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Given a binomial experiment with \(n=200\) trials and probability of success on a single trial \(p=0.04,\) find the value of \(\lambda\) and then use the Poisson distribution to estimate the probability of \(r=8\) successes.

Short Answer

Expert verified
\(\lambda = 8; P(r=8) \approx 0.1396\)

Step by step solution

01

Identify the Parameters

In the given binomial experiment, the number of trials is \(n = 200\) and the probability of success on a single trial is \(p = 0.04\).
02

Calculate \(\lambda\) for Poisson Approximation

The mean \(\lambda\) for the Poisson distribution can be found by multiplying \(n\) and \(p\). Therefore, \(\lambda = n \cdot p = 200 \cdot 0.04 = 8\).
03

Use the Poisson Formula

The probability of observing exactly \(r\) successes in a Poisson distribution is given by the formula: \(P(r) = \frac{{e^{-\lambda} \cdot \lambda^r}}{{r!}}\). Here, \(r=8\) and \(\lambda=8\).
04

Calculate \(P(r=8)\)

Substitute the values of \(\lambda\) and \(r\) into the formula: \(P(8) = \frac{{e^{-8} \cdot 8^8}}{{8!}}\). Calculate \(8^8 = 16777216\) and \(8! = 40320\). Evaluate the expression: \(P(8) = \frac{{e^{-8} \cdot 16777216}}{{40320}}\).
05

Final Calculation

Calculate \(e^{-8} \approx 0.0003354626\). Substitute this into the expression: \(P(8) = \frac{{0.0003354626 \cdot 16777216}}{{40320}} \approx 0.1396\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Experiment
A binomial experiment involves a series of trials or experiments where each trial results in a binary outcome: success or failure. In the context of our problem, the classic example is flipping a coin, where you can either get heads or tails. However, in our exercise, we're considering a situation with more specifics. We have a total of 200 trials, which is denoted by the parameter \(n\). Each trial, such as any specific experiment, presents the same probability of success, which in our case is 0.04 or 4%.

In a binomial experiment, these consistent conditions allow us to make statistical predictions. The entire study of the binomial distribution revolves around understanding how success probabilities will compound over a number of trials. Often, by examining such scenarios, valuable insights can be gained regarding the likelihood of obtaining a certain number of successes across multiple attempts.
Probability of Success
Within a binomial experiment, the probability of success is the likelihood of a single trial turning out favourably. Here, it is represented by the symbol \(p\), which stands for probability. For our textbook problem, \(p\) equals 0.04, which translates to a 4% chance that any single tried result in success.

Probability of success is constant across all trials, so it doesn't matter whether you're considering the first, second, or last trial; each has the same chance. This consistency is vital for applying both binomial and Poisson distributions as it ensures uniformity over the analytical process.
  • A key point is that the probability of failure (not success) on a trial would thus be \(1 - p = 0.96\).
  • Knowing the probability of success is only the starting point, as it helps determine expected values such as the mean number of successes, which we need for the Poisson approximation.

By understanding and identifying the probability of success, we are primed to assess cumulative probabilities using various statistical approaches.
Poisson Approximation
Poisson Approximation is a powerful technique used in situations where calculating exact binomial probabilities becomes cumbersome. This happens particularly when you have a large number of trials, \(n\), and a small probability of success, \(p\). The Poisson distribution serves as a handy approximation under two conditions:
- Great number of trials \((n)\).
Probability Calculation
To determine the likelihood of a specific number of successes, we perform a probability calculation using the Poisson formula. Here, the Poisson probability mass function becomes essential.The formula used is:\[P(r) = \frac{e^{-\lambda} \cdot \lambda^r}{r!}\]In this equation:- \(e\) is the base of natural logarithms, approximately equal to 2.71828.
- \(\lambda\) is the mean number of successes, calculated as \(\lambda = n \cdot p\) and for our problem, this value was 8.
- \(r\) represents the number of successes we're interested in, which in this case, is 8.By substituting these values into our formula, we arrive at the probability:\[P(8) = \frac{e^{-8} \cdot 8^8}{8!}\]Following through with the calculation step-by-step:
  • Compute \(8^8 = 16777216\).
  • Calculate the factorial, \(8! = 40320\).
  • Substitute \(e^{-8} \approx 0.0003354626\) into the formula
  • Finally, assemble all components to arrive at \(P(8) \approx 0.1396\).

This computation shows there's approximately a 13.96% chance of observing exactly 8 successes, exemplifying how Poisson offers a practical tool for approximation in binomial settings.

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Most popular questions from this chapter

Pyramid Lake is located in Nevada on the Paiute Indian Reservation. This lake is famous for large cutthroat trout. The mean number of trout (large and small) caught from a boat is 0.667 fish per hour (Reference: Creel Chronicle, Vol. \(3,\) No. 2 ). Suppose you rent a boat and go fishing for 8 hours. Let \(r\) be a random variable that represents the number of fish you catch in the 8 -hour period. (a) Explain why a Poisson probability distribution is appropriate for \(r\). What is \(\lambda\) for the 8 -hour fishing trip? Round \(\lambda\) to the nearest tenth so that you can use Table 4 of Appendix II for Poisson probabilities. (b) If you have already caught three trout, what is the probability you will catch a total of seven or more trout? Compute \(P(r \geq 7 | r \geq 3) .\) See Hint below. (c) If you have already caught four trout, what is the probability you will catch a total of fewer than nine trout? Compute \(P(r<9 | r \geq 4) .\) See Hint below. (d) List at least three other areas besides fishing to which you think conditional Poisson probabilities can be applied. Hint for solution: Review item \(6,\) conditional probability, in the summary of basic probability rules at the end of Section \(4.2 .\) Note that $$P(A | B)=\frac{P(A \text { and } B)}{P(B)}$$ and show that in part (b), $$P(r \geq 7 | r \geq 3)=\frac{P[(r \geq 7) \text { and }(r \geq 3)]}{P(r \geq 3)}=\frac{P(r \geq 7)}{P(r \geq 3)}$$

Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about \(6.9 .\) Use the criterion that it is unusual to have data values more than 2.5 standard deviations above the mean or 2.5 standard deviations below the mean to answer the following questions. (a) Would it be unusual to have more than 120 successes out of 200 trials? Explain. (b) Would it be unusual to have fewer than 40 successes out of 200 trials? Explain. (c) Would it be unusual to have from 70 to 90 successes out of 200 trials? Explain.

Jim is a 60 -year-old Anglo male in reasonably good health. He wants to take out a 50,000 dollar term (i.e., straight death benefit) life insurance policy until he is \(65 .\) The policy will expire on his 65 th birthday. The probability of death in a given year is provided by the Vital Statistics Section of the Statistical Abstract of the United States (116th edition). $$\begin{array}{|l|ccccc|} \hline x=\text { age } & 60 & 61 & 62 & 63 & 64 \\\ \hline P( \text { death at this age) } & 0.01191 & 0.01292 & 0.01396 & 0.01503 & 0.01613 \\ \hline \end{array}$$ Jim is applying to Big Rock Insurance Company for his term insurance policy. (a) What is the probability that Jim will die in his 60 th year? Using this probability and the 50,000 dollar death benefit, what is the expected cost to Big Rock Insurance? (b) Repeat part (a) for years \(61,62,63,\) and \(64 .\) What would be the total expected cost to Big Rock Insurance over the years 60 through \(64 ?\) (c) If Big Rock Insurance wants to make a profit of 700 dollar above the expected total cost paid out for Jim's death, how much should it charge for the policy? (d) If Big Rock Insurance Company charges 5000 dollar for the policy, how much profit does the company expect to make?

A research team at Cornell University conducted a study showing that approximately \(10 \%\) of all businessmen who wear ties wear them so tightly that they actually reduce blood flow to the brain, diminishing cerebral functions (Source: Chances: Risk and Odds in Everyday Life, by James Burke). At a board meeting of 20 businessmen, all of whom wear ties, what is the probability that (a) at least one tie is too tight? (b) more than two ties are too tight? (c) no tie is too tight? (d) at least 18 ties are not too tight?

On the leeward side of the island of Oahu, in the small village of Nanakuli, about \(80 \%\) of the residents are of Hawaiian ancestry (Source: The Honolulu Advertiser). Let \(n=1,2,3, \ldots\) represent the number of people you must meet until you encounter the first person of Hawaiian ancestry in the village of Nanakuli. (a) Write out a formula for the probability distribution of the random variable \(n\) (b) Compute the probabilities that \(n=1, n=2,\) and \(n=3\) (c) Compute the probability that \(n \geq 4\) (d) In Waikiki, it is estimated that about \(4 \%\) of the residents are of Hawaiian ancestry. Repeat parts (a), (b), and (c) for Waikiki.

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