/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 65 Which of the sequences \(\left\\... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. $$a_{n}=\frac{n !}{10^{6 n}}$$

Short Answer

Expert verified
The sequence converges to 0.

Step by step solution

01

Understand the sequence

The given sequence is \(a_n = \frac{n!}{10^{6n}}\). This sequence consists of the factorial \(n!\) in the numerator and \(10^{6n}\) in the denominator. As \(n\) increases, the factorial will grow very quickly.
02

Comparing growth rates

We need to compare the growth rates of \(n!\) and \(10^{6n}\). Factorials grow very fast, but in this case, the exponential function \(10^{6n}\) also grows extremely fast. We need to establish if the exponential growth in the denominator outpaces the factorial growth in the numerator.
03

Evaluating convergence using limits

Evaluate \(\lim_{n \to \infty} \frac{n!}{10^{6n}}\). As \(n\) increases, note that each term of the factorial \(n!\) in the numerator grows, but \(10^{6n}\) grows faster for sufficiently large \(n\). Hence, the terms of the sequence \(a_n\) will diminish to zero as \(n\) becomes very large.
04

Applying the Limit Comparison Test

Using the limit comparison test, compare the sequence to a simpler one: \(\frac{n}{10^6}\). As \(n\) becomes large, \(n!\) essentially behaves like \(\left(\frac{n}{e}\right)^n\), and \(10^{6n}\) like \(\left(10^6\right)^n\). Therefore, \(\lim_{n \to \infty} \frac{\left(\frac{n}{e}\right)^n}{(10^6)^n}=0\). Thus, the original sequence converges to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorials
Factorials are a mathematical operation that take a whole number and multiply it by every whole number less than it down to one. For instance, the factorial of 5, represented as 5!, is calculated as 5 × 4 × 3 × 2 × 1 = 120. This results in extremely large numbers as the input number increases.

The formula for calculating the factorial of a number \( n \) is:
  • \( n! = n \times (n-1) \times (n-2) \times \, ... \, \times 1 \)
Factorials are used in various fields including permutations, combinations, and in defining exponential growth in mathematics. They are particularly significant in sequences and series problems, where they can contribute to extremely rapid growth in terms.

In our sequence \( a_n = \frac{n!}{10^{6n}} \), the factorial in the numerator appears to grow rapidly. But in contrast to exponential terms, such as \( 10^{6n} \), factorial growth is outpaced when both terms are large. This quick growth makes factorials an important consideration in convergence tests like the Limit Comparison Test.
Exponential Growth
Exponential growth describes a process where the rate of growth is directly proportional to the current size. This type of growth is common in various real-world phenomena such as populations, investments, and more. Mathematically, exponential growth can often be expressed in the form of \( a^n \), where \( a \) is the base and \( n \) is the exponent.

Exponential functions, like \( 10^{6n} \), grow extremely fast as \( n \) increases. In sequences involving exponential terms, these terms will typically dominate over polynomial or even factorial growth in long-term behavior.

In the sequence \( a_n = \frac{n!}{10^{6n}} \), the term \( 10^{6n} \) in the denominator grows exponentially. This rapid growth in the denominator causes the overall value of the sequence term \( a_n \) to decrease, thereby contributing to the convergence of the sequence to zero as \( n \) approaches infinity.
Limit Comparison Test
The Limit Comparison Test is a method used to determine the convergence or divergence of certain series. This test is particularly useful when dealing with sequences or series that are complex, involving factorials, exponential functions, or other complicated expressions.

To use the Limit Comparison Test, you select a comparison sequence that simplifies the original sequence or series. You then take the limit of the ratio of these sequences as \( n \) approaches infinity:
  • \( \lim_{n \to \infty} \frac{a_n}{b_n} \)
If this limit evaluates to a positive finite number, then both series \( a_n \) and \( b_n \) will either both converge or both diverge.

In the exercise, we compared the sequence \( a_n = \frac{n!}{10^{6n}} \) to a simpler sequence \( b_n = \frac{n}{10^6} \). The sequence involving \( n! \) behaves like \( \left(\frac{n}{e}\right)^n \) for large \( n \), while the sequence \( 10^{6n} \) behaves like \( (10^6)^n \), creating a favorable comparison for convergence determination. Since the limit of this ratio is 0, it indicates that the original sequence \( a_n \) converges to zero, demonstrating the power of the Limit Comparison Test in handling factorial and exponential growth.

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Most popular questions from this chapter

Determine if the sequence is monotonic and if it is bounded. $$a_{n}=2-\frac{2}{n}-\frac{1}{2^{n}}$$

If \(\Sigma a_{n}\) converges and \(\Sigma b_{n}\) diverges, can anything be said about their term-by-term sum \(\Sigma\left(a_{a}+b_{n}\right) ?\) Give reasons for your answer.

It is not yet known whether the series $$ \sum_{n=1}^{\infty} \frac{1}{n^{3} \sin ^{2} n} $$converges or diverges. Use a CAS to explore the behavior of the series by performing the following steps. a. Define the sequence of partial sums $$ s_{k}=\sum_{n=1}^{k} \frac{1}{n^{3} \sin ^{2} n} $$ What happens when you try to find the limit of \(s_{k}\) as \(k \rightarrow \infty ?\) Does your CAS find a closed form answer for this limit? b. Plot the first 100 points \(\left(k, s_{k}\right)\) for the sequence of partial sums. Do they appear to converge? What would you estimate the limit to be? c. Next plot the first 200 points \(\left(k, s_{k}\right) .\) Discuss the behavior in your own words. d. Plot the first 400 points \(\left(k, s_{k}\right) .\) What happens when \(k=355 ?\) Calculate the number \(355 / 113 .\) Explain from you calculation what happened at \(k=355 .\) For what values of \(k\) would you guess this behavior might occur again?

Taylor's formula with \(n=1\) and \(a=0\) gives the linearization of a function at \(x=0 .\) With \(n=2\) and \(n=3\) we obtain the standard quadratic and cubic approximations. In these exercises we explore the errors associated with these approximations. We seek answers to two questions: a. For what values of \(x\) can the function be replaced by each approximation with an error less than \(10^{-2} ?\). b. What is the maximum error we could expect if we replace the function by each approximation over the specified interval? Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step \(I:\) Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(x=0\) Step 3: Calculate the \((n+1)\) st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M .\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=(1+x)^{3 / 2}, \quad-\frac{1}{2} \leq x \leq 2$$

Which of the sequences converge, and which diverge? Give reasons for your answers. $$a_{n}=\frac{4^{n+1}+3^{n}}{4^{n}}$$

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