Chapter 10: Problem 4
Identify the symmetries of the curves. Then sketch the curves in the \(x y\) -plane. $$r=1+\sin \theta$$
Short Answer
Expert verified
The curve is symmetric about \(\theta=\frac{\pi}{2}\) and is shaped like a cardioid.
Step by step solution
01
Identify Symmetries - Check for Reflection Symmetry
First, we need to determine if the curve is symmetric with respect to the polar axis (the x-axis), the line \(\theta = \frac{\pi}{2}\) (the y-axis), or the origin. A curve is symmetric with respect to the polar axis if for every point \((r, \theta)\), the point \((r, -\theta)\) is also on the curve. Substitute \(-\theta\) into the equation: \[r = 1 + \sin(-\theta) = 1 - \sin\theta.\] The equation \(r = 1 - \sin\theta\) is different from the original equation, indicating no symmetry with respect to the polar axis.
02
Identify Symmetries - Check for Symmetry with Line \(\theta=\frac{\pi}{2}\)
Check if the curve is symmetric with respect to the line \(\theta = \frac{\pi}{2}\). A curve is symmetric if substituting \(\pi-\theta\) for \(\theta\) results in an equivalent expression: \[r = 1 + \sin(\pi - \theta) = 1 + \sin\theta.\] This substitution returns the original equation, confirming symmetry with respect to the line \(\theta = \frac{\pi}{2}\).
03
Identify Symmetries - Check for Origin Symmetry
To check for origin symmetry, substitute \((r, \theta)\) with \((-r, \theta+\pi)\). This gives \[r = 1 + \sin(\theta) = -r' + \sin(-\theta) = -r' - \sin(\theta).\] Upon simplifying, this does not result in the original equation \(r = 1 + \sin \theta\), indicating no origin symmetry.
04
Sketch the Curve - Identify Points and Shape
Now, plot several points by substituting values of \(\theta\) into \(r = 1 + \sin \theta\). Calculate \(r\) for different \(\theta\):- For \(\theta=0\), \(r=1 + \sin(0)=1\).- For \(\theta=\frac{\pi}{2}\), \(r=1 + \sin(\frac{\pi}{2})=2\).- For \(\theta=\pi\), \(r=1 + \sin(\pi)=1\).- For \(\theta=\frac{3\pi}{2}\), \(r=1 + \sin(\frac{3\pi}{2})=0\).Connect these points to see the general heart-like shape known as a cardioid.
05
Final Graphical Representation of the Cardioid
Using the points calculated, sketch the curve in the Cartesian plane. The curve is a cardioid, which touches the origin at \(\theta=\frac{3\pi}{2}\) and has a maximum distance of 2 units from the origin at \(\theta=\frac{\pi}{2}\). It's symmetric about the vertical line \(\theta = \frac{\pi}{2}\) as previously determined.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Reflection Symmetry in Polar Coordinates
Reflection symmetry in polar coordinates involves determining if a curve is a mirror image across specific lines or points. A curve's symmetry can be checked with respect to three main axes: the polar axis, vertical axis, and the origin.
To see if a curve exhibits reflection symmetry about the polar axis (akin to the x-axis), substitute \( \theta \) with \( -\theta \) in the polar equation and check if the equation remains unchanged. For our equation \( r = 1 + \sin(\theta) \), replacing results in \( r = 1 - \sin(\theta) \), which differs from the original, showing no symmetry here.
For symmetry about the vertical line \( \theta = \frac{\pi}{2} \), substitute \( \pi - \theta \) for \( \theta \), which yields the original equation \( r = 1 + \sin(\theta) \). This confirms symmetry across the \( \theta = \frac{\pi}{2} \) line.
To test for origin symmetry, substitute \( (-r, \theta + \pi) \). If this procedure results in the original equation, the curve is origin-symmetric. Our result doesn’t match, showing no origin symmetry. Understanding these symmetries is important for accurately modeling and sketching polar curves.
To see if a curve exhibits reflection symmetry about the polar axis (akin to the x-axis), substitute \( \theta \) with \( -\theta \) in the polar equation and check if the equation remains unchanged. For our equation \( r = 1 + \sin(\theta) \), replacing results in \( r = 1 - \sin(\theta) \), which differs from the original, showing no symmetry here.
For symmetry about the vertical line \( \theta = \frac{\pi}{2} \), substitute \( \pi - \theta \) for \( \theta \), which yields the original equation \( r = 1 + \sin(\theta) \). This confirms symmetry across the \( \theta = \frac{\pi}{2} \) line.
To test for origin symmetry, substitute \( (-r, \theta + \pi) \). If this procedure results in the original equation, the curve is origin-symmetric. Our result doesn’t match, showing no origin symmetry. Understanding these symmetries is important for accurately modeling and sketching polar curves.
The Cardioid Curve: A Heart-Shaped Graph
The cardioid is a special type of polar curve defined by the equation \( r = 1 + \sin(\theta) \). This equation results in a distinctive heart-like shape when plotted.
The key features of a cardioid include its symmetry and its range of values:
The key features of a cardioid include its symmetry and its range of values:
- Symmetry with respect to the vertical line \( \theta = \frac{\pi}{2} \).
- No symmetry about the polar axis or the origin.
- Maximum value of \( r \) occurs when \( \theta = \frac{\pi}{2} \), resulting in \( r = 2 \).
- The cardioid touches the origin point \( (0, 0) \) at \( \theta = \frac{3\pi}{2} \).
Techniques for Curve Sketching in Polar Coordinates
Curve sketching in polar coordinates requires plotting by substituting values of \( \theta \) to find corresponding values of \( r \). This technique captures the shape of the curve on the plane.
Begin by creating a table of \( \theta \) values and computing \( r \) for each:
Additional tips for polar curve sketching:
Begin by creating a table of \( \theta \) values and computing \( r \) for each:
- \( \theta = 0 \rightarrow r = 1 + \sin(0) = 1 \)
- \( \theta = \frac{\pi}{2} \rightarrow r = 1 + \sin(\frac{\pi}{2}) = 2 \)
- \( \theta = \pi \rightarrow r = 1 + \sin(\pi) = 1 \)
- \( \theta = \frac{3\pi}{2} \rightarrow r = 1 + \sin(\frac{3\pi}{2}) = 0 \)
Additional tips for polar curve sketching:
- Plot additional points for more detailed curves.
- Use symmetry properties to minimize computations.
- Always verify sketch with known features like intercepts and maximums.