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Give parametric equations and parameter intervals for the motion of a particle in the \(x y\) -plane. Identify the particle's path by finding a Cartesian equation for it. Graph the Cartesian equation. (The graphs will vary with the equation used.) Indicate the portion of the graph traced by the particle and the direction of motion. $$x=-\sec t, \quad y=\tan t, \quad-\pi / 2

Short Answer

Expert verified
The path is a hyperbola given by \(x^2 - y^2 = 1\), traced counterclockwise for \(-\pi/2 < t < \pi/2\).

Step by step solution

01

Parametric Equations and Interval

The given parametric equations are \( x = -\sec t \) and \( y = \tan t \) with the parameter interval \(-\pi/2 < t < \pi/2\). We will use these equations to identify the Cartesian equation describing the particle's path.
02

Relating Parametric Equations to Find Cartesian Equation

We have \( x = -\sec t \), so \( \sec t = -x \). Since \( \sec t = \frac{1}{\cos t} \), it follows that \( \cos t = -\frac{1}{x} \). Similarly, since \( \tan t = \frac{\sin t}{\cos t} \), we have \( y = \tan t = \frac{\sin t}{\cos t} = \frac{\sin t}{-1/x} = -x \sin t \). Also, note that \( 1 + \tan^2 t = \sec^2 t \). Therefore, \( 1 + y^2 = (-x)^2 = x^2 \). This gives us a Cartesian equation of \( 1 + y^2 = x^2 \).
03

Analyzing and Graphing the Cartesian Equation

The Cartesian equation \( 1 + y^2 = x^2 \), can be rewritten as \( x^2 - y^2 = 1 \). This is the equation of a hyperbola centered on the origin with the transverse axis along the x-axis. To determine the particle's motion direction in the plane, we analyze the parameter \( t \): As \( t \) increases from \(-\pi/2\) to \(\pi/2\), the value of \( x = -\sec t \) goes from negative infinity to negative one and back to negative infinity, and \( y = \tan t \) increases from negative infinity through zero to positive infinity. The motion traces the right branch of the hyperbola.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cartesian equation
A Cartesian equation is a mathematical representation that expresses a relationship between coordinates in a plane, usually the x and y coordinates. Unlike parametric equations, which use a third variable—often denoted as t—to express each coordinate separately, a Cartesian equation combines them into a single formula.
- They provide a straightforward way to understand the shape and position of a curve in the plane.
- For example, in this exercise, the parametric equations were converted into the Cartesian equation \(x^2 - y^2 = 1\).
This describes a hyperbola, providing a powerful and consolidated form to depict the particle's path without needing to use the parameter t.
particle motion
Understanding particle motion involves analyzing how an object's position changes over time within a given environment, often expressed through equations. In our example, we use parametric equations to describe this motion in terms of time parameter \(t\).
- The x coordinate \(x = -\sec t\) and the y coordinate \(y = \tan t\) represent how the particle moves in the x and y directions, respectively.
- As \(t\) changes within the interval \(-\pi/2 < t < \pi/2\), the particle traces a specific path.
Thus, analyzing these changes helps to determine the trajectory and behavior of the particle over time, including the specific segment of a hyperbola it follows.
hyperbola
A hyperbola is a type of conic section formed by the intersection of a plane with two equal cones. It has a distinctive open curve shape, differing from other conic sections such as circles and ellipses, which are closed curves.
- The standard equation of a hyperbola centered at the origin can be \(x^2 - y^2 = 1\) or \(y^2 - x^2 = 1\), depending on its orientation.
- Our exercise's Cartesian equation \(x^2 - y^2 = 1\) represents a hyperbola with its transverse axis (the main axis) along the x-axis.
- Hyperbolas have two branches, and in our case, the motion traced by the particle is on one of these branches.
Unlike other curves, hyperbolas have two distinct parts called branches, often implying paths that diverge from a central point, which is crucial when considering particle motion on these curves.
parametric to Cartesian conversion
Parametric to Cartesian conversion involves transforming equations that express points in terms of a third parameter, often time, into a single mathematical expression that depicts the relationship between x and y coordinates.
- This conversion process simplifies analyzing and graphing the path of a particle, making it easier to understand its motion without focusing on the parameter.
- In solving the original problem, parametric equations \(x = -\sec t\) and \(y = \tan t\) were converted to a Cartesian form by leveraging trigonometric identities such as \(1 + \tan^2 t = \sec^2 t\).
- The resulting equation \(x^2 - y^2 = 1\) offers a comprehensive picture of the particle's trajectory.
This conversion is invaluable as it facilitates visualizing the entire pathway the particle takes, which often highlights important geometric features such as symmetry and intercepts not immediately clear in parametric form.

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Most popular questions from this chapter

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