/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 For a fixed confidence level, ho... [FREE SOLUTION] | 91Ó°ÊÓ

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For a fixed confidence level, how does the length of the confidence interval for predicted values of \(y\) change as the corresponding \(x\) values become further away from \(\bar{x} ?\)

Short Answer

Expert verified
The confidence interval length for \( y \) increases as \( x \) moves further from \( \bar{x} \).

Step by step solution

01

Understanding the Problem

We need to consider how the confidence interval for predicted values of \( y \) changes as \( x \) moves away from the mean of \( x \), \( \bar{x} \), while keeping the confidence level fixed.
02

Analyzing Confidence Interval Formula

The formula for the confidence interval in linear regression is often calculated as: \[ \hat{y} \pm t_{\alpha/2, n-2} \cdot SE(\hat{y}) \] where \( SE(\hat{y}) = s \sqrt{\frac{1}{n} + \frac{(x - \bar{x})^2}{S_{xx}}} \). Notice the term \( \frac{(x - \bar{x})^2}{S_{xx}} \), which increases as \( x \) moves away from \( \bar{x} \).
03

Identifying Changes in Standard Error

Since \( SE(\hat{y}) \) depends on \( \frac{(x - \bar{x})^2}{S_{xx}} \), as \( x \) gets further from \( \bar{x} \), \( SE(\hat{y}) \) increases. Thus, the width of the confidence interval, \( 2 \cdot t_{\alpha/2, n-2} \cdot SE(\hat{y}) \), also increases.
04

Conclusion

As the \( x \) values become further from \( \bar{x} \), the length of the confidence interval for \( y \) increases due to the increase in the standard error as predicted by the term \( \frac{(x - \bar{x})^2}{S_{xx}} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression
Linear regression is a fundamental statistical method used to model the relationship between two variables by fitting a linear equation to the observed data. The primary aim is to predict the value of a dependent variable, often denoted as \( y \), based on the value of an independent variable, \( x \). The linear equation can be expressed in the form: \( y = \beta_0 + \beta_1 x + \epsilon \). Here, \( \beta_0 \) is the intercept, \( \beta_1 \) is the slope, and \( \epsilon \) represents the error term.
The slope, \( \beta_1 \), indicates how much \( y \) is expected to change with a one-unit increase in \( x \). Linear regression assumes a constant relationship between \( x \) and \( y \), meaning the slope remains the same across all values of \( x \). It's crucial for understanding how changes in \( x \) impact the predicted value of \( y \).
The model employs the least squares method to find the best-fitting line by minimizing the sum of squared differences between observed and predicted values. Linear regression helps in forecasting and finding relationships but requires assumptions like linearity, independence, and normal distribution of residuals.
Standard Error
The standard error is a measure of variability or dispersion in statistical terms. In the context of linear regression, it refers to the standard error of the predicted value of \( y \), denoted as \( SE(\hat{y}) \). This quantifies the uncertainty associated with predictions made using the regression line. The smaller the standard error, the closer the observed values are to the regression line, indicating a more precise prediction model.
The standard error of the predicted value \( SE(\hat{y}) \) is calculated using the equation: \[ SE(\hat{y}) = s \sqrt{\frac{1}{n} + \frac{(x - \bar{x})^2}{S_{xx}}} \] where \( s \) is the standard deviation of the residuals, \( n \) is the sample size, \( x \) is the independent variable's value, \( \bar{x} \) is the mean of \( x \), and \( S_{xx} \) is the sum of squares of \( x \).
A critical aspect here is \( \frac{(x - \bar{x})^2}{S_{xx}} \), which increases when \( x \) moves away from \( \bar{x} \). As this term grows, \( SE(\hat{y}) \) increases, making predictions less precise and widening the confidence interval.
Mean Value
A mean value, typically represented as \( \bar{x} \) or \( \mu \), is the average of a set of numbers and provides a central value of a dataset. It's a measure of central tendency and is calculated as the sum of all values divided by the number of values. In the context of linear regression, \( \bar{x} \) represents the average of the independent variable \( x \) values and plays a crucial role in the model's predictions.
The mean value serves as a reference point in regression analysis. When calculating the confidence interval for predictions, deviations from this mean value significantly affect the width of the interval. Greater deviations from the mean typically result in increased uncertainty in predictions, as indicated by the formula for standard error.
Understanding the mean value is vital because it impacts how we interpret the relationship between \( x \) and \( y \). It offers insight into how varying \( x \) might impact the predictability of \( y \), influencing how we approach data analysis and decision-making in real-world applications.

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Most popular questions from this chapter

In the least-squares line \(\hat{y}=5-2 x,\) what is the value of the slope? When \(x\) changes by 1 unit, by how much does \(\hat{y}\) change?

What is the symbol used for the slope of the population least-squares line?

What is the symbol used for the population correlation coefficient?

An Internet advertising agency is studying the number of "hits" on a certain web site during an advertising campaign. It is hoped that as the campaign progresses, the number of hits on the web site will also increase in a predictable way from one day to the next. For 10 days of the campaign, the number of hits \(\times 10^{5}\) is shown: $$\begin{array}{l|rrrrrrrrrr} \hline \text { Day } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\\\\hline \text { Hits } \times 10^{5} & 1.2 & 3.5 & 4.4 & 7.2 & 6.9 & 8.3 & 9.0 & 11.2 & 13.1 & 14.6 \\\\\hline\end{array}$$ (a) To construct a serial correlation, we use data pairs \((x, y)\) where \(x=\) original data and \(y=\) original data shifted ahead by one time period. Verify that the data set \((x, y)\) for serial correlation is shown here. (For discussion of serial correlation, see Problem 15.) $$\begin{array}{c|ccccccccc}\hline x & 1.2 & 3.5 & 4.4 & 7.2 & 6.9 & 8.3 & 9.0 & 11.2 & 13.1 \\\\\hline y & 3.5 & 4.4 & 7.2 & 6.9 & 8.3 & 9.0 & 11.2 & 13.1 & 14.6 \\\\\hline\end{array}$$ (b) For the \((x, y)\) data set of part (a), compute the equation of the sample least-squares line \(\hat{y}=a+b x .\) If the number of hits was \(9.3\left(\times 10^{5}\right)\) one day, what do you predict for the number of hits the next day? (c) Compute the sample correlation coefficient \(r\) and the coefficient of determination \(r^{2} .\) Test \(\rho>0\) at the \(1 \%\) level of significance. Would you say the time series of web site hits is relatively predictable from one day to the next? Explain.

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