Chapter 9: Problem 59
Which series converge, and which diverge? Give reasons for your answers. If a series converges, find its sum. $$\sum_{n=0}^{\infty} \frac{2^{n}-1}{3^{n}}$$
Short Answer
Expert verified
The series converges and its sum is \( \frac{3}{2} \).
Step by step solution
01
Identify the Series
We need to determine whether the series \( \sum_{n=0}^{\infty} \frac{2^n - 1}{3^n} \) converges or diverges. This is a series where each term is defined as \( a_n = \frac{2^n - 1}{3^n} \).
02
Split the Series
Separate the series into two recognizable geometric series: \( \sum_{n=0}^{\infty} \frac{2^n}{3^n} - \sum_{n=0}^{\infty} \frac{1}{3^n} \). This uses the fact that the terms can be rewritten as a difference.
03
Evaluate the First Geometric Series
Consider the series \( \sum_{n=0}^{\infty} \left( \frac{2}{3} \right)^n \). This is a geometric series with a common ratio of \( r = \frac{2}{3} \) and first term \( a = 1 \). Since \( |r| < 1 \), the series converges. The sum of this geometric series is calculated using the formula \( S = \frac{a}{1 - r} = \frac{1}{1 - \frac{2}{3}} = 3 \).
04
Evaluate the Second Geometric Series
Consider the second series \( \sum_{n=0}^{\infty} \left( \frac{1}{3} \right)^n \). This is another geometric series with common ratio \( r = \frac{1}{3} \) and first term \( a = 1 \). Since \( |r| < 1 \), it converges to \( S = \frac{1}{1 - \frac{1}{3}} = \frac{3}{2} \).
05
Combine the Results
Since both series are convergent, we can find the sum of the original series by subtracting the sum of the second series from the first: \( 3 - \frac{3}{2} = \frac{3}{2} \).
06
Conclusion on Convergence
The series \( \sum_{n=0}^{\infty} \frac{2^n - 1}{3^n} \) converges, and its sum is \( \frac{3}{2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a special type of series where each term is obtained by multiplying the previous term by a fixed number, called the common ratio. The general form of a geometric series is given by:
A geometric series converges if the absolute value of the common ratio is less than 1, that is, \( |r| < 1 \). Its sum can be calculated using the formula:\[S = \frac{a}{1 - r}\]Because geometric series have a predictable pattern, they are easier to solve than some other types of series.
- The first term is represented as \( a \).
- The common ratio, denoted as \( r \), is the fixed number multiplied to get subsequent terms.
A geometric series converges if the absolute value of the common ratio is less than 1, that is, \( |r| < 1 \). Its sum can be calculated using the formula:\[S = \frac{a}{1 - r}\]Because geometric series have a predictable pattern, they are easier to solve than some other types of series.
Convergence Tests
When studying series, determining whether a series converges or diverges is crucial. Convergence tests provide tools to analyze the behavior of series.
For geometric series, the convergence test focuses on the common ratio \( r \):
For geometric series, the convergence test focuses on the common ratio \( r \):
- If \( |r| < 1 \), the series converges and has a definite sum.
- If \( |r| \geq 1 \), the series diverges and does not approach a finite value.
Infinite Series
An infinite series is a sum of infinitely many terms, written in the form \( \sum_{n=0}^{ \infty} a_n \), where \( a_n \) represents each term. A crucial aspect of an infinite series is whether it converges to a finite sum as more terms are added.
In the realm of mathematics, we often ask if the infinite sum settles to a particular value, known as convergence, or if it continues to grow indefinitely, known as divergence.
Geometric series are a subset where the terms form a geometric progression. If the conditions for convergence are met, they provide an elegant example of how an infinite number of terms can add up to a finite sum. This characteristic makes them an important tool in mathematical analysis.
In the realm of mathematics, we often ask if the infinite sum settles to a particular value, known as convergence, or if it continues to grow indefinitely, known as divergence.
Geometric series are a subset where the terms form a geometric progression. If the conditions for convergence are met, they provide an elegant example of how an infinite number of terms can add up to a finite sum. This characteristic makes them an important tool in mathematical analysis.
Sum of Series
Finding the sum of a series, especially when it's infinite, requires particular techniques and strategies. For a convergent geometric series, the sum can be calculated using:\[S = \frac{a}{1 - r}\]where \( a \) is the first term and \( r \) is the common ratio with \( |r| < 1 \).
For the series \( \sum_{n=0}^{ \infty} \frac{2^n - 1}{3^n} \), the sum is determined by breaking it into two separate geometric series:
For the series \( \sum_{n=0}^{ \infty} \frac{2^n - 1}{3^n} \), the sum is determined by breaking it into two separate geometric series:
- \( \sum_{n=0}^{ \infty} \left( \frac{2}{3} \right)^n \), yielding 3.
- \( \sum_{n=0}^{ \infty} \left( \frac{1}{3} \right)^n \), yielding \( \frac{3}{2} \).