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Evaluate the integrals. $$\int 4 \tan ^{3} x d x$$

Short Answer

Expert verified
\( \int 4 \tan^3 x \, dx = 2 \tan^2 x - 4 \ln |\sec x| + C \)

Step by step solution

01

Identify the Integral Form

We have the integral \( \int 4 \tan^3 x \, dx \). It's beneficial to rewrite it in a form that can be more easily integrated. Notice that \( \tan^3 x = \tan x \cdot \tan^2 x \). Since \( \tan^2 x = \sec^2 x - 1 \), we can express \( \tan^3 x \) as \( \tan x (\sec^2 x - 1) \). This allows us to split the integral: \( \int 4 \tan x (\sec^2 x - 1) \, dx = \int 4 \tan x \sec^2 x \, dx - \int 4 \tan x \, dx \).
02

Integrate \( \int 4 \tan x \sec^2 x \, dx \)

Note that the derivative of \( \tan x \) is \( \sec^2 x \). Thus, we can use substitution. Let \( u = \tan x \), then \( du = \sec^2 x \, dx \). The integral becomes \( \int 4 u \, du \), which evaluates to \( 2u^2 + C_1 \), where \( u = \tan x \). Hence, \( \int 4 \tan x \sec^2 x \, dx = 2 \tan^2 x + C_1 \).
03

Integrate \( \int 4 \tan x \, dx \)

This is a standard integral that requires the knowledge of \( \ln |\sec x| \). Using the fact that the derivative of \( \ln |\sec x| \) is \( \tan x \), the integral \( \int 4 \tan x \, dx \) is \( 4 \ln |\sec x| + C_2 \).
04

Combine Results and Simplify

Combine the results of the two integrals: \( \int 4 \tan^3 x \, dx = 2 \tan^2 x - 4 \ln |\sec x| + C \), where \( C = C_1 + C_2 \) is the constant of integration. This expression represents the antiderivative of \( 4 \tan^3 x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometric Integrals
Trigonometric integrals are a special category of calculus problems that involve integrals of functions composed with trigonometric functions like sine, cosine, and tangent. These integrals often necessitate specific techniques for simplification and evaluation.
For example, to integrate a trigonometric term such as \( \tan^3 x \), it's helpful to express it in terms of other trigonometric identities. In the case of \( \tan x \), we utilize the identity \( \tan^2 x = \sec^2 x - 1 \), which allows us to rewrite the integral in a more manageable form.
An essential first step in dealing with trigonometric integrals is to identify these identities and use them to transform the original integral into simpler terms, facilitating the integration process. This often involves recognizing patterns or rearranging terms to exploit these identities effectively.
Integration Techniques
When solving trigonometric integrals, a variety of integration techniques can be employed. The two main techniques demonstrated in the solution involve splitting and substitution.
Initially, the integral \( \int 4 \tan^3 x \, dx \) is split into two separate integrals: \( \int 4 \tan x \sec^2 x \, dx \) and \( \int 4 \tan x \, dx \). Splitting allows us to focus on integrating simpler parts individually. \
After splitting, each integral may require its own technique. The first integral takes advantage of the chain rule through substitution, while the second involves recognizing a standard antiderivative rule.
Understanding which technique to apply and when can make a significant difference in managing more complex integrals, ultimately simplifying the calculation process.
Substitution Method
The substitution method, often referred to as u-substitution, is a powerful tool for evaluating integrals. It simplifies an integral by temporarily rewriting part of the integrand in terms of a new variable. This method is particularly useful for transforming a complex integrand into a form that is easier to integrate.
In the given problem, by letting \( u = \tan x \), the differential of \( u \) becomes \( du = \sec^2 x \, dx \). This substitution transforms the integral \( \int 4 \tan x \sec^2 x \, dx \) into \( \int 4u \, du \), which is straightforward to solve, yielding \( 2u^2 + C_1 \). Finally, back-substituting \( u = \tan x \) gives the result in terms of the original variable.
Mastering substitution requires practice in choosing an appropriate "u" and recognizing the resulting simplification. Properly executed, it can significantly ease the integration of complicated functions.

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Most popular questions from this chapter

As Example 3 shows, the integral \(\int_{1}^{\infty}(d x / x)\) diverges. This means that the integral $$\int_{1}^{\infty} 2 \pi \frac{1}{x} \sqrt{1+\frac{1}{x^{4}}} d x$$ which measures the surface area of the solid of revolution traced out by revolving the curve \(y=1 / x, 1 \leq x,\) about the \(x\)-axis, diverges also. By comparing the two integrals, we see that, for every finite value \(b>1,\) $$\int_{1}^{b} 2 \pi \frac{1}{x} \sqrt{1+\frac{1}{x^{4}}} d x>2 \pi \int_{1}^{b} \frac{1}{x} d x$$ (Check your book to see image) However, the integral $$\int_{1}^{\infty} \pi\left(\frac{1}{x}\right)^{2} d x$$ for the volume of the solid converges. a. Calculate it. b. This solid of revolution is sometimes described as a can that does not hold enough paint to cover its own interior. Think about that for a moment. It is common sense that a finite amount of paint cannot cover an infinite surface. But if we fill the horn with paint (a finite amount), then we will have covered an infinite surface. Explain the apparent contradiction.

In Exercises \(33-38,\) perform long division on the integrand, write the proper fraction as a sum of partial fractions, and then evaluate the integral. $$\int \frac{16 x^{3}}{4 x^{2}-4 x+1} d x$$

Require the use of various trigonometric identities before you evaluate the integrals. $$\int \cos ^{2} 2 \theta \sin \theta d \theta$$

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In Exercises \(9-16,\) express the integrand as a sum of partial fractions and evaluate the integrals. $$\int \frac{2 x+1}{x^{2}-7 x+12} d x$$

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