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Find the first three nonzero terms of the Maclaurin series for each function and the values of \(x\) for which the series converges absolutely. $$f(x)=\left(1-x+x^{2}\right) e^{x}$$

Short Answer

Expert verified
The series terms are: \(1 - x + \frac{3}{2}x^2\); converges for all \(x \in \mathbb{R}\).

Step by step solution

01

Write the Maclaurin Series for \(e^x\)

The Maclaurin series for \(e^x\) is given by: \[e^x = 1 + x + \frac{x^2}{2} + \frac{x^3}{6} + \frac{x^4}{24} + \cdots\]This representation will help access the terms needed for our function \((1-x+x^2) e^x\).
02

Multiply \(e^x\) by \(1-x+x^2\)

We want to find the series for \(f(x) = (1-x+x^2)e^x\). Expand this by multiplying the series for \(e^x\) with the polynomial \(1-x+x^2\): \[\begin{align*}&(1 - x + x^2)(1 + x + \frac{x^2}{2} + \frac{x^3}{6} + \cdots) = \&1 + x + \frac{x^2}{2} + \cdots - (x^2 + x + x^3 + \cdots) + \cdots \&+ (x^2 + x^3 + x^4) + \cdots\end{align*}\]Collect and simplify the terms to find the first three nonzero terms.
03

Find the Nonzero Terms

Identify and compute the first three nonzero terms obtained from the multiplication:- 1st term: \(1\)- 2nd term: \(0\) from \(x - x = 0\)- 3rd term: \(\frac{1}{2}x^2 + x^2 = \frac{3}{2}x^2\)Thus, the first three nonzero terms of the series are: \[1 - x + \frac{3}{2}x^2\]
04

Determine Convergence

The series for \(e^x\) converges for all real numbers. Multiplying this by a polynomial, \((1-x+x^2)\), does not change the interval of convergence. Hence, the series for \((1-x+x^2)e^x\) also converges for all real numbers \(x\). Therefore, the series converges absolutely for all \(x \in \mathbb{R}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Series Expansion
The concept of series expansion is a powerful mathematical tool used to approximate functions by representing them as infinite sums of terms. In the context of the Maclaurin series, this involves expanding a function around zero to derive a polynomial expression. Consider the exponential function, \(e^x\).
  • The Maclaurin series for \(e^x\) is: \(e^x = 1 + x + \frac{x^2}{2} + \frac{x^3}{6} + \cdots\).
  • This takes the shape of an infinite polynomial, where the degree of the polynomial increases with each successive term.
Such expansions allow us to handle complex functions, like \(f(x) = (1-x+x^2)e^x\), by breaking them down into simpler components that can be easily analyzed. To tackle the problem, the polynomial \(1 - x + x^2\) is multiplied through the series expansion of \(e^x\). This way, the function is broken down into manageable parts that combine polynomial and exponential behavior, showing a simple approximation of the function near the origin.
Convergence
When we talk about convergence in the context of series, we refer to how the sum of the series behaves as more and more terms are added. The convergence tells us that if we keep adding more terms, our approximation of the actual function becomes more accurate.
  • The Maclaurin series for \(e^x\) is known to converge for all real numbers.
  • This means no matter the value of \(x\), as you add more terms from the series, the sum approaches \(e^x\) closely.
Convergence is crucial in determining the validity of our series expansion over a specific range of values. For the series \((1-x+x^2)e^x\), multiplying a polynomial by a series that converges for all \(x\) will not alter the convergence range. Thus, this series is said to converge absolutely for all real \(x\), giving us confidence in using it as an approximation tool for any real input.
Polynomial Multiplication
Polynomial multiplication involves multiplying each term of one polynomial by every term of another. This operation is foundational when working with series expansions, such as the Maclaurin series. Let's see how it applies:
  • Take two expressions, like \(1 - x + x^2\) and the series for \(e^x\).
  • Each term in the first polynomial is multiplied by every term in the second series.
This creates new terms that must be combined and simplified. For instance, multiplying \(1 - x + x^2\) by several terms of \(e^x\):
  • The constant \(1\) times the series \(e^x\) keeps the series the same.
  • The \(-x\) term reverses the sign of all series terms, contributing negatively.
  • \(x^2\) term will shift each series term rightwards by two degrees of \(x\).
The key simplification comes when these resulting products are collected, leading to combined terms like \(\frac{3}{2}x^2\), demonstrating the result of efficient multiplication and combination.

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Most popular questions from this chapter

Taylor's formula with \(n=1\) and \(a=0\) gives the linearization of a function at \(x=0 .\) With \(n=2\) and \(n=3\) we obtain the standard quadratic and cubic approximations. In these exercises we explore the errors associated with these approximations. We seek answers to two questions: a. For what values of \(x\) can the function be replaced by each approximation with an error less than \(10^{-2} ?\). b. What is the maximum error we could expect if we replace the function by each approximation over the specified interval? Using a CAS, perform the following steps to aid in answering questions (a) and (b) for the functions and intervals. Step \(I:\) Plot the function over the specified interval. Step 2: Find the Taylor polynomials \(P_{1}(x), P_{2}(x),\) and \(P_{3}(x)\) at \(x=0\) Step 3: Calculate the \((n+1)\) st derivative \(f^{(n+1)}(c)\) associated with the remainder term for each Taylor polynomial. Plot the derivative as a function of \(c\) over the specified interval and estimate its maximum absolute value, \(M .\) Step 4: Calculate the remainder \(R_{n}(x)\) for each polynomial. Using the estimate \(M\) from Step 3 in place of \(f^{(n+1)}(c),\) plot \(R_{n}(x)\) over the specified interval. Then estimate the values of \(x\) that answer question (a). Step 5: Compare your estimated error with the actual error \(E_{n}(x)=\left|f(x)-P_{n}(x)\right|\) by plotting \(E_{n}(x)\) over the specified interval. This will help answer question (b). Step 6: Graph the function and its three Taylor approximations together. Discuss the graphs in relation to the information discovered in Steps 4 and 5. $$f(x)=(1+x)^{3 / 2}, \quad-\frac{1}{2} \leq x \leq 2$$

Use a CAS to perform the following steps for the sequences. a. Calculate and then plot the first 25 terms of the sequence. Does the sequence appear to be bounded from above or below? Does it appear to converge or diverge? If it does converge, what is the limit \(L ?\) b. If the sequence converges, find an integer \(N\) such that \(\left|a_{n}-L\right| \leq 0.01\) for \(n \geq N .\) How far in the sequence do you have to get for the terms to lie within 0.0001 of \(L ?\) $$a_{n}=\frac{\ln n}{n}$$

For approximately what values of \(x\) can you replace \(\sin x\) by \(x-\left(x^{3} / 6\right)\) with an error of magnitude no greater than \(5 \times 10^{-4} ?\) Give reasons for your answer.

Show that if the graph of a twice-differentiable function \(f(x)\) has an inflection point at \(x=a,\) then the linearization of \(f\) at \(x=a\) is also the quadratic approximation of \(f\) at \(x=a .\) This explains why tangent lines fit so well at inflection points.

Uniqueness of limits Prove that limits of sequences are unique. That is, show that if \(L_{1}\) and \(L_{2}\) are numbers such that \(a_{n} \rightarrow L_{1}\) and \(a_{n} \rightarrow L_{2},\) then \(L_{1}=L_{2}\).

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