Chapter 5: Problem 111
Suppose that \(F(x)\) is an antiderivative of \(f(x)=(\sin x) / x\) \(x>0 .\) Express. $$\int_{1}^{3} \frac{\sin 2 x}{x} d x$$ in terms of \(F\)
Short Answer
Expert verified
\( \frac{1}{2} (F(6) - F(2)) \)
Step by step solution
01
Recognize the Inner Function
Identify the integral's function, which is \( \int \frac{ \sin 2x}{x} \, dx \). Notice that \( \frac{ \sin 2x}{x} \) resembles \( f(x) = \frac{\sin x}{x} \) with an argument substitution of \( 2x \).
02
Perform Substitution
We substitute \( u = 2x \), which implies \( du = 2 \, dx \) or \( dx = \frac{1}{2} du \). This changes the integral bounds accordingly: when \( x = 1 \), \( u = 2 \cdot 1 = 2 \) and when \( x = 3 \), \( u = 2 \cdot 3 = 6 \).
03
Rewrite the Integral with Substitution
Using the substitution in Step 2, rewrite \( \int_{1}^{3} \frac{\sin 2x}{x} \, dx \) as \( \int_{2}^{6} \frac{\sin u}{u} \cdot \frac{1}{2} \, du \). Factor out the constant \( \frac{1}{2} \); this simplifies the integral to \( \frac{1}{2} \int_{2}^{6} \frac{\sin u}{u} \, du \).
04
Express the Integral in Terms of F
Since \( F(x) \) is an antiderivative of \( f(x) = \frac{\sin x}{x} \), the integral \( \int_{2}^{6} \frac{\sin u}{u} \, du \) can be expressed as \( F(6) - F(2) \). Substitute this into the expression: \( \frac{1}{2} (F(6) - F(2)) \).
05
Final Expression
Combine all the previous steps to find that \( \int_{1}^{3} \frac{\sin 2x}{x} \, dx = \frac{1}{2} (F(6) - F(2)) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Trigonometric Substitution
Trigonometric substitution is a valuable technique used in calculus to simplify the integration of certain functions involving trigonometric expressions. In the context of the given exercise, it plays a crucial role by transforming the integral into a more manageable form. Here, we notice the similarity between the original function, \( \frac{\sin 2x}{x} \), and \( \frac{\sin x}{x} \) by considering a substitution based on the argument change.
- The function \( \sin 2x \) can be expressed in terms of \( \sin u \) by letting \( u = 2x \), which transforms the trigonometric identity into a simpler form for integration.
- This substitution adjusts the variable of integration, \( x \), to \( u \), which helps align the structure of the integral with the known form \( f(x) = \frac{\sin x}{x} \).
Antiderivative
An antiderivative is a fundamental concept in calculus, representing a function whose derivative is the original function. In this exercise, we are given that \( F(x) \) is an antiderivative of the function \( f(x) = \frac{\sin x}{x} \).
- Understanding that an antiderivative reverses the process of differentiation is key. It helps us recognize that integration is seeking out this reverse operation.
- The function \( F(x) \) will provide the value of the integral over any interval, by evaluating \( F(b) - F(a) \) when integrating from \( a \) to \( b \).
Change of Variables
The change of variables, also known as substitution, is a technique used to transform a complex integral into a simpler one. It is especially useful when dealing with fractions or products involving trigonometric functions.Consider the integral \( \int \frac{\sin 2x}{x} \, dx \). By substituting \( u = 2x \), the differential changes as well, allowing \( du = 2 \, dx \), thus \( dx = \frac{1}{2} \, du \). This substitution modifies the bounds:
- When \( x = 1 \), \( u = 2 \cdot 1 = 2 \).
- When \( x = 3 \), \( u = 2 \cdot 3 = 6 \).