Chapter 9: Problem 21
Use any method to determine if the series converges or diverges. Give reasons for your answer. $$\sum_{n=1}^{\infty} \frac{n^{10}}{10^{n}}$$
Short Answer
Expert verified
The series converges by the ratio test.
Step by step solution
01
Understand the Series
We need to determine whether the series \(\sum_{n=1}^{\infty} \frac{n^{10}}{10^n}\) converges or diverges. This is an infinite series, where each term is in the form of \(\frac{n^{10}}{10^n}\).
02
Apply the Ratio Test
The ratio test is often used for series with factorials or exponentials. The ratio test states that for the series \(a_n\), the series converges if \(\lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| < 1\). Here \(a_n = \frac{n^{10}}{10^n}\).
03
Compute \(a_{n+1}\) and \(\frac{a_{n+1}}{a_n}\)
Let \(a_{n+1} = \frac{(n+1)^{10}}{10^{n+1}}\). Now find \(\frac{a_{n+1}}{a_n} = \frac{(n+1)^{10}}{10^{n+1}} \cdot \frac{10^n}{n^{10}} = \frac{(n+1)^{10}}{10 \cdot n^{10}}\).
04
Simplify the Ratio
Simplify the ratio: \(\frac{a_{n+1}}{a_n} = \frac{(n+1)^{10}}{10 \cdot n^{10}}\). This can be expanded as \(\left(1 + \frac{1}{n}\right)^{10}\).
05
Evaluate the Limit
Evaluate the limit: \(\lim_{n \to \infty} \frac{(n+1)^{10}}{10 \cdot n^{10}} = \frac{1}{10}\cdot\lim_{n \to \infty}\left(1+\frac{1}{n}\right)^{10} = \frac{1}{10}\).
06
Determine Convergence
Since the limit \(\frac{1}{10} < 1\), by the ratio test, the series \(\sum_{n=1}^{\infty} \frac{n^{10}}{10^n}\) converges.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ratio Test
The ratio test is a powerful tool to determine the convergence of infinite series, especially those involving factorials or exponential components. When you have a series \( a_n \) and you need to decide its behavior, the ratio test takes center stage. It provides a clear process: compute \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \). If the limit is less than 1, the series converges absolutely.For our series \( \sum_{n=1}^{\infty} \frac{n^{10}}{10^n} \), the application was straightforward. We first calculated \( a_{n} = \frac{n^{10}}{10^n} \) and then \( a_{n+1} = \frac{(n+1)^{10}}{10^{n+1}} \). This led us to evaluate the limit:
- The simplified form \( \frac{(n+1)^{10}}{10 \cdot n^{10}} \) appeared.
- Expanding it showed that \( \lim_{n \to \infty} \left(1+\frac{1}{n}\right)^{10} \times \frac{1}{10} = \frac{1}{10} \).
Infinite Series
An infinite series is a sum of the terms of an infinite sequence. Picture adding numbers but holding a never-ending bucket. Our series, \( \sum_{n=1}^{\infty} \frac{n^{10}}{10^n} \), stretches infinitely as \( n \) climbs higher. Each term's form, \( \frac{n^{10}}{10^n} \), dictates how rapidly these terms shrink or grow as \( n \) increases.Infinite series offer numerous properties:
- Some are geometric or arithmetic, with recognizable patterns.
- Others, like ours, may be more complex, involving factorials or exponentials.
Exponential Functions
Exponential functions are a fundamental part of mathematics. These functions have a constant base raised to a variable exponent, like the terms in our series \( \frac{n^{10}}{10^n} \). Here, 10 is the base, used to shrink the series' size with each step of \( n \). An exponential decay is evident, given that the base \( 10 \) multiplied by itself reduces the number at higher speeds as compared to the linear growth of the numerator’s \( n^{10} \).Exponential functions have several key traits:
- They grow quickly or decay based on their exponent and base.
- In sequences and series, they can influence convergence with their dramatic changes.