Chapter 14: Problem 8
Evaluate the iterated integral. $$\int_{1}^{4} \int_{0}^{4}\left(\frac{x}{2}+\sqrt{y}\right) d x d y$$
Short Answer
Expert verified
The value of the iterated integral is \( \frac{92}{3} \).
Step by step solution
01
Set Up the Nested Integral
The given iterated integral is \( \int_{1}^{4} \int_{0}^{4} \left( \frac{x}{2} + \sqrt{y} \right) dx \, dy \). This means we first need to integrate with respect to \( x \), treating \( y \) as a constant.
02
Evaluate the Inner Integral
Compute the inner integral \( \int_{0}^{4} \left( \frac{x}{2} + \sqrt{y} \right) dx \). The integral separates as \( \int_{0}^{4} \frac{x}{2} \, dx + \int_{0}^{4} \sqrt{y} \, dx \). Since \( \sqrt{y} \) is a constant with respect to \( x \), this becomes: \[ \int_{0}^{4} \frac{x}{2} \, dx = \left[ \frac{x^2}{4} \right]_0^4 = \frac{16}{4} = 4 \] \[ \int_{0}^{4} \sqrt{y} \, dx = \left( 4 \sqrt{y} - 0 \right) = 4\sqrt{y} \] Hence, the result of the inner integral is \( 4 + 4\sqrt{y} \).
03
Evaluate the Outer Integral
Now evaluate the outer integral \( \int_{1}^{4} (4 + 4\sqrt{y}) \, dy \). This splits into two integrals: \( \int_{1}^{4} 4 \, dy + \int_{1}^{4} 4\sqrt{y} \, dy \). Integrate each part separately: \[ \int_{1}^{4} 4 \, dy = 4[y]_1^4 = 4(4 - 1) = 12 \] \[ \int_{1}^{4} 4\sqrt{y} \, dy = 4 \int_{1}^{4} y^{1/2} \, dy = 4 \left[ \frac{2}{3} y^{3/2} \right]_1^4 = \frac{8}{3} (8 - 1) = \frac{56}{3} \]
04
Add the Results
Now add the results of the two integrals from the outer integral evaluation: \( 12 + \frac{56}{3} \). Convert 12 into thirds: \( 12 = \frac{36}{3} \). So, \[ \frac{36}{3} + \frac{56}{3} = \frac{92}{3} \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nested Integration
Nested integration, often referred to as iterated integration, is a method where we perform integrals over more than one variable. This process involves repeatedly integrating a function, taking into account different variables in a specific order. In our problem, we have been given an iterated integral, \[ \int_{1}^{4} \int_{0}^{4} \left( \frac{x}{2}+\sqrt{y} \right) dx \, dy \]. Here, the integration is first conducted with respect to the variable \( x \), while \( y \) is held constant, followed by integration with respect to \( y \).
- The procedure simplifies a complex integral into easier, sequential steps.
- It highlights the structure of the problem as each step tackles one layer of the integral.
Inner Integral
The inner integral is the first step in a nested integration process. It refers to integrating the function with respect to one variable while considering others as constants. In this problem, the inner integral is \[ \int_{0}^{4} \left( \frac{x}{2} + \sqrt{y} \right) dx \].
Firstly, separate the terms in the integral:
Firstly, separate the terms in the integral:
- \( \int_{0}^{4} \frac{x}{2} \, dx \)
- \( \int_{0}^{4} \sqrt{y} \, dx \)
Outer Integral
The outer integral is evaluated after computing the inner integral and involves integrating over the remaining variable. Once the inner integral gives us the function \( 4 + 4\sqrt{y} \), our task is to integrate it from \( y=1 \) to \( y=4 \). The outer integral becomes \[ \int_{1}^{4} (4 + 4\sqrt{y}) \, dy \].
Here, separate the expression into two simpler integrals:
Here, separate the expression into two simpler integrals:
- \( \int_{1}^{4} 4 \, dy \)
- \( \int_{1}^{4} 4\sqrt{y} \, dy \)
Evaluation of Definite Integrals
Evaluating definite integrals involves finding the accumulation of the function's values over a specified interval, resulting in a numerical value. In our problem, after performing the necessary integration processes, we add the results from the outer integral.
- The first part of the outer integral gives us \( 12 \).
- The second evaluation yields \( \frac{56}{3} \).