Chapter 15: Problem 18
Although they are not defined on all of space \(R^{3},\) the fields associated with Exercises \(18-22\) are conservative. Find a potential function for each field and evaluate the integrals as in Example 6. $$\int_{(0,2,1)}^{(1, \pi / 2,2)} 2 \cos y d x+\left(\frac{1}{y}-2 x \sin y\right) d y+\frac{1}{z} d z$$
Short Answer
Step by step solution
Identify the Vector Field
Integrate to Find Potential Function with Respect to x
Integrate to Find Potential Function with Respect to y
Integrate to Find Potential Function with Respect to z
Combine Results for Complete Potential Function
Evaluate the Line Integral Using the Fundamental Theorem for Line Integrals
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Potential Function
- For the x-component, integrate the function with respect to \(x\) and add a function of \(y\) and \(z\), since these might depend on the other variables.
- For the y-component, integrate with respect to \(y\) and account for any arbitrary function of \(z\).
- Finally, for the z-component, integrate with respect to \(z\), obtaining the complete potential function.
Conservative Vector Field
- The vector field is defined everywhere in the domain. This condition can sometimes be relaxed if special properties hold, such as on domains called simply connected regions (no holes).
- The field is irrotational, meaning its curl is zero, \(abla \times \vec{F} = 0\).
Fundamental Theorem for Line Integrals
- Faster calculations, as you avoid integrating directly along the path.
- Simple application: find the potential function and compute its value at the endpoints.
- Higher-level understanding: it connects vector fields and scalar potentials, providing insights into the geometric properties of fields.