Chapter 12: Problem 34
Prove that if \(\mathbf{u}\) is the vector function with the constant value \(\mathbf{C},\) then \(d \mathbf{u} / d t=\mathbf{0}\).
Short Answer
Expert verified
Since \( \mathbf{u}(t) = \mathbf{C} \) and \( \mathbf{C} \) is constant, the derivative is \( \mathbf{0} \).
Step by step solution
01
Define the vector function
Let \( \mathbf{u}(t) \) be a vector function such that \( \mathbf{u}(t) = \mathbf{C} \), where \( \mathbf{C} \) is a constant vector. This means that \( \mathbf{u}(t) \) does not change with respect to \( t \).
02
Apply the definition of the derivative
The derivative of a vector function \( \mathbf{u}(t) \) with respect to \( t \) is defined as \( \frac{d\mathbf{u}}{dt} = \lim_{\Delta t \to 0} \frac{\mathbf{u}(t+\Delta t) - \mathbf{u}(t)}{\Delta t} \).
03
Substitute the constant vector in the derivative formula
Since \( \mathbf{u}(t) = \mathbf{C} \), we substitute it into the derivative formula: \( \mathbf{u}(t+\Delta t) = \mathbf{C} \) and \( \mathbf{u}(t) = \mathbf{C} \). Thus, \( \mathbf{u}(t+\Delta t) - \mathbf{u}(t) = \mathbf{C} - \mathbf{C} = \mathbf{0} \).
04
Evaluate the limit
Plug the result of the subtraction into the derivative formula: \( \frac{d\mathbf{u}}{dt} = \lim_{\Delta t \to 0} \frac{\mathbf{0}}{\Delta t} \). As \( \mathbf{0} \) divided by any non-zero \( \Delta t \) is still \( \mathbf{0} \), the limit evaluates to \( \mathbf{0} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Function
A vector function is a mathematical construct that assigns a vector to every value of a variable, often denoted as \( t \) for time. Imagine it as a continually changing arrow in space, where each point in time gets its own arrow pointing in a specific direction. This means vector functions can describe motion in physics, like the path of a moving object.
The general form of a vector function is \( \mathbf{u}(t) = \langle f(t), g(t), h(t) \rangle \), where \( f(t), g(t), \) and \( h(t) \) are scalar functions of \( t \). These functions define the components of the vector in three-dimensional space. By evaluating these component functions at different points of \( t \), you can find the vector's position at any time.
The general form of a vector function is \( \mathbf{u}(t) = \langle f(t), g(t), h(t) \rangle \), where \( f(t), g(t), \) and \( h(t) \) are scalar functions of \( t \). These functions define the components of the vector in three-dimensional space. By evaluating these component functions at different points of \( t \), you can find the vector's position at any time.
- Each component, \( f(t), g(t), h(t) \), corresponds to a different dimension.
- As \( t \) changes, the vector described by \( \mathbf{u}(t) \) moves along a certain path.
- The direction and length (magnitude) of the vector can change with \( t \).
Derivative of a Vector Function
The derivative of a vector function is a key concept showing how the vector changes as the variable, usually time \( t \), changes. It tells you the rate at which each component of the vector is changing — essentially providing insights into the velocity or speed of movement of the object the vector is describing.
It's represented as \( \frac{d\mathbf{u}}{dt} = \lim_{\Delta t \to 0} \frac{\mathbf{u}(t+\Delta t) - \mathbf{u}(t)}{\Delta t} \), similar to the derivative of a real-valued function in calculus, but applied to vectors. This results in a new vector, where each component is the derivative of the corresponding components of the original function:
It's represented as \( \frac{d\mathbf{u}}{dt} = \lim_{\Delta t \to 0} \frac{\mathbf{u}(t+\Delta t) - \mathbf{u}(t)}{\Delta t} \), similar to the derivative of a real-valued function in calculus, but applied to vectors. This results in a new vector, where each component is the derivative of the corresponding components of the original function:
- The derivative of \( \mathbf{u}(t) = \langle f(t), g(t), h(t) \rangle \) is \( \frac{d\mathbf{u}}{dt} = \langle f'(t), g'(t), h'(t) \rangle \).
- The magnitude of the derivative vector indicates how fast the vector's magnitude is changing.
- The direction of the derivative vector shows the direction of the fastest increase.
Constant Vector
A constant vector is a special case where a vector remains unchanged regardless of changes in the variable \( t \). In simpler terms, no matter what happens over time, the vector's size and direction stay the same.
In mathematical terms, if \( \mathbf{u}(t) = \mathbf{C} \), where \( \mathbf{C} \) is a constant vector, then that vector doesn't vary with \( t \). This permanency in size and direction means its derivative concerning \( t \) is zero, shown as \( \frac{d\mathbf{u}}{dt} = \mathbf{0} \).
In mathematical terms, if \( \mathbf{u}(t) = \mathbf{C} \), where \( \mathbf{C} \) is a constant vector, then that vector doesn't vary with \( t \). This permanency in size and direction means its derivative concerning \( t \) is zero, shown as \( \frac{d\mathbf{u}}{dt} = \mathbf{0} \).
- Since \( \mathbf{C} - \mathbf{C} = \mathbf{0} \), no change occurs, leading to a derivative of zero.
- The concept of a constant vector is crucial in simplifying complex problems where vectors need to be stable.
- Examples include constant forces or positions in physics problems.