Chapter 3: Problem 10
Find the indicated derivatives. $$\frac{d v}{d t}\( if \)v=t-\frac{1}{t}$$
Short Answer
Expert verified
The derivative is \( 1 - \frac{1}{t^2} \).
Step by step solution
01
Identify the Function to Differentiate
We are given the function \( v(t) = t - \frac{1}{t} \). We need to find the derivative \( \frac{d v}{d t} \).
02
Differentiate Each Term Individually
Differentiate the term \( t \) with respect to \( t \). This is a simple power rule operation, where the derivative of \( t \) is 1. For the second term \( -\frac{1}{t} \), rewrite it as \( -t^{-1} \) before differentiating.
03
Apply the Power Rule to the Second Term
Differentiate \( -t^{-1} \) using the power rule. The derivative of \( t^n \) is \( n\cdot t^{n-1} \). Thus, for \( -t^{-1} \), the derivative is \( -1\cdot t^{-2} = -\frac{1}{t^2} \).
04
Combine the Results
Combine the derivatives of each term. The derivative of \( v(t) = t - \frac{1}{t} \) is \( \frac{d v}{d t} = 1 - \frac{1}{t^2} \).
05
Write the Final Answer
The final expression for the derivative is \( \frac{d v}{d t} = 1 - \frac{1}{t^2} \). You can now use this to find the rate of change of \( v \) with respect to \( t \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Power Rule
The power rule is a fundamental concept in calculus used to find the derivative of functions that are expressed as powers of a variable. When you have a function in the form of \( t^n \), the power rule states that the derivative will be \( n \cdot t^{n-1} \). This means you multiply the coefficient (which is \( 1 \) if not explicitly written) by the exponent and subtract one from the exponent to find the derivative.
Here’s a simple breakdown:
Here’s a simple breakdown:
- For \( t^2 \), the derivative is \( 2 \cdot t^1 = 2t \).
- For \( t^3 \), it becomes \( 3 \cdot t^2 = 3t^2 \).
Mastering Derivative Calculation
Derivative calculation is the process of finding the derivative, or the rate of change, of a function with respect to a variable. In calculus, the derivative provides us with the slope of the tangent line to the function at any given point on its curve. This is crucial for understanding how a function behaves and varies over its domain.
Here’s how we approached the problem:
Here’s how we approached the problem:
- First, identify the function to differentiate, in this case, \( v(t) = t - \frac{1}{t} \).
- Differentiate each term separately by using calculus rules like the power rule.
Getting to Know a Function of a Variable
A function of a variable is an expression where you can substitute different values for the variable to get various outputs. Think of it like a machine that processes input values and produces corresponding results. Here, our function involves the variable \( t \), written as \( v(t) = t - \frac{1}{t} \). This setup shows us how the function value \( v \) changes as \( t \) changes.
Understanding this concept is fundamental in calculus because it gives insight into how variables interact in an equation or real-world situation. For instance, as \( t \) becomes very large or very small, \( v(t) \) will exhibit different behaviors:
Understanding this concept is fundamental in calculus because it gives insight into how variables interact in an equation or real-world situation. For instance, as \( t \) becomes very large or very small, \( v(t) \) will exhibit different behaviors:
- When \( t \) is large, \( \frac{1}{t} \) gets smaller, so \( v(t) \approx t \).
- When \( t \) is small, \( \frac{1}{t} \) becomes significant, affecting \( v(t) \) more.