/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Which of the expressions are def... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Which of the expressions are defined, and which are not? Give reasons for your answers. a. \(\cot ^{-1}(-1 / 2)\) b. \(\cos ^{-1}(-5)\)

Short Answer

Expert verified
Expression a is defined; expression b is not defined.

Step by step solution

01

Determine the Valid Range for Each Function

The functions given here are inverse trigonometric functions. For \( \cot^{-1}(x) \), the valid input range is \(-\infty < x < \infty\). For \( \cos^{-1}(x) \), the valid input range is \(-1 \, \leq x \leq \, 1\).
02

Evaluate Expression a

The expression is \( \cot^{-1}(-1/2) \). Since the input \( -1/2 \) falls within the range \(-\infty < x < \infty\), the expression is defined.
03

Evaluate Expression b

The expression is \( \cos^{-1}(-5) \). Here, the input \( -5 \) does not fall within the range \(-1 \, \leq x \leq \, 1\). Thus, the expression is not defined.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Cotangent
The cotangent function, often represented as "cot," is the reciprocal of the tangent function in trigonometry. In a right triangle, the cotangent of an angle is the ratio of the length of the adjacent side to the length of the opposite side. The formula is: \[\cot(\theta) = \frac{\text{adjacent}}{\text{opposite}}\]
For the inverse cotangent function, represented as \( \cot^{-1} \), it reverses this back to an angle from the ratio. Unlike the tangent function, whose range is typically limited, \( \cot^{-1}(x) \) can handle any real number \( x \). This means that any fraction, positive or negative, or even whole numbers can be valid inputs for \( \cot^{-1} \). The output of \( \cot^{-1} \) is usually an angle in radians which falls within the range of \( (0, \pi) \).
  • The function does not have strict input restrictions, making it quite versatile.
  • Given this flexibility, calculations involving \( \cot^{-1} \) often yield useful insights without limitation.
Exploring Arccosine
The arccosine function, denoted as "arccos," is the inverse of the cosine function. In a right triangle, the cosine of an angle is the ratio of the adjacent side to the hypotenuse, expressed as: \[\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}\]
To find the angle from a given cosine value, we use \( \cos^{-1} \). Unlike \( \cot^{-1} \), \( \cos^{-1}(x) \) only accepts values within a narrow range.
  • The valid input range for \( \cos^{-1}(x) \) is from \(-1\) to \(1\).
  • This is because the cosine of any angle cannot exceed these limits, as the adjacent side cannot be longer than the hypotenuse.
Outputs from the \( \cos^{-1}(x) \) function are angles measured in radians, specifically between \( 0 \) and \( \pi \). This bounded input ensures that any angle calculated is part of the real-world scenario where cosine values are applicable.
Valid Input Range for Inverse Trigonometric Functions
When working with inverse trigonometric functions, understanding valid input ranges is crucial for determining whether expressions are defined. Each inverse trigonometric function has specific input constraints based on the real-world interpretation of angles.
  • For \( \cot^{-1}(x) \), there are no input restrictions. The function can handle any real input.
  • For \( \cos^{-1}(x) \), inputs are tightly restricted to the range of \(-1 \leq x \leq 1\).
These restrictions come from the fundamental properties of the trigonometric functions themselves. The input range for a function is derived from its definition in a right triangle or unit circle. If you try to input a number outside of these defined ranges for \( \cos^{-1} \), like \(-5\), it leads to an undefined situation. Ensuring that your inputs respect these bounds will prevent errors in calculations and help maintain valid and meaningful results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You will explore some functions and their inverses together with their derivatives and tangent line approximations at specified points. Perform the following steps using your CAS: a. Plot the function \(y=f(x)\) together with its derivative over the given interval. Explain why you know that \(f\) is one-to-one over the interval. b. Solve the equation \(y=f(x)\) for \(x\) as a function of \(y,\) and name the resulting inverse function \(g\). c. Find the equation for the tangent line to \(f\) at the specified point \(\left(x_{0}, f\left(x_{0}\right)\right)\) d. Find the equation for the tangent line to \(g\) at the point \(\left(f\left(x_{0}\right), x_{0}\right)\) located symmetrically across the \(45^{\circ}\) line \(y=x\) (which is the graph of the identity function). Use Theorem 3 to find the slope of this tangent line. e. Plot the functions \(f\) and \(g\), the identity, the two tangent lines, and the line segment joining the points \(\left(x_{0}, f\left(x_{0}\right)\right)\) and \(\left(f\left(x_{0}\right), x_{0}\right)\) Discuss the symmetries you see across the main diagonal. $$y=\frac{4 x}{x^{2}+1}, \quad-1 \leq x \leq 1, \quad x_{0}=1 / 2$$

Find the derivative of \(y\) with respect to the given independent variable. $$y=t \log _{3}\left(e^{(\sin t)(\ln 3)}\right)$$

Unclogging arteries The formula \(V=k r^{4},\) discovered by the physiologist Jean Poiseuille (1797-1869), allows us to predict how much the radius of a partially clogged artery has to be expanded in order to restore normal blood flow. The formula says that the volume \(V\) of blood flowing through the artery in a unit of time at a fixed pressure is a constant \(k\) times the radius of the artery to the fourth power. How will a \(10 \%\) increase in \(r\) affect \(V ?\)

Use logarithmic differentiation to find the derivative of \(y\) with respect to the given independent variable. $$y=\sqrt{\left(x^{2}+1\right)(x-1)^{2}}$$

Use logarithmic differentiation to find the derivative of \(y\) with respect to the given independent variable. $$y=\sqrt[3]{\frac{x(x-2)}{x^{2}+1}}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.