Chapter 11: Problem 8
Give a geometric description of the set of points in space whose coordinates satisfy the given pairs of equations. $$y^{2}+z^{2}=1, \quad x=0$$
Short Answer
Expert verified
A circle of radius 1 in the yz-plane at x=0.
Step by step solution
01
Understanding the Equation
We start by analyzing the given equations. The first equation \( y^2 + z^2 = 1 \) describes a circle in the plane. The second equation \( x = 0 \) places the circle on the yz-plane at \( x = 0 \). The circle is centered at the origin \((0,0,0)\) with radius 1 on the yz-plane.
02
Visualizing the Circle
Imagine the yz-plane as the coordinate plane where the x-coordinate is always 0. The equation \( y^2 + z^2 = 1 \) forms a circle centered at the origin \((0, 0)\) in the yz-plane. Every point on this circle lies within a unit of 1 from the origin along the y and z axes.
03
Describing the Geometric Set
Since the equation restricts \( x = 0 \), the set of points is confined to the yz-plane. The circle \( y^2 + z^2 = 1 \) represents a vertical slice through the yz-plane. The entire set of points forms a cylinder along the y and z axes but exists specifically on the yz-plane indexed by the fixed x-coordinate.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equations of Circles
When talking about circles in coordinate geometry, the equation of a circle is vital. It helps us understand the shape and position of circles within coordinate planes. The general form of a circle's equation in the Cartesian coordinate system is \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) represents the circle's center, and \(r\) is its radius.
In our specific example, the equation \(y^2 + z^2 = 1\) is a slightly adjusted circle equation simplified for the yz-plane. Here, the absence of \(x\) in the equation implies that the center of this circle is aligned with the origin on the yz-plane with \(x = 0\), making \((0, 0)\) the center, and the radius is 1.
This means each point on this circle is directly 1 unit away from the center, along either the \(y\) or \(z\) axis. A complete understanding of these equations allows for the easy deduction of information about the geometric properties of circles.
In our specific example, the equation \(y^2 + z^2 = 1\) is a slightly adjusted circle equation simplified for the yz-plane. Here, the absence of \(x\) in the equation implies that the center of this circle is aligned with the origin on the yz-plane with \(x = 0\), making \((0, 0)\) the center, and the radius is 1.
This means each point on this circle is directly 1 unit away from the center, along either the \(y\) or \(z\) axis. A complete understanding of these equations allows for the easy deduction of information about the geometric properties of circles.
Coordinate Planes
The coordinate planes are a fundamental concept in analytic geometry, providing a flat two-dimensional surface where we can plot points and shapes. Each plane is defined by two of the three Cartesian coordinates: \(x\), \(y\), and \(z\).
In this context, our exercise involves the yz-plane, where the x-coordinate is constantly zero (\(x=0\)). Imagine holding a piece of flat paper aligned with this plane; it extends infinitely along the \(y\) and \(z\) directions but remains fixed in one position in the \(x\) direction.
In this context, our exercise involves the yz-plane, where the x-coordinate is constantly zero (\(x=0\)). Imagine holding a piece of flat paper aligned with this plane; it extends infinitely along the \(y\) and \(z\) directions but remains fixed in one position in the \(x\) direction.
- The "xy-plane" keeps z constant and serves to provide a view where only x and y coordinates vary.
- Similarly, the "xz-plane" keeps y constant allowing only changes to x and z coordinates.
- Each coordinate plane helps isolate a two-dimensional perspective of our three-dimensional space, simplifying the visualization and study of shapes like lines and circles.
Geometric Visualization
Visualizing geometric solutions in coordinate space enhances understanding and is a key part of solving analytic geometry problems. Our given situation involves visualizing a circle within a specific plane.
Start by imagining the circle, given by \(y^2 + z^2 = 1\), in the yz-plane. This means every point satisfying this circle's equation lies within this plane, forming a perfect circular shape centered at the coordinate \((0,0)\) on the yz-plane. Visualize this like a perfectly round frame.
Now, since the x-coordinate is fixed at zero in our problem (\(x = 0\)), the circle doesn't "float" around our three-dimensional space but is stuck or fixed specifically on the yz-plane. This turns our circular understanding into more of a flattened disk or slice, always wherever \(x\) is zero.
Start by imagining the circle, given by \(y^2 + z^2 = 1\), in the yz-plane. This means every point satisfying this circle's equation lies within this plane, forming a perfect circular shape centered at the coordinate \((0,0)\) on the yz-plane. Visualize this like a perfectly round frame.
Now, since the x-coordinate is fixed at zero in our problem (\(x = 0\)), the circle doesn't "float" around our three-dimensional space but is stuck or fixed specifically on the yz-plane. This turns our circular understanding into more of a flattened disk or slice, always wherever \(x\) is zero.
- To help, picture a donut standing upright, where the "hole" or circle only spans the yz-plane.
- The circle, then, can be part of a cylinder where the height isn't in the z-direction as you might expect, but rather the yz surface extends "up" in the sense of existing wholly without deviation from \(x = 0\).