/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 83 Find the limits. $$\lim _{\rig... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the limits. $$\lim _{\rightarrow-\infty}(2 x+\sqrt{4 x^{2}+3 x-2})$$

Short Answer

Expert verified
The limit is 0.

Step by step solution

01

Set Up the Limit

The expression given is \(2x + \sqrt{4x^2 + 3x - 2}\). We need to find the limit as \(x\) approaches negative infinity: \( \lim_{x \to -\infty} (2x + \sqrt{4x^2 + 3x - 2}) \).
02

Identify the Dominant Terms Inside the Square Root

Inside the square root, the dominant term as \(x\) goes to negative infinity is \(4x^2\) because it grows faster than the linear term \(3x\) and the constant \(-2\). Therefore, \(\sqrt{4x^2 + 3x - 2} \approx \sqrt{4x^2} = 2|x|\).
03

Consider the Absolute Value of x for Negative Values

Since \(x\) approaches negative infinity, \(|x| = -x\). Thus, \(\sqrt{4x^2 + 3x - 2} \approx 2(-x) = -2x\).
04

Substitute and Simplify the Limit Expression

Substituting the approximation, we get the expression: \(\lim_{x \to -\infty} (2x - 2x)\). This simplifies to \(\lim_{x \to -\infty} 0 = 0\).
05

Conclude

After simplification, the entire expression approaches zero as \(x\) goes to negative infinity. Therefore, the limit is 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limits at Infinity
Limits at infinity help us understand the behavior of a function as the input grows larger or smaller without bound. In this exercise, we're interested in what happens to the expression \(2x + \sqrt{4x^2 + 3x - 2}\) as \(x\) approaches negative infinity. The main idea is to identify what part of the expression will "dominate" or have the most significant impact on the value of the function as \(x\) becomes very large in the negative direction. By focusing on the dominant behavior of the function, we can effectively determine the limit without resolving every detail in the expression.
  • This technique simplifies the often complex behavior of functions and allows us to make informed predictions about their end behavior.
  • It's especially useful in calculus when dealing with polynomial and rational functions where terms can grow or shrink rapidly.
When discussing limits at infinity, always search for terms that will most significantly influence the final behavior of the function.
Square Root Simplification
Square root simplification involves reducing complex expressions under a square root sign to simpler, more understandable terms. In the expression \(\sqrt{4x^2 + 3x - 2}\), we look for the term that will dominate the expression’s behavior. In this case, \(4x^2\) is clearly the dominant term, as it grows more rapidly than the linear term \(3x\) and the constant term \(-2\).
  • For large values of \(|x|\), terms like \(3x\) or constants become negligible compared to \(4x^2\).
  • Thus, it is reasonable to approximate \(\sqrt{4x^2 + 3x - 2} \,\approx \,\sqrt{4x^2} = 2|x|\).
Simplifying the dominant terms helps greatly in moving forward with a limit problem as it reduces the complexity and focuses on the most impactful part of the function.
Dominant Term Analysis
Dominant term analysis is a process used to identify which parts of a mathematical expression will have the largest influence on the value of the entire expression for extreme values of the variable. When evaluating \(\lim_{x \to -\infty} (2x + \sqrt{4x^2 + 3x - 2})\), we recognize that the term \(4x^2\) dominates the square root.
  • We approximate \(\sqrt{4x^2 + 3x - 2}\) by simplifying to \(2|x|\), which further simplifies to \(-2x\) due to \(x\) being negative.
  • This allows us to transform the original expression to something easier to manage: \(\lim_{x \to -\infty} (2x - 2x)\), which rather straightforwardly becomes \(\lim_{x \to -\infty} 0 = 0\).
By focusing on dominant terms, we eliminate unnecessary complexity and reveal the core behavior of the function towards infinity.
Asymptotic Behavior
Asymptotic behavior describes how a function behaves as its input values grow very large or very small. In the example \(\lim_{x \to -\infty} (2x + \sqrt{4x^2 + 3x - 2})\), we see that the approach toward negative infinity results in the function simplifying to zero. This means the overall behavior of the function resembles that of a constant function as \(x\) approaches negative infinity.
  • Knowing the asymptotic behavior allows us to see that the function stabilizes, or "flattens," and moves towards a horizontal asymptote.
  • In this instance, the horizontal asymptote is \(y = 0\), reflecting that the drastic changes caused by the presence of \(2x\) and \(-2x\) are cancelled out by each other.
Understanding the asymptotic nature of a function is crucial in predicting long-term behavior and is a valuable tool in calculus when evaluating limits at infinity.

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Most popular questions from this chapter

To prove that each equation has a solution. Then use a graphing calculator or computer grapher to solve the equations. \(2 \sin x=x\) (three roots). Make sure you are using radian mode.

You will find a graphing calculator useful for Exercise. Let \(h(x)=\left(x^{2}-2 x-3\right) /\left(x^{2}-4 x+3\right)\) a. Make a table of the values of \(h\) at \(x=2.9,2.99,2.999,\) and so on. Then estimate \(\lim _{x \rightarrow 3} h(x) .\) What estimate do you arrive at if you evaluate \(h\) at \(x=3.1,3.01,3.001, \ldots\) instead? b. Support your conclusions in part (a) by graphing \(h\) near \(c=3\) and using Zoom and Trace to estimate \(y\) -values on the graph as \(x \rightarrow 3.\) c. Find \(\lim _{x \rightarrow 3} h(x)\) algebraically.

For what values of \(a\) is $$ f(x)=\left\\{\begin{array}{ll} a^{2} x-2 a, & x \geq 2 \\ 12, & x<2 \end{array}\right. $$ continuous at every \(x ?\)

Use a CAS to perform the following steps: a. Plot the function \(y=f(x)\) near the point \(c\) being approached. b. Guess the value of the limit \(L\) and then evaluate the limit symbolically to see if you guessed correctly. c. Using the value \(\epsilon=0.2,\) graph the banding lines \(y_{1}=L-\epsilon\) and \(y_{2}=L+\epsilon\) together with the function \(f\) near \(c\) d. From your graph in part (c), estimate a \(\delta>0\) such that for all \(x\) \(0<|x-c|<\delta \Rightarrow|f(x)-L|<\epsilon\) Test your estimate by plotting \(f, y_{1},\) and \(y_{2}\) over the interval \(0<|x-c|<\delta .\) For your viewing window use \(c-2 \delta \leq\) \(x \leq c+2 \delta\) and \(L-2 \epsilon \leq y \leq L+2 \epsilon .\) If any function values lie outside the interval \([L-\epsilon, L+\epsilon],\) your choice of \(\delta\) was too large. Try again with a smaller estimate. e. Repeat parts (c) and (d) successively for \(\epsilon=0.1,0.05,\) and 0.001 $$f(x)=\frac{3 x^{2}-(7 x+1) \sqrt{x}+5}{x-1}, \quad c=1$$

Gives a function \(f(x)\) and numbers \(L, c,\) and \(\epsilon \geq 0 .\) In each case, find an open interval about \(c\) on which the inequality \(|f(x)-L|<\epsilon\) holds. Then give a value for \(\delta>0\) such that for all \(x\) satisfying \(0<|x-c|<\delta\) the inequality \(|f(x)-L|<\epsilon\) holds. $$f(x)=m x, \quad m>0, \quad L=3 m, \quad c=3, \quad \epsilon=c>0$$

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