Chapter 11: Problem 26
Sketch the graph of the given equation. Find the intercepts; approximate to the nearest tenth where necessary. $$y=-(x+3)^{2}$$
Short Answer
Expert verified
Vertex at (-3, 0), y-intercept at (0, -9), x-intercept at (-3, 0).
Step by step solution
01
Identify the Equation Type
The given equation is a quadratic equation in vertex form, which is generally written as \[ y = a(x-h)^2 + k \] where \( (h, k) \) is the vertex.
02
Find the Vertex
Rewrite the equation in vertex form: \[ y = -(x + 3)^2 \] This lets us identify that \( h = -3 \) and \( k = 0 \). Hence, the vertex of the parabola is at \( (-3,0) \).
03
Determine the Direction of the Parabola
Since the coefficient of the squared term is negative (\( a = -1 \)), the parabola opens downwards.
04
Find the Y-Intercept
The y-intercept is the value of \( y \) when \( x = 0 \). Substitute \( x = 0 \) into the equation: \[ y = -(0 + 3)^2 \] Simplify it: \[ y = -9 \]. Therefore, the y-intercept is at (0, -9).
05
Find the X-Intercepts
The x-intercepts are the values of \( x \) when \( y = 0 \). Set \( y = 0 \) and solve for \( x \): \[ 0 = -(x + 3)^2 \] Solve the equation: \[(x + 3)^2 = 0 \] \( x = -3 \). Hence, the x-intercept is at ( -3, 0).
06
Sketch the Graph
Plot the vertex \((-3, 0)\) and the intercepts ( -3, 0) and (0, -9). Draw a downward-opening parabola through these points, ensuring it is symmetrical about the vertex.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Equation
A quadratic equation is a second-degree polynomial equation in a single variable, usually written as a x^2 + bx + c = 0 where a ≠0.Key characteristics:• The graph of a quadratic equation is a parabola.• The coefficient 'a' determines the direction (upward if a > 0, downward if a < 0).• It can have zero, one, or two real solutions.In the exercise, the quadratic equation given is already in the vertex form, y = -(x + 3)^2, an example of a quadratic equation.
Vertex Form
The vertex form of a quadratic equation is y = a(x - h)^2 + k,where (h, k) is the vertex of the parabola.Important elements:
- The vertex is the highest or lowest point on the graph, depending on the parabola's direction.
- The coefficient 'a' determines the width and direction of the parabola. The parabola gets narrower as |a| increases.
- If 'a' is positive, the parabola opens upwards. If 'a' is negative, it opens downwards.
- The equation y = -(x + 3)^2 shows the vertex form with h = -3 and k = 0.
- Therefore, the vertex is at (-3, 0).
Intercepts
Intercepts are points where the graph crosses the axes.
- Y-Intercept is where the graph crosses the y-axis (x = 0).
- X-Intercepts are where the graph crosses the x-axis (y = 0).