 3,-2\rangle\) and \(\mathbf{v}=\langle-2,5\rangle .\) Find the (a) component form and (b) magnitude (length) of the vector. $$\frac{3}{5}\mathbf{u}+\frac{4}{5} \mathbf{v}$$
Short Answer
Expert verified
Component form: \( \langle \frac{1}{5}, \frac{14}{5} \rangle \). Magnitude: \( \frac{\sqrt{197}}{5} \).
Step by step solution
01
Scale Vector u
First, find the scaled version of vector \( \mathbf{u} = \langle 3, -2 \rangle \) by multiplying each component by \( \frac{3}{5} \). Follow the formula for scaling vectors: \( k\mathbf{a} = \langle kx, ky \rangle \). Thus, \( \frac{3}{5}\mathbf{u} = \left\langle \frac{3}{5} \times 3, \frac{3}{5} \times -2 \right\rangle = \langle \frac{9}{5}, -\frac{6}{5} \rangle \).
02
Scale Vector v
Next, scale vector \( \mathbf{v} = \langle -2, 5 \rangle \) by multiplying each component by \( \frac{4}{5} \). So, \( \frac{4}{5}\mathbf{v} = \left\langle \frac{4}{5} \times -2, \frac{4}{5} \times 5 \right\rangle = \langle -\frac{8}{5}, \frac{20}{5} \rangle \).
03
Add Scaled Vectors
Now add the scaled vectors from Step 1 and Step 2 to find the resulting vector. Use vector addition by adding the corresponding components: \( \left\langle \frac{9}{5}, -\frac{6}{5} \right\rangle + \left\langle -\frac{8}{5}, \frac{20}{5} \right\rangle = \left\langle \frac{9}{5} - \frac{8}{5}, -\frac{6}{5} + \frac{20}{5} \right\rangle = \langle \frac{1}{5}, \frac{14}{5} \rangle \).
04
Find the Magnitude
To find the magnitude of a vector \( \langle x, y \rangle \), use the formula \( \sqrt{x^2 + y^2} \). For vector \( \langle \frac{1}{5}, \frac{14}{5} \rangle \), the magnitude is \( \sqrt{\left(\frac{1}{5}\right)^2 + \left(\frac{14}{5}\right)^2} \). Calculate this as: \( \sqrt{\frac{1}{25} + \frac{196}{25}} = \sqrt{\frac{197}{25}} = \frac{\sqrt{197}}{5} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Addition
Vector addition is a fundamental operation in vector mathematics that involves combining two or more vectors to produce a resultant vector. When we add vectors, we simply add their corresponding components. For example, if you have two vectors, say \( \mathbf{a} = \langle a_1, a_2 \rangle \) and \( \mathbf{b} = \langle b_1, b_2 \rangle \), their sum is found as:
- \( \mathbf{a} + \mathbf{b} = \langle a_1 + b_1, a_2 + b_2 \rangle \)
- \( \langle \frac{9}{5}, -\frac{6}{5} \rangle + \langle -\frac{8}{5}, \frac{20}{5} \rangle \)
- \( = \langle \frac{9}{5} - \frac{8}{5}, -\frac{6}{5} + \frac{20}{5} \rangle \)
- \( = \langle \frac{1}{5}, \frac{14}{5} \rangle \)
Scalar Multiplication
Scalar multiplication involves multiplying a vector by a scalar (a real number). This operation scales a vector by stretching or compressing its magnitude, without changing its direction (unless the scalar is negative, which reverses it).
- Given a vector \( \mathbf{v} = \langle x, y \rangle \) and a scalar \( k \), the scalar multiplication is \( k \mathbf{v} = \langle kx, ky \rangle \).
- \( \frac{3}{5} \mathbf{u} = \langle \frac{3}{5} \times 3, \frac{3}{5} \times -2 \rangle = \langle \frac{9}{5}, -\frac{6}{5} \rangle \)
- \( \frac{4}{5} \mathbf{v} = \langle \frac{4}{5} \times -2, \frac{4}{5} \times 5 \rangle = \langle -\frac{8}{5}, \frac{20}{5} \rangle \)
Magnitude of a Vector
The magnitude of a vector, also known as its length, is a measure of how long the vector is. It is calculated using the Pythagorean theorem. For a vector \( \mathbf{v} = \langle x, y \rangle \), the formula to find the magnitude \( \| \mathbf{v} \| \) is:
- \( \| \mathbf{v} \| = \sqrt{x^2 + y^2} \)
- Calculate: \( \sqrt{\left(\frac{1}{5}\right)^2 + \left(\frac{14}{5}\right)^2} \)
- Result: \( = \sqrt{\frac{1}{25} + \frac{196}{25}} = \sqrt{\frac{197}{25}} \)
- Simplified: \( = \frac{\sqrt{197}}{5} \)