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Which series converge, and which diverge? Give reasons for your answers. If a series converges, find its sum. $$\sum_{n=1}^{\infty} \frac{2^{n}+3^{n}}{4^{n}}$$

Short Answer

Expert verified
The series converges and its sum is 4.

Step by step solution

01

Break Down the Series

The given series is \( \sum_{n=1}^{\infty} \frac{2^{n}+3^{n}}{4^{n}} \). This can be split into two separate series: \( \sum_{n=1}^{\infty} \frac{2^{n}}{4^{n}} \) and \( \sum_{n=1}^{\infty} \frac{3^{n}}{4^{n}} \). We'll analyze each part separately to determine convergence.
02

Analyze the First Series

Consider \( \sum_{n=1}^{\infty} \frac{2^{n}}{4^{n}} \). Simplify the terms: \( \frac{2^{n}}{4^{n}} = \left( \frac{2}{4} \right)^{n} = \left( \frac{1}{2} \right)^{n} \). This is a geometric series with first term \( a = \frac{1}{2} \) and common ratio \( r = \frac{1}{2} \). Since \( |r| < 1 \), the series converges.
03

Find the Sum of the First Series

For a convergent geometric series \( \sum_{n=1}^{\infty} ar^n \), the sum is \( S = \frac{a}{1-r} \). Here, \( a = \frac{1}{2} \) and \( r = \frac{1}{2} \), so the sum is \( S = \frac{\frac{1}{2}}{1-\frac{1}{2}} = 1 \).
04

Analyze the Second Series

Consider \( \sum_{n=1}^{\infty} \frac{3^{n}}{4^{n}} \). Simplify the terms: \( \frac{3^{n}}{4^{n}} = \left( \frac{3}{4} \right)^{n} \). This is a geometric series with first term \( a = \frac{3}{4} \) and common ratio \( r = \frac{3}{4} \). Since \( |r| < 1 \), the series converges.
05

Find the Sum of the Second Series

For the convergent geometric series \( \sum_{n=1}^{\infty} ar^n \), the sum is \( S = \frac{a}{1-r} \). Here, \( a = \frac{3}{4} \) and \( r = \frac{3}{4} \), so the sum is \( S = \frac{\frac{3}{4}}{1-\frac{3}{4}} = 3 \).
06

Find the Sum of the Original Series

Since both components of the series, \( \sum_{n=1}^{\infty} \left( \frac{1}{2} \right)^{n} \) and \( \sum_{n=1}^{\infty} \left( \frac{3}{4} \right)^{n} \), converge, the original series converges as well. The sum of the original series is the sum of the individual series: \( 1 + 3 = 4 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence of Series
Convergence is a key concept when exploring series in mathematics. A series is considered convergent if the sum of its infinite terms approaches a finite number. This behavior is vital because it tells us whether further terms of the series will accumulate into something meaningful or simply diverge towards infinity.

To check if a series converges, especially a geometric series, we look at the common ratio, denoted as \( r \). If the absolute value of \( r \) is less than one \( (|r| < 1) \), the series will converge. This means that as we add more terms, they contribute less and less, eventually stabilizing into a fixed sum.

For instance, with the given exercise, two separate geometric series arise: \( \sum_{n=1}^{\infty} \left( \frac{1}{2} \right)^{n} \) with \( r = \frac{1}{2} \), and \( \sum_{n=1}^{\infty} \left( \frac{3}{4} \right)^{n} \) with \( r = \frac{3}{4} \). Since both ratios are less than one, each series converges, and thus, their combined effect results in a convergent series.
Infinite Series
An infinite series is essentially a sum that continues indefinitely, adding an endless sequence of terms. While this might seem daunting, infinite series often lead to fascinating results, especially when dealing with geometric series. The behavior of such sums largely depends on the properties of the terms within them.

In our example, the series \( \sum_{n=1}^{\infty} \frac{2^{n}+3^{n}}{4^{n}} \) is infinite, as suggested by the notation. Infinite series are represented generally by \( \sum_{n=1}^{\infty} a_n \), indicating the summation of terms starting from some initial number \( n = 1 \) to infinity.

Understanding infinite series is crucial in calculus and analysis since many functions can be expressed or approximated by them. In physics and engineering, they are often used to model different kinds of processes, like waves or signals. They bring insight into how functions behave and how certain solutions are constructed or derived.
Series Summation
Series summation refers to the process of adding terms in a sequence to find their cumulative value. The sum of a geometric series, in particular, can be elegantly deduced when the series converges.

For geometric series, a convenient formula is used: If \( a \) is the first term and \( r \) is the common ratio, the sum \( S \) of an infinite geometric series is given by the formula \( S = \frac{a}{1-r} \). Provided \( |r| < 1 \), this formula allows us to compute the sum directly.

In the exercise at hand, the two separate geometric series are summed using this formula:
  • The first series \( \sum_{n=1}^{\infty} \left( \frac{1}{2} \right)^{n} \) results in a sum of 1.
  • The second series \( \sum_{n=1}^{\infty} \left( \frac{3}{4} \right)^{n} \) produces a sum of 3.
Adding these values gives us the sum of the original series as 4. Understanding series summation helps in simplifying complex problems to find definite solutions.

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Most popular questions from this chapter

A patient takes a 300 mg tablet for the control of high blood pressure every morning at the same time. The concentration of the drug in the patient's system decays exponentially at a constant hourly rate of \(k=0.12\) a. How many milligrams of the drug are in the patient's system just before the second tablet is taken? Just before the third tablet is taken? b. In the long run, after taking the medication for at least six months, what quantity of drug is in the patient's body just before taking the next regularly scheduled morning tablet?

Show by example that \(\Sigma\left(a_{n} / b_{n}\right)\) may diverge even though \(\Sigma a_{n}\) and \(\Sigma b_{n}\) converge and no \(b_{n}\) equals 0

It is not yet known whether the series $$ \sum_{n=1}^{\infty} \frac{1}{n^{3} \sin ^{2} n} $$converges or diverges. Use a CAS to explore the behavior of the series by performing the following steps. a. Define the sequence of partial sums $$ s_{k}=\sum_{n=1}^{k} \frac{1}{n^{3} \sin ^{2} n} $$ What happens when you try to find the limit of \(s_{k}\) as \(k \rightarrow \infty ?\) Does your CAS find a closed form answer for this limit? b. Plot the first 100 points \(\left(k, s_{k}\right)\) for the sequence of partial sums. Do they appear to converge? What would you estimate the limit to be? c. Next plot the first 200 points \(\left(k, s_{k}\right) .\) Discuss the behavior in your own words. d. Plot the first 400 points \(\left(k, s_{k}\right) .\) What happens when \(k=355 ?\) Calculate the number \(355 / 113 .\) Explain from you calculation what happened at \(k=355 .\) For what values of \(k\) would you guess this behavior might occur again?

In each of the geometric series, write out the first few terms of the series to find \(a\) and \(r\), and find the sum of the series. Then express the inequality \(|r|<1\) in terms of \(x\) and find the values of \(x\) for which the inequality holds and the series converges. $$\sum_{n=0}^{\infty} 3\left(\frac{x-1}{2}\right)^{n}$$

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L ?\) b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$a_{n}=n \sin \frac{1}{n}$$

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