/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 The Sandwich Theorem for functio... [FREE SOLUTION] | 91Ó°ÊÓ

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The Sandwich Theorem for functions of two variables states that if \(g(x, y) \leq f(x, y) \leq h(x, y)\) for all \((x, y) \neq\left(x_{0}, y_{0}\right)\) in a disk centered at \(\left(x_{0}, y_{0}\right)\) and if \(g\) and \(h\) have the same finite limit \(L\) as \((x, y) \rightarrow\left(x_{0}, y_{0}\right)\) then$$\lim _{(x, y) \rightarrow\left(x_{0}, y_{0}\right)} f(x, y)=L$$ Use this result to support your answers to the questions. Does knowing that \(|\cos (1 / y)| \leq 1\) tell you anything about $$\lim _{(x, y) \rightarrow(0,0)} x \cos \frac{1}{y} ?$$ Give reasons for your answer.

Short Answer

Expert verified
The limit is 0 by the Sandwich Theorem, since \(-x \leq x\cos(1/y) \leq x\) and limits of bounding functions are 0.

Step by step solution

01

Understanding the Problem

We need to evaluate the limit \( \lim_{(x,y) \rightarrow (0,0)} x \cos \frac{1}{y} \). We know that \( |\cos(1/y)| \leq 1 \). We will use this inequality to apply the Sandwich Theorem.
02

Set the Inequality

Because \(|\cos(1/y)| \leq 1\), we multiply by \(x\) to get \(-x \leq x \cos(1/y) \leq x\). We will use this to create a bounding function pair \(g(x,y) = -x\) and \(h(x,y) = x\).
03

Identify Limits of Bounds

Evaluate the limits of \(g(x,y)\) and \(h(x,y)\) as \((x,y) \rightarrow (0,0)\). Both bounds have the limit \(\lim_{(x,y) \rightarrow (0,0)} g(x,y) = \lim_{(x,y) \rightarrow (0,0)} (-x) = 0\) and \(\lim_{(x,y) \rightarrow (0,0)} h(x,y) = \lim_{(x,y) \rightarrow (0,0)} x = 0\).
04

Apply the Sandwich Theorem

Since \(g(x,y) \leq f(x,y) \leq h(x,y)\) with both bounds having the limit \(0\) as \((x,y) \rightarrow (0,0)\), the Sandwich Theorem states that \(\lim_{(x,y) \rightarrow (0,0)} x \cos \frac{1}{y} = 0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit of Functions
The concept of the limit of a function is crucial in calculus, especially when analyzing the behavior of functions as they approach a particular point. A limit helps us understand the value that a function tends towards as the input gets closer to some point, even if the function is not explicitly defined at that point.
In this context, the Sandwich Theorem is instrumental. This theorem enables us to find the limit of a function that is "sandwiched" between two other functions whose limits are known. If a function \(f(x, y)\) is bounded by two other functions \(g(x, y)\) and \(h(x, y)\) such that \(g(x, y) \leq f(x, y) \leq h(x, y)\) and both \(g(x, y)\) and \(h(x, y)\) approach the same limit \(L\) as \((x, y)\) approaches \((x_0, y_0)\), then \(f(x, y)\) must also approach \(L\).
In essence, limits help describe the behavior of functions at points that may be difficult or impossible to evaluate directly.
Functions of Two Variables
Functions of two variables are expressions that depend on two independent factors, typically denoted as \(x\) and \(y\). Such functions, written as \(f(x, y)\), can describe phenomena that change based on two inputs, unlike single-variable functions.
These functions are evaluated in a plane, and the insights from studying them extend our understanding of how changes in one variable impact the function concerning another. When dealing with the limit of functions of two variables, the point of interest, like \((x_0, y_0)\), is approached from any direction within the plane.
Considering our exercise, we examined the limit \(\lim_{(x, y) \rightarrow (0,0)} x \cos \frac{1}{y}\). Here, \(x\) and \(y\) are two independent variables. The goal is to analyze how the function behaves as \(x\) and \(y\) simultaneously close in on zero, providing deeper understanding into multi-variable calculus.
Inequalities in Calculus
Inequalities are essential tools in calculus, often used to estimate or restrict the values a function can take. In this problem, we use inequalities to bound \(f(x, y) = x \cos \frac{1}{y}\) between two simple functions.
Given that \(|\cos(1/y)| \leq 1\), multiplying through by \(x\) yields \(-x \leq x \cos(1/y) \leq x\). This inequality is a pivotal step in applying the Sandwich Theorem. By controlling the boundaries within which \(f(x, y)\) can vary, we ensure that when both bounds tend to zero, the target function \(f(x, y)\) also conforms to this limit.
Inequalities thus facilitate the application of powerful theorems and ensure accurate evaluations of limits, allowing us to deduce consistent conclusions from otherwise complex problems.

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Most popular questions from this chapter

During the 1920 s, Charles Cobb and Paul Douglas modeled total production output \(P\) (of a firm, industry, or entire economy) as a function of labor hours involved \(x\) and capital invested \(y\) (which includes the monetary worth of all buildings and equipment). The Cobb-Douglas production function is given by $$P(x, y)=k x^{\alpha} y^{1-\alpha}$$ where \(k\) and \(\alpha\) are constants representative of a particular firm or economy. a. Show that a doubling of both labor and capital results in a doubling of production \(P\) b. Suppose a particular firm has the production function for \(k=\) 120 and \(\alpha=3 / 4 .\) Assume that each unit of labor costs $$ 250$ and each unit of capital costs $$ 400, and that the total expenses for all costs cannot exceed $$ 100,000 . Find the maximum production level for the firm.

If \(f\left(x_{0}, y_{0}\right)=3,\) what can you say about \(\lim _{(x, y) \rightarrow\left(x_{0}, y_{\mathrm{a}}\right)} f(x, y)\) if \(f\) is continuous at \(\left(x_{0}, y_{0}\right) ?\) If \(f\) is not continuous at \(\left(x_{0}, y_{0}\right) ?\) Give reasons for your answers.

Human blood types are classified by three gene forms \(A, B,\) and \(O .\) Blood types \(A A, B B,\) and \(O O\) are homozygous, and blood types \(A B, A O,\) and \(B O\) are heterozygous. If \(p, q,\) and \(r\) represent the proportions of the three gene forms to the population, respectively, then the Hardy-Weinberg Law asserts that the proportion \(Q\) of heterozygous persons in any specific population is modeled by $$Q(p, q, r)=2(p q+p r+q r)$$ subject to \(p+q+r=1 .\) Find the maximum value of \(Q\)

Gives a function \(f(x, y)\) and a positive number \(\epsilon\) In each exercise, show that there exists a \(\delta>0\) such that for all \((x, y)\) $$\sqrt{x^{2}+y^{2}}<\delta \Rightarrow|f(x, y)-f(0,0)|<\epsilon$$ $$f(x, y)=(x+y) /(2+\cos x), \quad \epsilon=0.02$$

Find the extreme values of a function \(f(x, y)\) on a curve \(x=x(t), y=y(t),\) we treat \(f\) as a function of the single variable \(t\) and use the Chain Rule to find where \(d f / d t\) is zero. As in any other single-variable case, the extreme values of \(f\) are then found among the values at the a. critical points (points where \(d f / d t\) is zero or fails to exist), and b. endpoints of the parameter domain. Find the absolute maximum and minimum values of the following functions on the given curves. Functions: $$f(x, y)=x y$$ Curves: i) The line \(x=2 t, \quad y=t+1\) ii) The line segment \(x=2 t, \quad y=t+1, \quad-1 \leq t \leq 0\) iii) The line segment \(x=2 t, \quad y=t+1, \quad 0 \leq t \leq 1\)

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