Chapter 2: Problem 71
To prove that each equation has a solution. Then use a graphing calculator or computer grapher to solve the equations. $$x^{3}-3 x-1=0$$
Short Answer
Expert verified
The equation has at least one real solution as the function crosses the x-axis.
Step by step solution
01
Understand the problem
We are given the equation \(x^3 - 3x - 1 = 0\). Our goal is to show that there is at least one value of \(x\) that satisfies this equation, meaning the function \(f(x) = x^3 - 3x - 1\) crosses the x-axis at least once.
02
Analyze the function's behavior
Consider the function \(f(x) = x^3 - 3x - 1\) and analyze its behavior. Start by examining its limits as \(x\) approaches positive and negative infinity. As \(x\) approaches \(+fty\), \(x^3\) dominates, and thus \(f(x)\) approaches \(+fty\). Conversely, as \(x\) approaches \(-fty\), \(f(x)\) approaches \(-fty\). This behavior suggests that the function crosses the x-axis at least once.
03
Apply the Intermediate Value Theorem
Since \(f(x)\) is a polynomial and thus continuous, use the Intermediate Value Theorem. Evaluate \(f(x)\) at a few points: \(f(0) = 0^3 - 3(0) - 1 = -1\) and \(f(2) = 2^3 - 3(2) - 1 = 8 - 6 - 1 = 1\). With \(f(0) = -1\) and \(f(2) = 1\), we know the function transitions from negative to positive, indicating that there is at least one root between \(x = 0\) and \(x = 2\).
04
Use a graphing calculator or computer grapher
Utilize a graphing calculator or graphing software to find the exact roots of \(x^3 - 3x - 1 = 0\). The graph will visually represent where \(f(x)\) intersects the x-axis, confirming the presence of a real solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Roots of Equations
Finding the roots of a polynomial equation means discovering the values of \(x\) where the polynomial equals zero. In simpler terms, roots are where the graph of the polynomial touches or crosses the x-axis. For the equation \(x^3 - 3x - 1 = 0\), the roots are the \(x\) values that make the equation true. These values are also known as the zeros of the polynomial function \(f(x) = x^3 - 3x - 1\).
To find these roots, we first need to understand the behavior of the polynomial function:
To find these roots, we first need to understand the behavior of the polynomial function:
- If \(f(x)\) is positive, the section of the graph is above the x-axis.
- If \(f(x)\) is negative, the section of the graph is below the x-axis.
- Roots occur where \(f(x) = 0\), meaning the graph either touches or crosses the x-axis.
Intermediate Value Theorem
The Intermediate Value Theorem (IVT) is an important concept in calculus that is often used to determine whether a continuous function has a root in a certain interval. A function \(f(x)\) is continuous if it can be drawn without lifting a pencil off the paper. The theorem states that if \(f\) is continuous on an interval \([a, b]\), and \(f(a)\) and \(f(b)\) have opposite signs, then there exists at least one value \(c\) in \( (a, b) \) where \(f(c) = 0\).
In our problem, we applied the IVT to demonstrate that \(x^3 - 3x - 1 = 0\) has a root in the interval \([0, 2]\). We calculated \(f(0) = -1\) and \(f(2) = 1\), indicating a sign change from negative to positive, which confirms the presence of a root in that section as per IVT. Without solving it directly, IVT suggests that the function must cross the x-axis, which translates to finding a solution. This approach is particularly useful when dealing with complex equations where analytical solutions may not easily derive the roots.
In our problem, we applied the IVT to demonstrate that \(x^3 - 3x - 1 = 0\) has a root in the interval \([0, 2]\). We calculated \(f(0) = -1\) and \(f(2) = 1\), indicating a sign change from negative to positive, which confirms the presence of a root in that section as per IVT. Without solving it directly, IVT suggests that the function must cross the x-axis, which translates to finding a solution. This approach is particularly useful when dealing with complex equations where analytical solutions may not easily derive the roots.
Graphical Solutions
Graphical solutions offer a visual approach to solving equations, particularly polynomial equations. When using a graphing calculator or computer software, you can plot the function to observe how it behaves in different regions.
The graph of \(f(x) = x^3 - 3x - 1\) shows a curve rather than a straight line, typical of cubic polynomials. The regions where this curve intersects the x-axis mark the roots of the equation. By plotting the polynomial, it is easier to identify these intersections, giving a clear picture of where \(x^3 - 3x - 1\) equals zero.
The graph of \(f(x) = x^3 - 3x - 1\) shows a curve rather than a straight line, typical of cubic polynomials. The regions where this curve intersects the x-axis mark the roots of the equation. By plotting the polynomial, it is easier to identify these intersections, giving a clear picture of where \(x^3 - 3x - 1\) equals zero.
- Potential roots can initially be noted through observation of where the plot crosses the x-axis.
- Graphical solutions not only provide approximate root locations but can also verify calculations from other methods, like the IVT.
- This technique offers a visual confirmation, enhancing understanding, especially when dealing with abstract algebraic manipulations.