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Assume that \(x\) has a normal distribution with the specified mean and standard deviation. Find the indicated probabilities.$$P(3 \leq x \leq 6) ; \mu=4 ; \sigma=2$$

Short Answer

Expert verified
The probability that \(3 \leq x \leq 6\) is approximately \(0.5328\).

Step by step solution

01

Identify the Standard Normal Variable

To find the probability of a normal distribution, we need to convert the variable to a standard normal variable using the formula for the Z-score: \[ Z = \frac{x - \mu}{\sigma} \] where \( \mu = 4 \) and \( \sigma = 2 \).
02

Calculate the Z-scores for the Interval Edges

Calculate the Z-score for the lower bound \(x = 3\): \[ Z = \frac{3 - 4}{2} = -0.5 \]Calculate the Z-score for the upper bound \(x = 6\): \[ Z = \frac{6 - 4}{2} = 1 \]
03

Use Standard Normal Distribution Table

With the Z-scores \(-0.5\) and \(1\), use the standard normal distribution table or calculator to find the corresponding probabilities:- Probability for \(Z = -0.5\) is approximately \(0.3085\).- Probability for \(Z = 1\) is approximately \(0.8413\).
04

Calculate the Probability of the Interval

Subtract the probability for the lower Z-score from the probability for the upper Z-score to find the probability of the interval:\[ P(3 \leq x \leq 6) = P(Z \leq 1) - P(Z \leq -0.5) = 0.8413 - 0.3085 = 0.5328 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
The Z-score is a crucial concept in statistics that helps standardize normal distribution data. It measures how many standard deviations an element is from the mean, making it easy to compare different data points.
To calculate the Z-score for any value, use the formula: \[ Z = \frac{x - \mu}{\sigma} \] - Here, \(x\) is the data point you're evaluating. - \(\mu\) represents the mean of the dataset. - \(\sigma\) denotes the standard deviation.
By converting data into Z-scores, you transform the distribution to have a mean of 0 and a standard deviation of 1. This standardization allows you to easily assess how typical or atypical certain data points are within the dataset. The Z-score also makes it feasible to calculate probabilities using the standard normal distribution table.
Standard Normal Variable
A Standard Normal Variable is a type of random variable that has a normal distribution with a mean (\(\mu\)) of 0 and a standard deviation (\(\sigma\)) of 1. Such a transformation is achieved by converting raw data points into Z-scores, allowing for a consistent basis for interpretation.
The world of statistics often turns to the standard normal distribution, or Z-distribution, when comparing datasets because of its simplicity and intuitive properties.
When you have a set of data converted into standard normal variables, the dataset becomes easier to work with in probability and statistical analysis. You can apply the standard normal table to find areas under the curve, which correspond to probabilities and can give insights into the likelihood of certain outcomes.This universality is why converting to standard normal form is so prevalent in statistical analysis.
Probability Calculation
Calculating probability in the context of normal distribution involves determining the likelihood that a random variable falls within a specified range. After converting to Z-scores, you can use the standard normal distribution table to find these probabilities.
For example, if you are asked to find \(P(3 \leq x \leq 6) \) with \(\mu = 4\) and \(\sigma = 2\), you first convert values to their respective Z-scores. For \(x = 3\), \(Z = -0.5\), and for \(x = 6\), \(Z = 1\). These Z-scores help pinpoint the related probabilities from the standard normal table.
- Probability when \(Z = -0.5\) is approximately 0.3085. - Probability when \(Z = 1\) is approximately 0.8413.
Subtract the probability at the lower Z-score from the one at the higher Z-score to find the probability that \(x\) falls within that range. This method not only simplifies finding probabilities but also demonstrates the power of Z-scores in statistical calculations.

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