Chapter 3: Problem 12
Find the indicated derivatives. $$\frac{d z}{d w}\( if \)z=\frac{1}{\sqrt{w^{2}-1}}$$
Short Answer
Expert verified
\( \frac{d z}{d w} = -\frac{w}{(w^2 - 1)^{3/2}} \)
Step by step solution
01
Rewrite the Function
The function given is \( z = \frac{1}{\sqrt{w^2-1}} \). To make differentiation easier, we can rewrite this as \( z = (w^2 - 1)^{-1/2} \). This form allows us to apply the power rule more directly in the differentiation process.
02
Apply the Chain Rule
To find \( \frac{d z}{d w} \), we need to use the chain rule. The chain rule states that if a function \( z = u^n \), then its derivative is \( \frac{d z}{d w} = n \cdot u^{n-1} \cdot \frac{d u}{d w} \). Here, set \( u = w^2 - 1 \) and \( n = -\frac{1}{2} \).
03
Differentiate the Inside Function
Differentiate \( u = w^2 - 1 \) with respect to \( w \). The derivative is \( \frac{d u}{d w} = 2w \).
04
Differentiate the Outer Function
Using the chain rule, differentiate the outer function \( z = u^{-1/2} \). The derivative is \(-\frac{1}{2} \cdot u^{-3/2} \cdot \frac{d u}{d w} \).
05
Substitute and Simplify
Substitute \( u = w^2 - 1 \) and \( \frac{d u}{d w} = 2w \) into the derivative found in Step 4. This gives: \[ \frac{d z}{d w} = -\frac{1}{2} (w^2 - 1)^{-3/2} \cdot 2w \]. Simplify this expression to get \[ \frac{d z}{d w} = -\frac{w}{(w^2 - 1)^{3/2}} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Chain Rule
The chain rule is a critical concept in calculus used for differentiating composite functions—functions nested within each other. In simple terms, when you have a function inside a function, the chain rule helps you find the derivative by multiplying the derivative of the outer function by the derivative of the inner function.
For instance, to differentiate a function like \( z = (w^2 - 1)^{-1/2} \), you don't just differentiate the power \(-1/2\). Instead, you identify the inner function, here given by \( u = w^2 - 1 \), and the outer function—which is \( u^{-1/2} \).
**Steps of the chain rule:**
For instance, to differentiate a function like \( z = (w^2 - 1)^{-1/2} \), you don't just differentiate the power \(-1/2\). Instead, you identify the inner function, here given by \( u = w^2 - 1 \), and the outer function—which is \( u^{-1/2} \).
**Steps of the chain rule:**
- Identify the outer function and the inner function.
- Differentiate the outer function keeping the inner function unchanged.
- Multiply by the derivative of the inner function.
Introduction to Differentiation
Differentiation is at the heart of calculus and essentially involves finding the rate at which a function changes. It's like taking a snapshot of a function's behavior at any given point.
When you differentiate a function, you obtain its derivative, which gives you valuable information about slopes of tangents and rates of change.
**Basic principles of differentiation:**
When you differentiate a function, you obtain its derivative, which gives you valuable information about slopes of tangents and rates of change.
**Basic principles of differentiation:**
- The derivative of a constant is zero.
- The derivative of \( x^n \) is found using the power rule \( nx^{n-1} \).
- For functions combined via addition or subtraction, differentiate separately.
Power Rule in Differentiation
The power rule is one of the simplest and most widely used techniques in differentiation. It provides a quick way to find the derivative of polynomial functions.
Under the power rule, if you have a function \( f(x) = x^n \), its derivative, \( f'(x) \), is \( n \cdot x^{n-1} \). This rule is especially useful when dealing with straightforward, power-based components of functions.
**Application of the power rule:**
Under the power rule, if you have a function \( f(x) = x^n \), its derivative, \( f'(x) \), is \( n \cdot x^{n-1} \). This rule is especially useful when dealing with straightforward, power-based components of functions.
**Application of the power rule:**
- In the problem \( z = (w^2 - 1)^{-1/2} \), we apply the power rule on the outer function \( u^{-1/2} \) as part of the chain rule process.
- During this process, the exponent \(-1/2\) is brought down and decreased by 1, making it \(-3/2\).
Solving a Calculus Problem - Putting it All Together
When approaching a calculus problem, like finding derivatives, breaking it down into manageable steps is key. Start by analyzing the function to see which differentiation techniques apply.
**Steps to solve the given problem:**
**Steps to solve the given problem:**
- Identify and rewrite the function if necessary—clarity helps through the differentiation process. For \( z = \frac{1}{\sqrt{w^2-1}} \), rewriting it as \( (w^2 - 1)^{-1/2} \) makes applying rules straightforward.
- Use the chain rule by differentiating the outer function while keeping the inner function intact.
- Then, differentiate the inner function.
- Combine these results, often requiring simplification to find the final derivative.
- (In our case, this results in \( \frac{d z}{d w} = -\frac{w}{(w^2 - 1)^{3/2}} \)).