Chapter 4: Problem 10
Identify the coordinates of any local and absolute extreme points and inflection points. Graph the function. $$y=6-2 x-x^{2}$$
Short Answer
Expert verified
The local and absolute maximum is at (-1, 7); no minimum or inflection points exist.
Step by step solution
01
Identify the derivative
To find the extreme and inflection points, first determine the derivative of the function. Given \[y = 6 - 2x - x^2,\]we find the first derivative, \[y' = \frac{d}{dx}(6 - 2x - x^2) = -2 - 2x.\]
02
Find critical points
Critical points occur where the derivative is zero or undefined. Set \[y' = -2 - 2x = 0\]and solve for \(x\). \[-2 - 2x = 0 \-2 = 2x \x = -1.\]Thus, there is a potential extreme point at \(x = -1\).
03
Determine extreme point type
Use the second derivative test to classify the critical point. Find the second derivative:\[y'' = \frac{d}{dx}(-2 - 2x) = -2.\]Since \(y'' < 0\), the function is concave down at \(x = -1\), indicating a local maximum.
04
Calculate function value at critical point
Substitute \(x = -1\) into the original function to find the y-coordinate:\[y = 6 - 2(-1) - (-1)^2 = 6 + 2 - 1 = 7.\]The local maximum is \((-1, 7)\).
05
Identify inflection points
Inflection points occur where the second derivative changes sign. Since \[y'' = -2\]is constant and never zero or undefined, there are no inflection points.
06
Determine the absolute extreme
Given that the parabola opens downwards (as indicated by the leading negative coefficient \(-x^2\)), the highest point is the vertex. The local maximum at \((-1, 7)\) is also the absolute maximum over all real numbers. There is no absolute minimum since the parabola extends downwards indefinitely.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Extreme Points
In calculus, extreme points of a function are key markers that help identify the highest or lowest values of the function within a certain interval. These points can either be local or absolute extreme points.
In our quadratic function, we identified the extreme point at \(x = -1\), making \(-1, 7\) a local maximum, which also serves as the absolute maximum point because the parabola opens downward.
- Local Extreme Points: These are points where the function takes on a maximum or minimum value relative to nearby points.
- Absolute Extreme Points: These are points where a function achieves its highest or lowest value across its entire domain.
In our quadratic function, we identified the extreme point at \(x = -1\), making \(-1, 7\) a local maximum, which also serves as the absolute maximum point because the parabola opens downward.
Derivative
Derivatives are foundational in calculus, acting as mathematical tools to describe how a function changes as its input changes.
- The derivative \(f'(x)\) gives us the slope of the tangent line to the function at any point.
- A zero derivative indicates a horizontal tangent, often pointing towards a local extreme point.
Second Derivative
The second derivative of a function gives us insight into its curvature or concavity. It tells us about the acceleration or deceleration of the function's slope.
- If \(f''(x) > 0\), the function is concave up, resembling the shape of a "U" and suggesting that a minimum point might be present.
- If \(f''(x) < 0\), the function is concave down, resembling an "n" and potentially indicating a maximum point.
Concavity
Understanding concavity is crucial for interpreting the shape of a graph around certain points. It is determined by the sign of the second derivative. Concavity plays a role in predicting the behavior of functions beyond just locating extreme points.
- Concave Up: If the second derivative is positive, the function curves upwards like a cup, which generally indicates the presence of a local minimum.
- Concave Down: When the second derivative is negative, it implies the function curves downward, hinting at a local maximum.