Chapter 14: Problem 54
Find the volume of the region bounded below by the paraboloid \(z=x^{2}+y^{2},\) laterally by the cylinder \(x^{2}+y^{2}=1,\) and above by the paraboloid \(z=\) \(x^{2}+y^{2}+1\).
Short Answer
Expert verified
The volume is \( \pi \).
Step by step solution
01
Identify the boundaries
The given paraboloids are \( z = x^2 + y^2 \) and \( z = x^2 + y^2 + 1 \). The lateral boundary is the cylinder \( x^2 + y^2 = 1 \). Our region of interest lies between the two paraboloids and within this cylinder.
02
Set up the volume integral
We are working with two paraboloids and a cylindrical boundary. We will use cylindrical coordinates because it naturally fits the cylindrical boundary: \( r^2 = x^2 + y^2 \), \( z = r^2 \), and \( z = r^2 + 1 \). The limits for \( r \) will be from 0 to 1, and for \( \theta \) from 0 to \( 2\pi \).
03
Determine the integrand
The integrand is the difference between the two paraboloids since we want the volume between them: \( (r^2 + 1) - r^2 = 1 \). So, we integrate this constant value with respect to the cylindrical coordinates.
04
Write the integral in cylindrical coordinates
The volume is given by the double integral \[ V = \int_{0}^{2\pi} \int_{0}^{1} (1) \, r \, dr \, d\theta \]The extra \( r \) in the integrand comes from converting the Cartesian area element \( dx \, dy \) to the cylindrical area element \( r \, dr \, d\theta \).
05
Integrate with respect to r
Calculate the integral with respect to \( r \):\[ \int_{0}^{1} r \, dr = \left[ \frac{r^2}{2} \right]_{0}^{1} = \frac{1}{2} \]
06
Integrate with respect to \( \theta \)
Now calculate the integral with respect to \( \theta \):\[ \int_{0}^{2\pi} \frac{1}{2} \, d\theta = \frac{1}{2} \times \left[ \theta \right]_{0}^{2\pi} = \frac{1}{2} \times 2\pi = \pi \]
07
Conclusion
The volume enclosed by the two paraboloids and the cylindrical boundary is \( \pi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cylindrical Coordinates
Cylindrical coordinates are a way to represent points in space using a combination of radial distance, angle, and height. Unlike Cartesian coordinates, which use
To convert from Cartesian to cylindrical coordinates:
- x,
- y,
- z-axis labels,
- a radial distance (r),
- angle (\(\theta\)),
- and height (z).
To convert from Cartesian to cylindrical coordinates:
- \(x = r\cos(\theta)\)
- \(y = r\sin(\theta)\)
- \(z = z\)
Paraboloid
A paraboloid is a three-dimensional surface that can be visualized as a continuous cross-section of parabolas. It comes in two main types: elliptical and hyperbolic. Our focus here is on the elliptical paraboloid, which, in simple terms, looks like a bowl or dish. This shape is often described using the equation \(z = x^2 + y^2\), which opens upwards.
Let's break down the behavior of the function:
Let's break down the behavior of the function:
- As you move away from the origin in any radial direction, the z value increases.
- The smallest z value is at the origin: \((x, y) = (0,0)\).
- The resulting surface is smooth and symmetrical around the z-axis.
Cylinder
A cylinder is a three-dimensional shape defined by its circular base and uniform height. Its cross-section at any parallel level is a circle. In this problem, the cylinder is described by the equation \(x^2 + y^2 = 1\), which represents all points equidistant from the origin, lying on a circle of radius 1 centered at the origin.
This equation defines the lateral boundary for the region we are looking at. Let's understand its key features:
This equation defines the lateral boundary for the region we are looking at. Let's understand its key features:
- The cylinder has an infinite length in the z-direction unless otherwise specified.
- In this exercise, our cylinder acts as the side walls demarcating the boundary for the paraboloid surfaces.
- Cylindrical coordinates are particularly useful here because they align perfectly with the circular nature of the boundary.