/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 Simplify each of the following a... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify each of the following as completely as possible. $$\frac{\left(x^{4}\right)^{3}}{\left(x^{3}\right)^{2}}$$

Short Answer

Expert verified
\(x^6\)

Step by step solution

01

Apply the Power of a Power Rule

First, use the power of a power rule \((a^m)^n = a^{m \times n}\). For the numerator, \((x^4)^3 = x^{4 \times 3} = x^{12}\). For the denominator, \((x^3)^2 = x^{3 \times 2} = x^6\). The fraction now becomes \frac{x^{12}}{x^6}\.
02

Apply the Quotient of Powers Rule

Next, use the quotient of powers rule \(a^m / a^n = a^{m-n}\). For the fraction \frac{x^{12}}{x^6}\, subtract the exponent in the denominator from the exponent in the numerator: \x^{12-6} = x^{6}\.
03

Simplify the Expression

Combine the results from the previous step to get the simplified expression. The final simplified form is \(x^6\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power of a Power Rule
The 'Power of a Power Rule' is a fundamental exponent rule. It states that when you have an exponent raised to another exponent, you multiply the exponents together. This can be written as \((a^m)^n = a^{m \times n}\).

Let's apply this to our exercise. We have \((x^4)^3\) in the numerator. By using the power of a power rule, we multiply the exponents:
4 multiplied by 3 equals 12, so \((x^4)^3 = x^{12}\).
In the denominator, we have \((x^3)^2\). Similarly, we multiply the 3 by 2, getting 6, which gives us \((x^3)^2 = x^6\).
So the fraction becomes \(\frac{x^{12}}{x^6}\).
Quotient of Powers Rule
The 'Quotient of Powers Rule' helps when you are dividing like bases with different exponents. It states that you subtract the exponent of the denominator from the exponent of the numerator. The rule can be written as \(a^m / a^n = a^{m-n}\).

Applying this rule to our fraction \(\frac{x^{12}}{x^6}\), we subtract the exponent in the denominator (6) from the one in the numerator (12):
\(\frac{x^{12}}{x^6} = x^{12-6} = x^6\).
This step simplifies the fraction significantly!
Exponent Subtraction
Exponent subtraction plays a crucial part when simplifying expressions involving division of powers. It is essentially what we do in the quotient of powers rule. Whenever you see like bases being divided, remember you are essentially subtracting the exponents.

For instance, in our simplified fraction \( \frac{x^{12}}{x^6} \), exponent subtraction gives us \ x^{12-6} \ and simplifies down to\ x^6 \. This is also known as exponent subtraction.

Always ensure that the bases are the same before subtracting the exponents. This will help ensure your math is accurate and the simplification is correct.
With practice, exponent subtraction will become second nature and will help you simplify complex expressions efficiently!

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Most popular questions from this chapter

Estimate the answer without actually carrying out the computation and make the most appropriate choice. If you divide 2350 by \(48,600\), the result is closest to (a) 0.05 (b) 0.5 (c) 5 (d) 50 (e) 500

Multiply out each of the following. As you work out the problems, identify those exercises that are either a perfect square or the difference of two squares. $$(3 x-4)(5 x+7)$$

Do your computations using scientific notation. If 1 in. is equal to \(2.54 \mathrm{cm},\) how many angstroms are there in 1 inch?

In this section we defined \(a^{0}=1 .\) It is important to realize that a definition is neither right nor wrong-it just is. The proper question to ask about a definition is "Is it useful?" What happens if someone decides on an "alternative definition" such as \(a^{0}=7\) because 7 happens to be his or her favorite number? What happens when we consider the expression \(a^{0} \cdot a^{4} ?\) If you use exponent rule 1 you get \(a^{0} \cdot a^{4}=a^{0+4}=a^{4} .\) However, if you use this alternative definition, you get \(a^{0} \cdot a^{4} \stackrel{\underline{2}}{=} 7 a^{4} .\) The answer we get from the alternative definition is not consistent with the answer we get from the exponent rule. The exponent rules and this alternative definition cannot coexist. Since we do not want to throw away all the exponent rules, we must modify the alternative definition so that it is consistent with all the exponent rules. Verify that our definition of \(a^{0}=1\) is consistent with all five exponent rules.

Convert each number into standard notation. $$78,951 \times 10^{-5}$$

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