/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Which of the series in Exercises... [FREE SOLUTION] | 91Ó°ÊÓ

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Which of the series in Exercises \(55-62\) converge, and which diverge? Give reasons for your answers. $$\sum_{n=1}^{\infty} \frac{n^{n}}{\left(2^{n}\right)^{2}}$$

Short Answer

Expert verified
The series diverges by the Ratio Test.

Step by step solution

01

Write the Series in a Simplified Form

Starting with the given series, we note that the expression can be slightly simplified for analysis. The series given is: \( \sum_{n=1}^{\infty} \frac{n^{n}}{(2^{n})^{2}} \). We can rewrite the denominator power as: \( \sum_{n=1}^{\infty} \frac{n^{n}}{2^{2n}} \).
02

Simplify the Expression

The current series is expressed as \( \sum_{n=1}^{\infty} \frac{n^{n}}{4^{n}} \) because \( (2^{n})^{2} = 4^{n} \). This expression will be analyzed further to determine convergence or divergence.
03

Apply the Ratio Test

Use the Ratio Test to determine the behavior of the series. Compute the limit of the absolute value of the ratio of consecutive terms: \[\lim_{{n \to \infty}} \left| \frac{n^{n+1}}{4^{n+1}} \div \frac{n^{n}}{4^{n}} \right| = \lim_{{n \to \infty}} \left(\frac{n^{n+1}}{4^{n+1}} \times \frac{4^{n}}{n^{n}}\right)\]Simplifying the ratio, we obtain:\[\lim_{{n \to \infty}} \frac{n^{n+1}}{4 \cdot n^{n}} = \lim_{{n \to \infty}} \frac{n \cdot n^{n}}{4 \cdot n^{n}} = \lim_{{n \to \infty}} \frac{n}{4}\]As \( n \to \infty \), this limit clearly diverges (approaches infinity).
04

Conclusion on Convergence or Divergence

Given that the limit goes to infinity, the series does not satisfy the condition for convergence in the ratio test (i.e., the limit \(< 1\)). Hence, the series diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ratio Test
The Ratio Test is a powerful tool in calculus used to determine the convergence or divergence of infinite series. It involves analyzing the ratio of consecutive terms in a series. For a series \( \sum a_n \), the test involves the following steps:
  • Compute the limit \( L = \lim_{{n \to \infty}} \left| \frac{a_{n+1}}{a_n} \right| \)
  • If \( L < 1 \), the series converges absolutely.
  • If \( L > 1 \) or the limit is infinite, the series diverges.
  • If \( L = 1 \), the test is inconclusive, and other methods may be needed.
In our example, applying the Ratio Test involved simplifying the ratio of consecutive terms of the series \( \sum \frac{n^n}{4^n} \) and examining its limit. The computed limit \( \lim_{{n \to \infty}} \frac{n}{4} \) goes to infinity, which indicates divergence, as expected when \( L > 1 \). The ease in applying the Ratio Test lies in the simplicity of handling powers and factorial-like terms.
Divergence
Divergence in series occurs when the series does not settle towards a specific value as more terms are added. Rather than approaching a finite sum, divergent series grow indefinitely or oscillate without approaching a single value. This can result in the partial sums of the series increasing beyond any bound or oscillating without end.
To check for divergence, conditions from specific tests like the Ratio Test are often employed. If the test's conditions, such as in the ratio result yielding a limit greater than 1, reveal an ever-increasing sequence, divergence is confirmed.
For our series, the limit resulting from the Ratio Test was \( \lim_{{n \to \infty}} \frac{n}{4} \), which grows beyond any limit as \( n \rightarrow \infty \). This verified the series' divergence. Divergence indicates that summing the series indefinitely will not yield a finite result.
Calculus
Calculus, particularly infinite series calculus, plays a critical role in understanding how different mathematical series behave over their domain. It helps us not only check convergence or divergence but also gives insight into how rapidly sequences grow or shrink.
In handling series, calculus uses various tests, such as the Ratio Test or Root Test, as well as notions like limits and derivatives, allowing more complex series to be analyzed efficiently. It can connect the abstract nature of infinity with tangible outcomes, ensuring that the sum of infinite terms reaches a meaningful and practical conclusion.
For instance, in our given series \( \sum \frac{n^n}{4^n} \), calculus tools like simplifying expressions and applying limits were employed. These strategies enable handling and interpreting infinite sequences, aiding in making sound conclusions about series like convergence and divergence in a manageable way. Calculus provides the foundational rules and methods essential for tackling intricate mathematical problems such as this.

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