/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Sketch the graph of the given eq... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of the given equation. Find the intercepts; approximate to the nearest tenth where necessary. $$y=x^{2}-4 x-12$$

Short Answer

Expert verified
Intercepts: (0, -12), (6, 0), (-2, 0). Vertex: (2, -16).

Step by step solution

01

Identify the equation

The given equation is a standard quadratic function: \( y = x^2 - 4x - 12 \)
02

Find the y-intercept

Set \( x = 0 \) and solve for \( y \): \( y = (0)^2 - 4(0) - 12 = -12 \). Hence, the y-intercept is \( (0, -12) \).
03

Find the x-intercepts

Set \( y = 0 \) and solve for \( x \): \( 0 = x^2 - 4x - 12 \). Solve the quadratic equation using the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Here, \( a = 1 \), \( b = -4 \), and \( c = -12 \): \( x = \frac{4 \pm \sqrt{16 + 48}}{2} = \frac{4 \pm \sqrt{64}}{2} = \frac{4 \pm 8}{2} \). Thus, the solutions are \( x = 6 \) and \( x = -2 \). Hence, the x-intercepts are \( (6, 0) \) and \( (-2, 0) \).
04

Determine the vertex

The vertex formula for a quadratic equation \( y = ax^2 + bx + c \) is \( x = -\frac{b}{2a} \): \( x = -\frac{-4}{2(1)} = 2 \). To find the y-coordinate, substitute \( x = 2 \) into the equation: \( y = (2)^2 - 4(2) - 12 = 4 - 8 - 12 = -16 \). Thus, the vertex is \( (2, -16) \).
05

Sketch the graph

Plot the intercepts \( (0, -12) \), \( (6, 0) \), and \( (-2, 0) \), as well as the vertex \( (2, -16) \). Draw a parabola opening upwards through these points. Label all critical points on the sketch.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations

A quadratic equation is any equation in the form y = ax² + bx + c where a, b, and c are constants. Quadratic equations form parabolic shapes when graphed. These equations are crucial for modeling various real-world phenomena like projectile motion and area problems.


In the given equation y = x² - 4x - 12, the coefficients are:


  • a = 1
  • b = -4
  • c = -12

Recognizing these coefficients helps in further calculations like finding intercepts and the vertex, essential steps for graphing the parabola.


This form is often called the 'Standard Form' of a quadratic equation. Understanding the meanings and roles of a, b, and c is foundational to mastering quadratic functions.

Intercepts

Intercepts are points where the graph crosses the axes:


  • Y-Intercept: This is found when x is set to 0. Solve y = x² - 4x - 12 at x = 0 to get:
  • y = (0)² - 4(0) - 12 = -12
  • Thus, the y-intercept is (0, -12).
  • X-Intercepts: These are found when y is set to 0. Set y = 0 in y = x² - 4x - 12 and solve the resulting quadratic equation:
  • 0 = x² - 4x - 12
  • Using the quadratic formula: x = \(\frac{-(-4) ± \sqrt{(-4)² - 4(1)(-12)}}{2(1)}\)
  • This resolves to: x = 6 and x = -2
  • Thus, the x-intercepts are (6, 0) and (-2, 0).
Vertex Formula

The vertex of a parabola gives a peak or a trough, representing the maximum or minimum value. For a quadratic equation y = ax² + bx + c, the vertex formula is:


  • x = -\(\frac{b}{2a}\)
  • For the given equation y = x² - 4x - 12:
  • b = -4 and a = 1, so x = -\(\frac{-4}{2(1)}\) = 2
  • Then, calculate y at x = 2:
  • y = (2)² - 4(2) - 12 = -16

Thus, the vertex is (2, -16).

Parabolas

A parabola is the U-shaped curve of a quadratic function. These curves open upwards if a > 0 and downwards if a < 0. Parabolas have a functional symmetry about their vertex.


To sketch a parabola:


  • Identify intercepts like (0, -12), (6, 0), and (-2, 0).
  • Find and mark the vertex, in this example, (2, -16).
  • Plot these critical points and draw a smooth curve through them, making sure the curve opens upwards due to a being positive.
  • Label all key points for clarity.

This method helps visualize quadratic relationships and understand the curve's behavior.

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