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Suppose you are a hospital manager and have been told that there is no need to worry that respirator monitoring equipment might fail because the probability any one monitor will fail is only \(0.01 .\) The hospital has 20 such monitors and they work independently. Should you be more concerned about the probability that exactly one of the 20 monitors fails, or that at least one fails? Explain.

Short Answer

Expert verified
Be more concerned about at least one monitor failing, with a probability of 0.1821.

Step by step solution

01

Define the Problem

We need to decide if we should be more concerned about the probability of exactly one monitor failing or at least one monitor failing out of 20 monitors, given each monitor's failure probability is 0.01. This involves calculating probabilities using the binomial distribution.
02

Identify Probability Parameters

The problem concerns a binomial distribution where: the probability of a single monitor failing, \(p = 0.01\), and the number of trials (monitors), \(n = 20\).
03

Calculate Probability of Exactly One Failure

Use the binomial probability formula: \(P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\). For exactly one failure, \(k = 1\): \[P(X = 1) = \binom{20}{1} (0.01)^1 (0.99)^{19}\]Calculate:\[\binom{20}{1} = 20\]\[P(X = 1) = 20 \times 0.01 \times (0.99)^{19}\]Calculate \((0.99)^{19}\) separately first.
04

Calculate (0.99)^19

Calculate \((0.99)^{19} \) using a calculator: \[(0.99)^{19} \approx 0.817\]Substitute back into the probability calculation.
05

Determine Probability of Exactly One Failure

Substitute the value obtained from Step 4 back into the formula:\[P(X = 1) = 20 \times 0.01 \times 0.817 \approx 0.1634\]
06

Calculate Probability of At Least One Failure

Use complementary probability: \[P(X \geq 1) = 1 - P(X = 0)\]Calculate \(P(X = 0)\) using the binomial probability formula:\[P(X = 0) = \binom{20}{0} (0.01)^0 (0.99)^{20}\]\[\binom{20}{0} = 1\]Thus, \[P(X = 0) = 0.99^{20}\].
07

Calculate (0.99)^20

Calculate \((0.99)^{20} \) using a calculator: \[(0.99)^{20} \approx 0.8179\]Use this in calculating \(P(X \geq 1)\).
08

Calculate Probability of At Least One Failure

Substitute the previous calculation into the formula:\[P(X \geq 1) = 1 - 0.8179 \approx 0.1821\]
09

Compare Probabilities

We have now:- Probability of exactly one failure: \(P(X = 1) \approx 0.1634\)- Probability of at least one failure: \(P(X \geq 1) \approx 0.1821\)Since \(0.1821\) is greater than \(0.1634\), the probability of at least one failure is higher.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
The concept of probability calculation is fundamental to understanding many real-world scenarios, like the reliability of medical equipment. Probability quantifies the likelihood of a particular event occurring. When dealing with a situation involving multiple events, such as the performance of hospital monitors, we use the binomial distribution. This mathematical framework helps assess the probability of a certain number of successes (or failures) in a set number of trials.

For our example, each monitor's failure is considered an independent event with a probability of failure, denoted as \(p = 0.01\). Here, we are interested in two particular probabilities: the probability that exactly one monitor fails and the probability that at least one monitor fails out of 20. To find these probabilities, we utilize the binomial probability formula, given by:

\[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]

where \(n\) is the total number of monitors, \(k\) is the number of failing monitors we are investigating, and \(p\) is the probability of failure for each individual monitor.
Complementary Probability
When calculating the probability of "at least one" event happening, it's often more convenient to use the concept of complementary probability. Complementary probability basically involves calculating the probability of the opposite scenario and then subtracting it from one.

In the context of the hospital monitors, to determine the probability that at least one monitor fails, we first calculate the probability of the complementary event. This is the scenario where no monitors fail. If "no monitors fail", then "at least one fails" is the complementary scenario.

The probability of no failures, denoted as \(P(X = 0)\), uses the binomial formula where \(k = 0\). This becomes:

\[P(X = 0) = \binom{20}{0} (0.01)^0 (0.99)^{20} = 0.99^{20}\]

Once this probability is found, simply subtract it from 1 to find the probability of at least one failure:

\[P(X \geq 1) = 1 - P(X = 0)\] Complementary probability is a powerful technique, especially with cases involving simpler calculations.
Independent Events
Understanding the concept of independent events is crucial in probability, particularly when examining situations like the performance of hospital monitors. In probability theory, events are independent when the outcome of one event doesn’t affect the outcome of another. This means each monitor operates independently of the others; if one fails, it doesn't influence whether another fails or not.

For the 20 hospital monitors, each has a 1% failure rate regardless of what happens with the other monitors. This independence simplifies calculations because the probabilities can be multiplied directly without additional conditions or dependencies.

When using the binomial distribution, independence is assumed. It's this assumption that allows us to apply the probability formula across multiple trials without needing to adjust for interactions between trials.

Knowing the monitors work independently helps to clarify that each failure is an isolated event, simplifying the complexity of real-world applications into manageable mathematical models. By adequately accounting for independence, we can provide more accurate, contextually appropriate probabilities.

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