Chapter 5: Problem 43
Evaluate the integrals. $$\int x(x-1)^{10} d x$$
Short Answer
Expert verified
\(\frac{(x-1)^{12}}{12} + \frac{(x-1)^{11}}{11} + C\).
Step by step solution
01
Explore Substitution Possibility
We can simplify the integration by realizing that the function inside the integral can benefit from substitution. Let us set \( u = x - 1 \), which implies \( du = dx \) and \( x = u + 1 \). Thus, the integral becomes \( \int (u+1)u^{10} du \).
02
Expand the Integrand
Using the distributive property, expand \((u+1)u^{10}\) to get \(u^{11} + u^{10}\). Now the integral becomes \( \int u^{11} + u^{10} \, du \).
03
Integrate Term by Term
Integrate each term separately. The integral of \(u^{11}\) is \( \frac{u^{12}}{12} \) and the integral of \(u^{10}\) is \( \frac{u^{11}}{11} \). Thus, the integral becomes \( \frac{u^{12}}{12} + \frac{u^{11}}{11} + C \).
04
Substitute Back in Terms of x
Replace \(u\) back with \(x-1\) to return to the original variable. Thus, the integral expression is \( \frac{(x-1)^{12}}{12} + \frac{(x-1)^{11}}{11} + C \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Substitution Method
The substitution method is a powerful tool in calculus to simplify the process of finding integrals. It involves substituting a part of the integral with a new variable, which can often make the integral easier to solve. In the given exercise, the expression
- \((x - 1)^{10}\)
- \(u = x - 1\)
Integration Techniques
Understanding different integration techniques is crucial for mastering calculus. Once the substitution is applied in the exercise, we are left with the integral:
- \(\int (u+1)u^{10} \, du\)
- \(\int x^n \, dx = \frac{x^{n+1}}{n+1} + C\)
Algebraic Expansion
Algebraic expansion is a basic yet powerful technique that helps in rearranging expressions into forms that are more manageable for integration. After substitution, the expression
- \((u+1)u^{10}\)
- \(u^{11} + u^{10}\)