Chapter 3: Problem 81
Find the derivative of \(y\) with respect to the given independent variable. $$y=\theta \sin \left(\log _{7} \theta\right)$$
Short Answer
Expert verified
The derivative is \( \frac{dy}{d\theta} = \sin(\log_{7} \theta) + \frac{\cos(\log_{7} \theta)}{\ln(7)} \).
Step by step solution
01
Identify the Structure
The function given is a product of two functions, \( y = \theta \cdot \sin(\log_{7} \theta) \). We will use the product rule for differentiation, which states \( u'v + uv' \) if \( y = uv \). Let \( u = \theta \) and \( v = \sin(\log_{7} \theta) \).
02
Differentiate First Function
Differentiate \( u = \theta \) with respect to \( \theta \). Since \( u = \theta \), \( u' = \frac{d}{d\theta}(\theta) = 1 \).
03
Differentiate Second Function
Now differentiate \( v = \sin(\log_{7} \theta) \). Use the chain rule: \( v' = \cos(\log_{7} \theta) \cdot \frac{d}{d\theta}(\log_{7} \theta) \). Recall that \( \frac{d}{d\theta}(\log_{a} \theta) = \frac{1}{\theta \ln(a)} \), hence \( v' = \cos(\log_{7} \theta) \cdot \frac{1}{\theta \ln(7)} \).
04
Apply the Product Rule
According to the product rule, the derivative \( \frac{dy}{d\theta} \) is given by \( u'v + uv' \). Substituting the results from the previous steps:\[ \frac{dy}{d\theta} = (1)\sin(\log_{7} \theta) + \theta \cdot \left(\cos(\log_{7} \theta) \cdot \frac{1}{\theta \ln(7)}\right) \] Simplify the expression:\[ \frac{dy}{d\theta} = \sin(\log_{7} \theta) + \frac{\cos(\log_{7} \theta)}{\ln(7)} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Product Rule
The product rule is a fundamental concept within differential calculus that is used when differentiating products of two functions. When you have a function that is the product of two separate functions, say \( y = uv \), the product rule tells us how to find its derivative. It is expressed as \( u'v + uv' \), where \( u \) and \( v \) are functions of the same variable, and \( u' \) and \( v' \) are their respective derivatives.
In the original exercise, the function \( y = \theta \sin(\log_{7} \theta) \) is the product of \( \theta \) and \( \sin(\log_{7} \theta) \). By identifying this structure, we decide that \( u = \theta \) and \( v = \sin(\log_{7} \theta) \).
In the original exercise, the function \( y = \theta \sin(\log_{7} \theta) \) is the product of \( \theta \) and \( \sin(\log_{7} \theta) \). By identifying this structure, we decide that \( u = \theta \) and \( v = \sin(\log_{7} \theta) \).
- First, the derivative of \( u = \theta \) is straightforward: \( u' = 1 \).
- Next, you differentiate \( v = \sin(\log_{7} \theta) \) using further differentiation rules which will be discussed in subsequent sections.
- Finally, substitute these derivatives into the product rule formula to get the derivative of the entire function.
Chain Rule
The chain rule is essential when differentiating composite functions. A composite function is a function made up of two or more functions. In essence, the chain rule helps find the derivative of a function that is nested within another. Mathematically, if you have a function of \( g(f(x)) \), then its derivative can be found using the chain rule as \( g'(f(x)) \cdot f'(x) \).
For the exercise at hand, we encountered a composite function when differentiating \( \sin(\log_{7} \theta) \). Here, \( \log_{7} \theta \) is the inner function and \( \sin \) is the outer function.
For the exercise at hand, we encountered a composite function when differentiating \( \sin(\log_{7} \theta) \). Here, \( \log_{7} \theta \) is the inner function and \( \sin \) is the outer function.
- First, you take the derivative of the outer function, \( \sin \), which becomes \( \cos \).
- Then multiply it by the derivative of the inner function, \( \log_{7} \theta \).
- Using logarithmic differentiation, we find that the derivative of \( \log_{7} \theta \) is \( \frac{1}{\theta \ln(7)} \).
Derivative of Logarithmic Functions
Logarithmic functions appear often in calculus and have specific rules for differentiation. When taking the derivative of a logarithmic function, such as \( \log_{a} x \), you use the formula \( \frac{1}{x \ln(a)} \). This is crucial when the base of the logarithm is not the natural base \( e \).
In the given problem, you have \( \log_{7} \theta \) as part of the function that was differentiated using the chain rule. The derivative process involved involves:
In the given problem, you have \( \log_{7} \theta \) as part of the function that was differentiated using the chain rule. The derivative process involved involves:
- Using the specific formula: \( \frac{d}{d\theta}(\log_{7} \theta) = \frac{1}{\theta \ln(7)} \).
- Substituting this derivative back into the equation when applying the chain rule to the sine function.
- Understanding that the natural log \( \ln(a) \) adjusts the rate of change specified by the base of the logarithm.