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Homser Lake, Oregon, has an Atlantic salmon catch and release program that has been very successful. The average fisherman's catch has been \(\mu=8.8\) Atlantic salmon per day (Source: National Symposium on Catch and Release Fishing, Humboldt State University). Suppose that a new quota system restricting the number of fishermen has been put into effect this season. A random sample of fishermen gave the following catches per day: $$\begin{array}{ccccccc} 12 & 6 & 11 & 12 & 5 & 0 & 2 \\ 7 & 8 & 7 & 6 & 3 & 12 & 12 \end{array}$$ i. Use a calculator with mean and sample standard deviation keys to verify that \(\bar{x}=7.36\) and \(s \approx 4.03.\) ii. Assuming the catch per day has an approximately normal distribution, use a \(5 \%\) level of significance to test the claim that the population average catch per day is now different from \(8.8 .\)

Short Answer

Expert verified
The population average catch per day is now different from 8.8.

Step by step solution

01

Prepare the Data

First, list all given data points and verify the sample mean \(\bar{x}\) and sample standard deviation \(s\). The given sample data is: \[ 12, 6, 11, 12, 5, 0, 2, 7, 8, 7, 6, 3, 12, 12 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Sample Mean
The sample mean is a statistical measure that represents the average of a set of observations or data points. It is essential when you want to estimate the central tendency of a sample. To find the sample mean, you sum up all the data points in the sample and then divide by the number of data points.
For instance, if you have the catches per day from a sample of fishermen, you would add these up first. Using the given values \(12, 6, 11, 12, 5, 0, 2, 7, 8, 7, 6, 3, 12, 12\), the sum is \(103\). Since there are \(14\) data points in total, you divide \(103\) by \(14\) to get the sample mean \(\bar{x}\). Thus, the sample mean is approximately \(7.36\).
It's crucial because it provides a simple snapshot of the data set, but remember, it doesn't capture the variability or spread of the data.
Decoding Sample Standard Deviation
The sample standard deviation is a measure that tells us how much individual data points deviate from the sample mean. In simpler terms, it quantifies the amount of variation or dispersion in the sample.
To calculate the sample standard deviation, use the following steps:
  • Find the mean of your sample.
  • Subtract the mean from each data point and square the result.
  • Sum all these squared differences.
  • Divide this sum by one less than the number of observations (i.e., \(n-1\)).
  • Take the square root of the result.
For our example, the data yields a sample standard deviation (\(s\)) of approximately \(4.03\). It means the individual catches can differ by around \(4.03\) salmon from the mean catch \(7.36\). Remember, a higher standard deviation indicates more variability in the sample.
Importance of Normal Distribution
In statistics, the normal distribution is a probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence. This distribution is known for its bell-shaped curve where most values cluster around the mean.
In the context of hypothesis testing, assuming a normal distribution helps in predicting the probability of outcomes. If a sample is normally distributed, you can use it to make inferences about population parameters.
The assumption that the fisherman's daily catches are approximately normally distributed is crucial. It justifies using certain statistical tests that require this property, allowing for more valid and reliable conclusions.
Exploring Level of Significance
The level of significance in hypothesis testing is the threshold at which you decide whether to reject the null hypothesis. It is denoted by \( \alpha \) and commonly set at \(0.05\), which is a 5% level of risk you're willing to take when making the decision.
In the given exercise, testing at a 5% level of significance means you reject the null hypothesis if the probability of observing the test statistic under the null hypothesis is less than 5%.
This concept is vital because it helps decide whether an effect truly exists or if the observed data might have occurred by random chance. A lower level of significance indicates more stringent criteria for rejecting the null hypothesis, thus lowering the risk of incorrect conclusions.

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Most popular questions from this chapter

Consumers: Product Loyalty USA Today reported that about \(47 \%\) of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1006 Chevrolet owners and found that 490 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than \(47 \% ?\) Use \(\alpha=0.01.\)

Please provide the following information for Problems. (a) What is the level of significance? State the null and alternate hypotheses. (b) Check Requirements What sampling distribution will you use? What assumptions are you making? Compute the sample test statistic and corresponding \(z\) or \(t\) value as appropriate. (c) Find (or estimate) the \(P\) -value. Sketch the sampling distribution and show the area corresponding to the \(P\) -value. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level \(\alpha ?\) (e) Interpret your conclusion in the context of the application. Note: For degrees of freedom \(d . f .\) not in the Student's \(t\) table, use the closest \(d . f .\) that is smaller. In some situations, this choice of \(d . f .\) may increase the \(P\) -value a small amount and therefore produce a slightly more "conservative" answer. Medical: REM Sleep REM (rapid eye movement) sleep is sleep during which most dreams occur. Each night a person has both REM and non-REM sleep. However, it is thought that children have more REM sleep than adults (Reference: Secrets of Sleep by Dr. A. Borbely). Assume that REM sleep time is normally distributed for both children and adults. A random sample of \(n_{1}=10\) children (9 years old) showed that they had an average REM sleep time of \(\bar{x}_{1}=2.8\) hours per night. From previous studies, it is known that \(\sigma_{1}=0.5\) hour. Another random sample of \(n_{2}=10\) adults showed that they had an average REM sleep time of \(\bar{x}_{2}=2.1\) hours per night. Previous studies show that \(\sigma_{2}=0.7\) hour. Do these data indicate that, on average, children tend to have more REM sleep than adults? Use a \(1 \%\) level of significance.

When testing the difference of means for paired data, what is the null hypothesis?

Please provide the following information. (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. Compute the \(z\) value of the sample test statistic. (c) Find (or estimate) the \(P\) -value. Sketch the sampling distribution and show the area corresponding to the \(P\) -value. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level \(\alpha ?\) (e) Interpret your conclusion in the context of the application. Total blood volume (in ml) per body weight (in \(\mathrm{kg}\) ) is important in medical research. For healthy adults, the red blood cell volume mean is about \(\mu=28 \mathrm{ml} / \mathrm{kg}\) (Reference: Laboratory and Diagnostic Tests by F. Fischbach). Red blood cell volume that is too low or too high can indicate a medical problem (see reference). Suppose that Roger has had seven blood tests, and the red blood cell volumes were $$\begin{array}{rrrrrr} 32 & 25 & 41 & 35 & 30 & 37 & 29 \end{array}$$ The sample mean is \(\bar{x} \approx 32.7 \mathrm{ml} / \mathrm{kg} .\) Let \(x\) be a random variable that represents Roger's red blood cell volume. Assume that \(x\) has a normal distribution and \(\sigma=4.75 .\) Do the data indicate that Roger's red blood cell volume is different (either way) from \(\mu=28 \mathrm{ml} / \mathrm{kg} ?\) Use a 0.01 level of significance.

Suppose you want to test the claim that a population mean equals \(30 .\) (a) State the null hypothesis. (b) State the alternate hypothesis if you have no information regarding how the population mean might differ from \(30 .\) (c) State the alternate hypothesis if you believe (based on experience or past studies) that the population mean may be greater than \(30 .\) (d) State the alternate hypothesis if you believe (based on experience or past studies) that the population mean may not be as large as \(30 .\)

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