/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Find the slope of the line passi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the slope of the line passing through the given points. Round to the nearest hundredth where necessary. \((3.7,-1.05)\) and \((-2.16,4.9)\)

Short Answer

Expert verified
The slope of the line is approximately \(-1.02\).

Step by step solution

01

Recall the Slope Formula

The formula for the slope of a line passing through two points \(x_1, y_1\) and \(x_2, y_2\) is given by \[ m = \frac{y_2 - y_1}{x_2 - x_1} \].
02

Identify the Points

Assign \(x_1, y_1\) to \(3.7, -1.05\) and \(x_2, y_2\) to \(-2.16, 4.9\).
03

Substitute the Values

Plug the coordinates into the slope formula: \[ m = \frac{4.9 - (-1.05)}{-2.16 - 3.7} \].
04

Simplify the Numerator

Calculate the numerator first: \(4.9 - (-1.05) = 4.9 + 1.05 = 5.95\).
05

Simplify the Denominator

Now, calculate the denominator: \(-2.16 - 3.7 = -5.86\).
06

Calculate the Slope

Finally, divide the numerator by the denominator: \[ m = \frac{5.95}{-5.86} \approx -1.02 \].

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope Formula
In coordinate geometry, the slope of a line is a measure of its steepness. Knowing how to find the slope is essential when dealing with line equations. The formula for the slope, denoted as \(m\), can be remembered by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Here, \((x_1, y_1)\) and \((x_2, y_2)\) are two points on the line. This formula calculates the 'rise' over 'run', showing how much the line goes up or down for each unit it goes across. For example, if we have two points like \((3.7, -1.05)\) and \((-2.16, 4.9)\), substituting them into the slope formula, we get: \[ m = \frac{4.9 - (-1.05)}{-2.16 - 3.7} \] This will help find the slope by determining the difference between the y-coordinates divided by the difference between the x-coordinates.
Coordinate Geometry
Coordinate geometry allows us to use algebraic techniques to solve geometry problems. It involves the use of the coordinate plane, a grid defined by a horizontal (x-axis) and a vertical (y-axis) line. Each point on this plane has an ordered pair of coordinates \((x, y)\) that denote its position. When working with points like \((3.7, -1.05)\) and \((-2.16, 4.9)\), we can visualize them on this grid. This helps in comprehending how the slope formula works in a two-dimensional space. By moving from point \( A (x_1, y_1) \) to point \( B (x_2, y_2) \), we can see the change in the y-values and x-values, which contributes to our understanding of the line's steepness—its slope.
Line Equations
When dealing with lines, it's important to know their equations. They are often written in the slope-intercept form: \[ y = mx + b \] Here, \(m\) is the slope and \(b\) is the y-intercept (where the line crosses the y-axis). Once we know the slope using the formula \( m = \frac{y_2 - y_1}{x_2 - x_1} \), we can plug it into this form if we know one of the points on the line. In our case, with the slope \( m \approx -1.02 \) from the points \((3.7, -1.05)\) and \((-2.16, 4.9)\), finding the equation is straightforward. If needed, we can substitute one of the points into the equation to find \(b\).
Numerical Computation
Accurate numerical computation is key when calculating the slope of a line, especially when working with decimals. Let's break it down: First, identify your points: \((x_1, y_1) = (3.7, -1.05)\) and \((x_2, y_2) = (-2.16, 4.9)\). Next, calculate the numerator: \[ y_2 - y_1 = 4.9 - (-1.05) = 4.9 + 1.05 = 5.95 \] Then, find the denominator: \[ x_2 - x_1 = -2.16 - 3.7 = -5.86 \] Finally, compute the slope: \[ m = \frac{5.95}{-5.86} \approx -1.02 \] Breaking down each step ensures clarity and prevents mistakes. Consider rounding your results to prevent miscalculations, such as rounding to the nearest hundredth to get \(-1.02\).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Round off to the nearest hundredth when necessary. A gourmet food shop sells custom blended coffee by the ounce. Suppose that 1 oz sells for 1.70 dollar and 2 oz sells for 3.20 dollar Assume that the cost \(c\) of the coffee is linearly related to the number of ounces \(n\) purchased (where \(n \geq 1\) ). (a) Write an equation relating the cost of the coffee to the number of ounces purchased. (b) What would be the cost of 3.5 oz of coffee? (c) Suppose a package of coffee is marked at 6.50 dollar but has no indication of how much coffee it contains. Determine the number of ounces of coffee this package contains. (d) Sketch a graph of this equation for \(n \geq 1\) using the horizontal axis for \(n\) and the vertical axis for \(c .\)

Sketch the graph of the line satisfying the given conditions. Passing through \((-1,0)\) with slope \(-4\)

The conveyor belt on a certain assembly line has a grade of \(3.2 \% .\) If the belt carries items through a vertical distance of \(12.8 \mathrm{ft}\), how long is the belt?

Write an equation of the line satisfying the given conditions. Horizontal line passing through \((2,3)\)

Sets of values are given for variables having a linear relationship. In each case, write the slope-intercept form for the equation of the line corresponding to the given set of values and answer the accompanying question. $$\begin{array}{|l|c|c|} \hline x \text { (Number of hours spent studying) } & 2 & 3 \\ \hline y \text { (Grade on math exam) } & 75 & 82 \\ \hline \end{array}$$ What would the grade be if a student studies for 5 hours?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.