Chapter 1: Problem 9
Sketch the shifted exponential curves. $$y=1-e^{x} \text { and } y=1-e^{-x}$$
Short Answer
Expert verified
Both curves have a horizontal asymptote at y=1 and intersect the y-axis at y=0.
Step by step solution
01
Understand the Basic Exponential Function
Before sketching the shifted curves, recall that the basic exponential function, \( y = e^x \), is a curve that passes through the point (0,1) and increases rapidly as \( x \) increases. Similarly, \( y = e^{-x} \) is a reflection of \( y = e^x \) across the y-axis.
02
Determine the Vertical Shifts
The given functions are shifted versions of the basic exponential function. The expressions \( y = 1 - e^x \) and \( y = 1 - e^{-x} \) imply a vertical shift upwards by 1 unit from the basic curves of \( y = -e^x \) and \( y = -e^{-x} \) respectively.
03
Sketch \( y = 1 - e^x \)
Start from the basic curve of \( y = -e^x \), an exponential decay function. Shift this curve up by 1 unit. This curve will intersect the y-axis at \( y = 0 \) when \( x = 0 \), and approach \( y = 1 \) as \( x \) tends towards \(-\infty\).
04
Sketch \( y = 1 - e^{-x} \)
For \( y = 1 - e^{-x} \), begin with the curve \( y = -e^{-x} \), an exponential growth function. Shift this curve up by 1 unit. It intersects the y-axis at \( y = 0 \) when \( x = 0 \), and approaches \( y = 1 \) as \( x \) tends towards \( \infty \).
05
Check Asymptotic Behavior
Both curves, \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), have a horizontal asymptote at \( y = 1 \) because as \( x \) approaches infinity or negative infinity, \( e^x \) and \( e^{-x} \) approach zero, making \( 1 - e^x \) and \( 1 - e^{-x} \) approach 1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertical Shifts
Vertical shifts are transformations that adjust the position of a function graph up or down on the coordinate plane. These changes are achieved by adding or subtracting a constant to the function. In the context of exponential functions like \( y = e^x \) and \( y = e^{-x} \), a vertical shift can significantly change the graph's appearance without altering its shape.
When we analyze functions such as \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), we notice they result from a vertical shift of 1 unit upwards. This means every point on the graphs of \( y = -e^x \) and \( y = -e^{-x} \) is moved 1 unit higher along the y-axis.
When we analyze functions such as \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), we notice they result from a vertical shift of 1 unit upwards. This means every point on the graphs of \( y = -e^x \) and \( y = -e^{-x} \) is moved 1 unit higher along the y-axis.
- For \( y = 1 - e^x \): The graph initially starts from the basic curve of \( y = -e^x \). It moves up by 1 unit, changing the intersection with the y-axis to \( y = 0 \) when \( x = 0 \).
- For \( y = 1 - e^{-x} \): Similarly, this function starts from \( y = -e^{-x} \), and a shift upwards results in the y-intercept at the same point.
Asymptotic Behavior
The asymptotic behavior of a function describes how the function behaves as it approaches a boundary or a limit, known as an asymptote. For exponential functions, asymptotes are typically horizontal lines that the graph gets infinitely close to but never actually reaches.
For the functions \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), there exists a horizontal asymptote at \( y = 1 \). This behavior happens because:
For the functions \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), there exists a horizontal asymptote at \( y = 1 \). This behavior happens because:
- As \( x \) approaches positive infinity in \( y = 1 - e^{-x} \), the term \( e^{-x} \) approaches zero, thus \( y \) gets closer to 1.
- Conversely, as \( x \) approaches negative infinity for \( y = 1 - e^x \), the term \( e^x \) also approaches zero, causing \( y \) to again approach 1.
Exponential Growth and Decay
Exponential growth and decay describe how quantities change exponentially over time, either increasing or decreasing. The function \( y = e^x \) typifies exponential growth, where values rise rapidly as \( x \) increases. On the flip side, \( y = e^{-x} \) represents exponential decay, where values decrease swiftly as \( x \) increases.
In our specific functions, \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), these basic forms are adjusted through vertical shifts, yet their underlying behavior remains:
In our specific functions, \( y = 1 - e^x \) and \( y = 1 - e^{-x} \), these basic forms are adjusted through vertical shifts, yet their underlying behavior remains:
- In \( y = 1 - e^x \), the function decreases, or decays, as \( x \) increases, moving towards the asymptote \( y = 1 \).
- Conversely, \( y = 1 - e^{-x} \) encapsulates growth as \( x \) increases, as it moves upwards towards the same horizontal asymptote.