Chapter 1: Problem 26
Graph the functions.
$$g(x)=\left\\{\begin{array}{ll}1-x, & 0 \leq x \leq 1 \\\2-x, & 1
Short Answer
Expert verified
Graph consists of two linear sections: from \((0,1)\) to \((1,0)\) and from \((1,1)\) to \((2,0)\).
Step by step solution
01
Understand the Function Parts
The given function is a piecewise function that has two parts:1. **Part 1:** For the domain where \(0 \leq x \leq 1\), the function is defined as \(g(x) = 1-x\).2. **Part 2:** For the domain where \(1 < x \leq 2\), the function is defined as \(g(x) = 2-x\).These two parts will have different expressions based on where the value of \(x\) lies in the given domains.
02
Define the Domain and Range for Each Part
**Part 1:**- **Domain:** \(0 \leq x \leq 1\)- **Range:** Calculate the function at the domain endpoints: - At \(x=0\), \(g(x)=1-0=1\). - At \(x=1\), \(g(x)=1-1=0\). - So, the range is \([0, 1]\).**Part 2:**- **Domain:** \(1 < x \leq 2\)- **Range:** Calculate the function at the domain endpoints: - At \(x=1\), just for continuity, \(g(1^+)=2-1=1\). - At \(x=2\), \(g(x)=2-2=0\). - So, the range is \([0, 1)\).
03
Sketch the Graph for Part 1
For \(0 \leq x \leq 1\), the function is linear with the equation \(y=1-x\). This is a downward-sloping line from point \((0,1)\) to \((1,0)\). Plot both the points and connect them with a straight line, noting that there's a closed (filled) circle at \((0,1)\) and an open (unfilled) circle at \((1,0)\) because part 2 begins there.
04
Sketch the Graph for Part 2
For \(1 < x \leq 2\), the function is linear with the equation \(y=2-x\). This is a downward-sloping line from point \((1,1)\) to \((2,0)\). Plot these points and connect them with a straight line. At \((1,1)\), the circle is open since \(x\) does not include 1 for this segment, while at \((2,0)\) the circle is closed.
05
Combine the Parts of the Graph
Now, combine both parts on the Cartesian plane:- From \(x=0\) to \(x=1\), follow the line from \((0,1)\) to \((1,0)\) and mark with an open circle at \((1,0)\).- Continue from \(x=1\) with an open circle from \((1,1)\) to \((2,0)\), marking \((2,0)\) with a closed circle as the end point of the second segment.This results in a continuous piecewise graph composed of two linear sections.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Graphing in Practice
Graphing functions helps us visualize how a function behaves. For a piecewise function like our example, graphing involves plotting two separate linear segments on the same set of axes. Each segment corresponds to a different formula that applies to specific intervals of the domain. This function is defined in two parts: \(g(x) = 1-x\) for \(0 \leq x \leq 1\) and \(g(x) = 2-x\) for \(1 < x \leq 2\).
Here's how to approach graphing each part:
Here's how to approach graphing each part:
- Start by identifying the interval for each piece and use these to frame the respective sections of the graph.
- Plot the start and end points of each interval. For \(g(x) = 1-x\), plot points \((0,1)\) and \((1,0)\).
- Draw the slope connecting these points. Ensure the end points are correctly represented: filled if included in the range and open if not.
Understanding Domain and Range
The domain of a function refers to all possible input values (x-values) for which the function is defined, while the range is the set of possible output values (y-values). For our piecewise function, we have distinct domains for each part:
**Part 1**:
**Part 1**:
- Domain: \(0 \leq x \leq 1\)
- Range: Obtained by evaluating the function at \(x=0\) and \(x=1\), resulting in values \(1\) and \(0\), respectively. Thus, range is \([0, 1]\).
- Domain: \(1 < x \leq 2\)
- Range: Here, evaluate at the boundary \(x=2\) (which gives \(0\)) and at just over 1 (giving \(1\)), so range is \([0, 1)\).
Characteristics of Linear Functions
Linear functions graph as straight lines and have the form \(y = mx + b\) where \(m\) is the slope and \(b\) is the y-intercept. In the piecewise function from the exercise, we have two linear functions:
- For \(g(x) = 1-x\), the function represents a line with a slope of \(-1\), starting at y-intercept 1.
- For \(g(x) = 2-x\), it also has a slope of \(-1\) but starts higher, at y-intercept 2.