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Without sigma notation. Then evaluate them. $$\sum_{k=1}^{4}(-1)^{k} \cos k \pi$$

Short Answer

Expert verified
The sum is 4.

Step by step solution

01

Understand the Series

We are given the sum \( \sum_{k=1}^{4}(-1)^{k} \cos k \pi \). This means that we need to calculate the cosine of multiples of \( \pi \) (i.e., \( k \pi \) for \( k = 1, 2, 3, 4 \)), multiply each result by \((-1)^{k}\), and then sum all the values.
02

Evaluate Each Cosine Term

Let's calculate each \( \cos k \pi \) for \( k = 1, 2, 3, 4 \):- \( \cos \pi = -1 \)- \( \cos 2\pi = 1 \)- \( \cos 3\pi = -1 \)- \( \cos 4\pi = 1 \)
03

Multiply by \((-1)^{k}\)

Now, apply the multiplier \((-1)^{k}\) to each term:- For \( k = 1 \), \((-1)^1 \cos 1\pi = -1 (-1) = 1\)- For \( k = 2 \), \((-1)^2 \cos 2\pi = 1 (1) = 1\)- For \( k = 3 \), \((-1)^3 \cos 3\pi = -1 (-1) = 1\)- For \( k = 4 \), \((-1)^4 \cos 4\pi = 1 (1) = 1\)
04

Sum the Results

Add up all the results from Step 3: \( 1 + 1 + 1 + 1 = 4 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sigma Notation
Sigma notation is a concise way of expressing long sums and is usually represented by the symbol \( \Sigma \). This notation helps in summing a sequence of numbers using a compact form. For example, the expression \( \sum_{k=1}^{4} (-1)^{k} \cos k \pi \) means:
  • \( k \) is the index of summation, starting at 1 and ending at 4.
  • Each term of the series is calculated by substituting \( k \) into the expression \( (-1)^{k} \cos k \pi \).
This makes it easy to see patterns and quickly understand which terms to include in the sequence.
Sigma notation is especially useful for expressing sums involving sequences with a clear step or repeating pattern, such as alternating series, geometric progressions, and trigonometric series.
By interpreting the series using sigma notation, calculations become more organized and calculations for large numbers of terms are simplified.
Cosine Function
The cosine function is a fundamental part of trigonometry. It is closely related to the circle and helps measure angles.
In the context of trigonometric series, the cosine function often appears in mathematical expressions where angles correspond to multiples of \( \pi \). Here’s a quick overview of key points regarding the cosine function:
  • Cosine of zero degrees or \( \, \pi \, \) radians is 1.
  • Cosine of 180 degrees or \( \, 2\pi \, \) radians is -1.
  • Cosine has a periodicity of \( \, 2\pi \, \) radians, meaning it repeats every full circle (360 degrees).
For our exercise, we evaluated \( \cos k \pi \) for \( k = 1, 2, 3, 4 \). This revealed a pattern:
  • When \( k \) is odd, \( \cos k \pi = -1 \).
  • When \( k \) is even, \( \cos k \pi = 1 \).
Understanding these values is crucial for discovering the outcome of a sequence, especially when combined with alternating series terms.
Alternating Series
An alternating series is a series where the signs of each term flip in a regular pattern—typically between positive and negative. This is often expressed mathematically with the use of factors like \( (-1)^{k} \).
In our earlier exercise, \( (-1)^{k} \cos k \pi \) alternated between positive and negative because \( (-1)^{k} \) affects the sign of the cosine terms.
Let's unpack this next:
  • When \( k = 1 \), \( (-1)^1 = -1 \); \( \cos 1\pi = -1 \), hence the result is positive because \( (-1) \times (-1) = 1 \).
  • When \( k = 2 \), \( (-1)^2 = 1 \); \( \cos 2\pi = 1 \), so the result remains positive.
  • This pattern continues, creating interesting patterns in such series.
Alternating series are important because they often converge (the sums approach a limit), which provide insights into many real-world phenomena.Examining how terms change and interact in an alternating series can reveal deep insights into how sequences behave.

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Most popular questions from this chapter

Find the areas of the regions enclosed by the lines and curves in Exercises \(63-72\). $$y=7-2 x^{2} \quad \text { and } \quad y=x^{2}+4$$

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Use a CAS to perform the following steps: a. Plot the functions over the given interval. b. Partition the interval into \(n=100.200\), and 1000 subintervals of equal length, and evaluate the function at the midpoint of each subinterval. c. Compute the average value of the function values generated in part (b). d. Solve the equation \(f(x)=\) (average value) for \(x\) using the average value calculated in part (c) for the \(n=1000\) partitioning. $$f(x)=x e^{-x} \quad \text { on } \quad[0,1]$$

Use a CAS to perform the following steps: a. Plot the functions over the given interval. b. Partition the interval into \(n=100.200\), and 1000 subintervals of equal length, and evaluate the function at the midpoint of each subinterval. c. Compute the average value of the function values generated in part (b). d. Solve the equation \(f(x)=\) (average value) for \(x\) using the average value calculated in part (c) for the \(n=1000\) partitioning. $$f(x)=x \sin ^{2} \frac{1}{\pi} \quad \text { on } \quad\left[\frac{\pi}{4}, \pi\right]$$

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