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Converge absolutely, which converge, and which diverge? Give reasons for your answers. $$\sum_{n=1}^{\infty}(-1)^{n}(\sqrt{n+1}-\sqrt{n})$$

Short Answer

Expert verified
The series converges conditionally but not absolutely.

Step by step solution

01

Analyze the Series Type

The given series is \( \sum_{n=1}^{\infty} (-1)^{n} (\sqrt{n+1} - \sqrt{n}) \), which is an alternating series because of the \((-1)^{n}\) factor. This suggests that the Alternating Series Test approach may be useful.
02

Use Alternating Series Test

The Alternating Series Test requires two conditions for the series \( \sum_{n=1}^{\infty} (-1)^{n} a_n \) to converge: (1) the sequence \( a_n = \sqrt{n+1} - \sqrt{n} \) must be positive, and (2) \( a_n \) must approach zero as \( n \to \infty \).
03

Verify \( a_n = \sqrt{n+1} - \sqrt{n} \) is Positive

The term \( a_n = \sqrt{n+1} - \sqrt{n} \) simplifies and is always positive for all \( n \geq 1 \), since \( \sqrt{n+1} > \sqrt{n} \). This satisfies the first condition of the Alternating Series Test.
04

Determine \( \\lim_{n \to \infty} a_n \)

To check if \( a_n \to 0 \): Simplify \( \sqrt{n+1} - \sqrt{n} \) by multiplying numerator and denominator by the conjugate \( \sqrt{n+1} + \sqrt{n} \), resulting in \( \frac{1}{\sqrt{n+1} + \sqrt{n}} \). As \( n \to \infty \), this goes to zero, since the denominator goes to infinity.
05

Conclude with Alternating Series Test

Since \( a_n = \sqrt{n+1} - \sqrt{n} \) is positive and \( a_n \to 0 \) as \( n \to \infty \), by the Alternating Series Test, the series \( \sum_{n=1}^{\infty} (-1)^{n} (\sqrt{n+1} - \sqrt{n}) \) converges.
06

Check for Absolute Convergence

To check for absolute convergence, consider the series \( \sum_{n=1}^{\infty} |(-1)^{n} (\sqrt{n+1} - \sqrt{n})| = \sum_{n=1}^{\infty} (\sqrt{n+1} - \sqrt{n}) \). Since \( \sqrt{n+1} - \sqrt{n} \sim \frac{1}{2\sqrt{n}} \) for large \( n \), the series behaves like a harmonic series and diverges.
07

Conclusion on Absolute Convergence

Since the series \( \sum_{n=1}^{\infty} (\sqrt{n+1} - \sqrt{n}) \) diverges, the original alternating series does not converge absolutely. It only converges conditionally.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergence Criteria
Understanding convergence criteria is crucial when analyzing an infinite series. This allows us to determine if a series approaches a finite value as we sum more and more terms.

For alternating series, which are series with terms that alternatively change sign, like our given series \( \sum_{n=1}^{\infty}(-1)^{n}(\sqrt{n+1}-\sqrt{n}) \), the Alternating Series Test provides a clear and systematic approach. It requires verifying two essential conditions:
  • Each term’s absolute value, \( a_n \), must decrease and remain positive.
  • The limit of \( a_n \) as \( n \) approaches infinity must be zero, \( \lim_{n \to \infty}a_n = 0 \).


In the mentioned series, our focus is on \( a_n = \sqrt{n+1} - \sqrt{n} \). First, we check if each term is positive, which it is because \( \sqrt{n+1} > \sqrt{n} \).
As \( n \to \infty \), we multiply the expression by its conjugate to make it simplified, resulting in a denominator that approaches infinity, leading \( a_n \to 0 \). These conditions confirm convergence.
Absolute and Conditional Convergence
When we encounter a series, we often want to know more than just if it converges; we want to know how it converges.

Absolute convergence occurs when the absolute value of a series also converges. We often check this because if a series converges absolutely, it also converges for sure, without worrying about alternating signs. For the given exercise, we examine:
\( \sum_{n=1}^{\infty} |(-1)^{n}(\sqrt{n+1} - \sqrt{n})| = \sum_{n=1}^{\infty} (\sqrt{n+1} - \sqrt{n}) \)

By comparing the series to \( \frac{1}{2\sqrt{n}} \), which resembles the harmonic series and diverges, we see that the corresponding positive series also diverges.

Therefore, the series does not converge absolutely. Its convergence is termed conditional, where the series converges only due to the alternating sign but not when ignoring the signs.
Series Divergence
In the study of infinite series, understanding divergence is just as essential as understanding convergence. A series diverges if the sum of its terms does not approach any finite limit.

In the given problem, our series does not show absolute convergence because its absolute counterpart, \( \sum_{n=1}^{\infty} (\sqrt{n+1} - \sqrt{n}) \), behaves like the divergent harmonic series. This demonstrates divergence behavior when disregarding alternating signs.

Recognizing this divergence when checking absolute convergence is necessary because it often guides the testing process for conditional convergence. Although this aspect of divergence indicates that the positive series diverges, it simultaneously highlights that the alternating series compensates to achieve a balance leading to conditional convergence.

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Most popular questions from this chapter

It is not yet known whether the series $$ \sum_{n=1}^{\infty} \frac{1}{n^{3} \sin ^{2} n} $$converges or diverges. Use a CAS to explore the behavior of the series by performing the following steps. a. Define the sequence of partial sums $$ s_{k}=\sum_{n=1}^{k} \frac{1}{n^{3} \sin ^{2} n} $$ What happens when you try to find the limit of \(s_{k}\) as \(k \rightarrow \infty ?\) Does your CAS find a closed form answer for this limit? b. Plot the first 100 points \(\left(k, s_{k}\right)\) for the sequence of partial sums. Do they appear to converge? What would you estimate the limit to be? c. Next plot the first 200 points \(\left(k, s_{k}\right) .\) Discuss the behavior in your own words. d. Plot the first 400 points \(\left(k, s_{k}\right) .\) What happens when \(k=355 ?\) Calculate the number \(355 / 113 .\) Explain from you calculation what happened at \(k=355 .\) For what values of \(k\) would you guess this behavior might occur again?

Find the value of \(b\) for which $$1+e^{b}+e^{2 b}+e^{3 b}+\cdots=9$$

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L ?\) b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$a_{n}=\frac{8^{n}}{n !}$$

For what values of \(r\) does the infinite series $$1+2 r+r^{2}+2 r^{3}+r^{4}+2 r^{5}+r^{6}+\cdots$$ converge? Find the sum of the serics when it converges.

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L ?\) b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$a_{n}=(123456)^{1 / n}$$

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