/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Find a formula for the \(n\) th ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a formula for the \(n\) th partial sum of the series and use it to determine if the series converges or diverges. If a series converges, find its sum. $$\sum_{n=1}^{\infty}(\tan (n)-\tan (n-1))$$

Short Answer

Expert verified
The series diverges as the partial sums do not converge.

Step by step solution

01

Identify the Series Type

The series given is in the form \( \sum_{n=1}^{\infty} (\tan(n) - \tan(n-1)) \). This is a telescoping series because most terms cancel with subsequent terms.
02

Expand to Understand Cancellation

Write out the first few terms: \[ (\tan(1) - \tan(0)) + (\tan(2) - \tan(1)) + (\tan(3) - \tan(2)) + \dots \] Notice how each \(\tan(n)\) cancels with \(\tan(n)\) from the previous term.
03

Find the Partial Sum

The \(n\)th partial sum \(S_n\) of the series is expressed as the sum of the first \(n\) terms. Due to the cancellation, \( S_n = \tan(n) - \tan(0) \).
04

Evaluate the Limit for Convergence

The series converges if \(\lim_{n \to \infty} S_n \) exists. Calculate this limit: \[ \lim_{n \to \infty} (\tan(n) - \tan(0)) = \lim_{n \to \infty} \tan(n) - 0 \] As \(\tan(n)\) does not converge to a single numerical value when \(n\) approaches infinity, this limit does not exist.
05

Conclusion on Convergence

Since the limit of the partial sums does not exist, the series does not converge. Therefore, the series diverges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Convergence and Divergence
When dealing with series, an essential aspect to understand is whether they converge or diverge. A series converges if, as you sum up its infinite terms, you approach a finite value. In simple terms, it means that the total amount doesn't explode to infinity or go haywire, but instead settles down to something sensible and simple.
When a series diverges, it does precisely the opposite. Instead of approaching a single, finite value, it grows without bound or doesn't settle into any particular pattern. This behavior makes the series impossible to pin down to a single number.
It's crucial to understand this distinction when evaluating series like the one in our problem. We needed to check whether the sum of the infinite terms results in a number we can call a sum or if it leads to chaos and divergence.
Defining the Partial Sum
The concept of a partial sum is vital in tackling series problems. So, what exactly is a partial sum? Well, it's just the total you get when adding up a certain number of terms from the start of your series.
Think of it as a snapshot of the summation process. Instead of looking at the entire series, we only consider the first few terms to build up the sequence. In mathematics, we often denote this as \( S_n \), which means the sum up to the \( n \)th term of the series.
In our exercise, the series was given by \( \sum_{n=1}^{\infty} (\tan(n) - \tan(n-1)) \). Thanks to its telescoping nature, most of the middle terms canceled out, leaving us with the neat formula \( S_n = \tan(n) - \tan(0) \). This form made it easier to evaluate what happens as \( n \) grows. So, by understanding partial sums, we can slowly extend our grasp from finite additions toward the infinite sum.
Evaluating the Limit for Convergence
To determine whether or not our series converges, we evaluated the limit of the partial sum. Evaluating the limit means looking at what happens as we add more and more terms - essentially letting \( n \) grow infinitely large.
The limit we examined was \( \lim_{n \to \infty} (\tan(n) - \tan(0)) \). Since \( \tan(0) \) is zero, the limit simplifies to \( \lim_{n \to \infty} \tan(n) \). The crucial challenge here is understanding how \( \tan(n) \) behaves as \( n \) continues to infinity. Notice that \( \tan(n) \) does not settle down to any single number as \( n \) becomes large.
Instead, it undergoes periodic oscillation due to the periodic nature of the tangent function, which causes it to not converge. Therefore, the absence of a finite limit for the partial sums leads us to conclude that this specific series diverges. This step illustrates why limit evaluation is so important for understanding the long-term behavior of a series.

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Most popular questions from this chapter

Assume that each sequence converges and find its limit. $$a_{1}=0, \quad a_{n+1}=\sqrt{8+2 a_{n}}$$

a. Suppose that \(f(x)\) is differentiable for all \(x\) in [0,1] and that \(f(0)=0 .\) Define sequence \(\left\\{a_{n}\right\\}\) by the rule \(a_{n}=n f(1 / n)\) Show that \(\lim _{n \rightarrow \infty} a_{n}=f^{\prime}(0) .\) Use the result in part (a) to find the limits of the following sequences \(\left\\{a_{n}\right\\}\). b. \(a_{n}=n \tan ^{-1} \frac{1}{n}\) c. \(a_{n}=n\left(e^{1 / n}-1\right)\) d. \(a_{n}=n \ln \left(1+\frac{2}{n}\right)\)

Determine if the sequence is monotonic and if it is bounded. $$a_{n}=2-\frac{2}{n}-\frac{1}{2^{n}}$$

It is not yet known whether the series $$ \sum_{n=1}^{\infty} \frac{1}{n^{3} \sin ^{2} n} $$converges or diverges. Use a CAS to explore the behavior of the series by performing the following steps. a. Define the sequence of partial sums $$ s_{k}=\sum_{n=1}^{k} \frac{1}{n^{3} \sin ^{2} n} $$ What happens when you try to find the limit of \(s_{k}\) as \(k \rightarrow \infty ?\) Does your CAS find a closed form answer for this limit? b. Plot the first 100 points \(\left(k, s_{k}\right)\) for the sequence of partial sums. Do they appear to converge? What would you estimate the limit to be? c. Next plot the first 200 points \(\left(k, s_{k}\right) .\) Discuss the behavior in your own words. d. Plot the first 400 points \(\left(k, s_{k}\right) .\) What happens when \(k=355 ?\) Calculate the number \(355 / 113 .\) Explain from you calculation what happened at \(k=355 .\) For what values of \(k\) would you guess this behavior might occur again?

Taylor's formula with \(n=1\) and \(a=0\) gives the linearization of a function at \(x=0 .\) With \(n=2\) and \(n=3\) we obtain the standard quadratic and cubic approximations. In these exercises we explore the errors associated with these approximations. We seek answers to two questions: a. For what values of \(x\) can the function be replaced by each approximation with an error less than \(10^{-2} ?\). b. What is the maximum error we could expect if we replace the function by each approximation over the specified interval? Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step \(I:\) Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(x=0\) Step 3: Calculate the \((n+1)\) st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M .\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=e^{-x} \cos 2 x, \quad|x| \leq 1$$

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