Chapter 8: Problem 22
Factor each of the following expressions as completely as possible. If an expression is not factorable, say so. $$12-8 a+a^{2}$$
Short Answer
Expert verified
The expression \(12 - 8a + a^2\) factors to \((a - 6)(a - 2)\).
Step by step solution
01
Rewrite the Expression
Rewrite the expression in standard form (descending power of a): \[a^2 - 8a + 12\]
02
Identify Coefficients
Identify the coefficients for the quadratic term, linear term, and constant term. Here, they are:\[a^2 + (-8a) + 12\] where \(a = 1\), \(b = -8\), \(c = 12\).
03
Find Two Numbers that Multiply and Add
Find two numbers that multiply to \(ac = 1 \times 12 = 12\) and add to \(b = -8\). These numbers are \(-6\) and \(-2\) because \(-6 \times -2 = 12\) and \(-6 + -2 = -8\).
04
Write Middle Term as a Sum
Rewrite the expression using \(-6\) and \(-2\) to split the middle term:\[a^2 - 6a - 2a + 12\]
05
Factor by Grouping
Factor by grouping. Group the terms into pairs:\[(a^2 - 6a) + (-2a + 12)\]Now factor out the greatest common factor from each pair:\[a(a - 6) - 2(a - 6)\]
06
Factor out the Common Binomial
Factor out the common binomial factor \((a - 6)\):\[(a - 6)(a - 2)\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equations
Quadratic equations are fundamental in algebra and appear in numerous math problems. A quadratic equation is any equation that can be written in the form: ax^2 + bx + c = 0, where:
- a, b, and c are polynomial coefficients.
- x represents the variable.
- a ≠0 (if a were zero, the equation would be linear, not quadratic).
Factoring by Grouping
Factoring by grouping is a useful method for factoring quadratic polynomials when simple factoring isn’t immediately obvious. This technique involves grouping the terms of the polynomial in pairs to identify a common binomial factor. Here’s how to do it effectively with our initial problem 12 - 8a + a^2, which we restructured as: a^2 - 8a + 12. Follow these steps:
- First, rewrite the polynomial by splitting the middle term into two terms whose coefficients add to the original middle coefficient (-8 in our case) and multiply to the constant term (12). This result gives us: a^2 - 6a - 2a + 12.
- Group the terms into two pairs: (a^2 - 6a) + (-2a + 12).
- Factor out the greatest common factor from each group: a(a - 6) - 2(a - 6).
- Notice that (a - 6) is a common factor in both grouped terms. Factor it out to obtain: (a - 6)(a - 2).
Polynomial Coefficients
Polynomial coefficients play a crucial role in defining the characteristics and behavior of polynomials. These coefficients are the numerical factors that multiply the terms of the polynomial. In the quadratic equation ax^2 + bx + c, the coefficients are a, b, and c. Understanding how to identify and manipulate these coefficients is fundamental in algebra. Consider the quadratic polynomial in our example: a^2 - 8a + 12. The coefficients are:
- a (coefficient of a^2) = 1.
- b (coefficient of a) = -8.
- c (constant term) = 12.