Chapter 5: Problem 4
Use the Substitution Formula in Theorem 7 to evaluate the integrals in Exercises \(1-46\). a. \(\int_{0}^{\pi} 3 \cos ^{2} x \sin x d x\) b. \(\int_{2 \pi}^{3 \pi} 3 \cos ^{2} x \sin x d x\)
Short Answer
Expert verified
Both integrals evaluate to 2.
Step by step solution
01
Identify Substitution Variables
The given integral is \( \int 3 \cos^2 x \sin x \, dx \). Note the function \( \sin x \) inside the integral. Let's choose \( u = \cos x \) so that \( du = -\sin x \, dx \).
02
Substitute into the Integral
Replace \( \cos x \) with \( u \) and \( \sin x dx \) with \(-du\). The integral becomes \( \int 3 u^2 (-du) \) which simplifies to \(-3 \int u^2 \, du \).
03
Evaluate the Integral with Respect to \( u \)
Use the standard power rule for integration to evaluate \( -3 \int u^2 \, du \). The antiderivative is \(-3 \cdot \frac{u^3}{3} = -u^3 \).
04
Back Substitute \( u = \cos x \)
Substitute \( u \) back to express the antiderivative in terms of \( x \): \( -\cos^3 x \).
05
Evaluate the Definite Integral for Part (a)
For \( \int_{0}^{\pi} 3 \cos^2 x \sin x \, dx \), evaluate \(-\cos^3 x\) from 0 to \( \pi \).\[ -\cos^3(\pi) - (-\cos^3(0)) = -(-1) - (-1) = 2 \]
06
Evaluate the Definite Integral for Part (b)
For \( \int_{2\pi}^{3\pi} 3 \cos^2 x \sin x \, dx \), evaluate \(-\cos^3 x\) from \( 2\pi \) to \( 3\pi \). \[ -\cos^3(3\pi) - (-\cos^3(2\pi)) = -(-1) - (-1) = 2 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals allow us to find the total accumulation of a quantity, like area under a curve, over a specified interval. Unlike indefinite integrals, which deal with antiderivatives without bounds, definite integrals provide a specific numerical value. Consider the integral \( \int_{a}^{b} f(x) \, dx \). This expression calculates the signed area between the curve of \( f(x) \) and the x-axis from \( x = a \) to \( x = b \).
The limits \( a \) and \( b \) in the definite integral are crucial:
The limits \( a \) and \( b \) in the definite integral are crucial:
- \( a \) is the lower limit and \( b \) is the upper limit.
- The definite integral computes the net area, taking into account regions above and below the x-axis.
- It can be computed by finding the antiderivative \( F(x) \) of \( f(x) \), then evaluating \( F(b) - F(a) \).
Power Rule for Integration
The power rule for integration is a straightforward technique that simplifies finding antiderivatives. It states that if \( n eq -1 \), then the integral of \( x^n \) with respect to \( x \) is \( \frac{x^{n+1}}{n+1} + C \), where \( C \) is the constant of integration.
Here's how you can use the power rule efficiently:
Here's how you can use the power rule efficiently:
- First, identify the term in the function that fits the form \( x^n \).
- Apply the rule to find the antiderivative, increasing the exponent by one and dividing by the new exponent.
- If dealing with a definite integral, use the antiderivative to evaluate the integral between the specified bounds.
- Always remember to adjust for any coefficients or constants multiplied with \( x^n \).
Trigonometric Substitution
Trigonometric substitution is a method used to simplify integration, particularly when dealing with expressions involving square roots or even powers of sine and cosine. By substituting a trigonometric identity or function, we can transform the problem into a simpler form.
The process typically involves these steps:
The process typically involves these steps:
- Identify parts of the integrand (the function to be integrated) that suggest a trigonometric substitution, such as products involving \( \sin x \) or \( \cos x \).
- Select the substitution that will simplify the integral, like \( u = \cos x \) in our exercise, turning the trigonometric expression into a polynomial one.
- Calculate \( du \), the derivative of the substitution, to replace the differential \( dx \).
- Re-express the entire integral in terms of the new variable.
- Complete the integration and then substitute back the original trigonometric expressions if necessary.