Chapter 10: Problem 7
Find the polar coordinates, \(0 \leq \theta<2 \pi\) and \(r \geq 0,\) of the following points given in Cartesian coordinates. a. (1,1) b. (-3,0) c. \((\sqrt{3},-1)\) d. (-3,4)
Short Answer
Expert verified
a. \((\sqrt{2}, \frac{\pi}{4})\), b. (3, \pi), c. (2, \frac{11\pi}{6}), d. (5, 2.2143)\)
Step by step solution
01
Understand Polar Coordinates
Polar coordinates represent a point in a plane using a distance from the origin, denoted by \( r \), and an angle from the positive x-axis, denoted by \( \theta \). For a point \( (x,y) \) in Cartesian coordinates, \( r = \sqrt{x^2 + y^2} \) and \( \theta = \tan^{-1}(\frac{y}{x}) \).
02
Step 2a: Convert (1,1) to Polar Coordinates
For the point \((1,1)\), calculate \( r \) as \( r = \sqrt{1^2 + 1^2} = \sqrt{2} \). Compute the angle \( \theta \) using \( \tan^{-1}(1) = \frac{\pi}{4} \). The polar coordinates are \((\sqrt{2}, \frac{\pi}{4})\).
03
Step 2b: Convert (-3,0) to Polar Coordinates
For the point \((-3,0)\), find \( r = \sqrt{(-3)^2 + 0^2} = 3 \). Since the point lies on the negative x-axis, \( \theta = \pi \). The polar coordinates are \((3, \pi)\).
04
Step 2c: Convert (\(\sqrt{3},-1\)) to Polar Coordinates
For \((\sqrt{3}, -1)\), calculate \( r = \sqrt{(\sqrt{3})^2 + (-1)^2} = 2 \). Compute \( \theta = \tan^{-1}\left(-\frac{1}{\sqrt{3}}\right) = -\frac{\pi}{6} \). Since \( \theta \) must be in the range \(0\) to \(2\pi\), add \(2\pi\) to get \( \theta = \frac{11\pi}{6} \). The polar coordinates are \((2, \frac{11\pi}{6})\).
05
Step 2d: Convert (-3,4) to Polar Coordinates
For the point \((-3, 4)\), calculate \( r = \sqrt{(-3)^2 + 4^2} = 5 \). Compute \( \theta = \tan^{-1}\left(\frac{4}{-3}\right) \). Since the point is in the second quadrant, \( \theta = \pi - \tan^{-1}(\frac{4}{3}) \approx 2.2143 \). The polar coordinates are \( (5, 2.2143) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cartesian Coordinates
Cartesian coordinates are a way to represent points within a plane using a pair of numerical values. These values are known as (x, y) coordinates. In this system:
- The 'x' value specifies the horizontal position of a point, determining how far left or right it is from the y-axis.
- The 'y' value specifies the vertical position of a point, assessing how far up or down it is from the x-axis.
Angle Calculation
Calculating the angle (\(\theta\)) in polar coordinates is crucial because it tells you the rotation from the positive x-axis to reach the point. To find the angle, you use:\[\theta = \tan^{-1}\left(\frac{y}{x}\right)\]This formula determines the angle based on the ratio of the y-coordinate to the x-coordinate.Some important reminders:
- Ensure the angle is within the range from 0 to 2\(\pi\).
- Use the inverse tangent function arctan or \(\tan^{-1}\), which will help determine the angle needed for the direction from the origin.
Quadrant Determination
The Cartesian plane is divided into four quadrants, each representing a different combination of positive and negative x and y coordinates:
- First Quadrant: Both x and y are positive (e.g., (1, 1)).
- Second Quadrant: x is negative and y is positive (e.g., (-3, 4)).
- Third Quadrant: Both x and y are negative.
- Fourth Quadrant: x is positive and y is negative (e.g., \((\sqrt{3}, -1)\)).
Coordinate Conversion
Converting between coordinate systems involves transforming Cartesian coordinates to polar coordinates and vice versa.To change a point from Cartesian (\(x, y\)) to polar coordinates (\(r, \theta\)), follow these steps:
- Calculate the radial coordinate \(r\) using the formula \(r = \sqrt{x^2 + y^2}\).
- Find the angular coordinate \(\theta\) with \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\).