/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 In the western United States, th... [FREE SOLUTION] | 91Ó°ÊÓ

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In the western United States, there are many dry-land wheat farms that depend on winter snow and spring rain to produce good crops. About \(65 \%\) of the years, there is enough moisture to produce a good wheat crop, depending on the region (Reference: Agricultural Statistics, U.S. Department of Agriculture). (a) Let \(r\) be a random variable that represents the number of good wheat crops in \(n=8\) years. Suppose the Zimmer farm has reason to believe that at least 4 out of 8 years will be good. However, they need at least 6 good years out of 8 to survive financially. Compute the probability that the Zimmers will get at least 6 good years out of \(8,\) given what they believe is true; that is, compute \(P(6 \leq r | 4 \leq r) .\) See part (d) for a hint.

Short Answer

Expert verified
The probability that the Zimmer farm will have at least 6 good years out of 8, given they have at least 4, is approximately 0.854.

Step by step solution

01

Define the Probability

The problem is about a binomial distribution where the probability of having a good crop in any given year is \(p = 0.65\). We are interested in the number of good crops, \(r\), in 8 years \(n = 8\).
02

Probability of At Least 4 Good Years

First, we calculate the probability of having at least 4 good years out of 8. This is expressed as \(P(r \geq 4)\) where \(r\) follows a binomial distribution with parameters \(n=8\) and \(p=0.65\). Using the cumulative distribution function, we compute this.
03

Calculate Complement Probabilities

Calculate \(P(r < 4)\) which is the same as \(P(r \leq 3)\) because it is the complement of what we need for \(P(r \geq 4)\). This is found by summing the probabilities \(P(r=0) + P(r=1) + P(r=2) + P(r=3)\).
04

Compute At Least 4 Good Years

Now, calculate \(P(r \geq 4) = 1 - P(r \leq 3)\) using the cumulative probability found in Step 3.
05

Probability of At Least 6 Good Years Given At Least 4 Years

We are interested in \(P(6 \leq r | 4 \leq r)\), which can be found using the formula for conditional probability: \(P(6 \leq r | 4 \leq r) = \frac{P(6 \leq r \leq 8)}{P(r \geq 4)}\). Compute \(P(6 \leq r \leq 8)\), which is the sum of the probabilities of having 6, 7, or 8 good years.
06

Final Probability Computation

Finally, calculate \(P(6 \leq r | 4 \leq r)\) using both probabilities derived earlier: \(P(6 \leq r | 4 \leq r) = \frac{P(r = 6) + P(r = 7) + P(r = 8)}{P(r \geq 4)}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation is a key concept in statistics, which helps us understand how likely an event is to occur. It is particularly important in scenarios involving uncertainty, like determining the success rate of crops in agriculture based on historical data. In this context, we analyze the likelihood of different outcomes, such as the number of successful crop years out of a given number of years. For example, in our exercise, we are given that there is a 65% chance of a good crop each year. With 8 years to consider, we use this probability to calculate different outcomes, like having at least 4 good years or the likelihood of having 6 or more good years given 4 good years have already occurred. Probability calculations involve both simple and complex operations, such as adding probabilities and dealing with the binomial distribution to find specific outcome probabilities. This method of calculating probabilities helps farmers and others make informed decisions based on a variety of potential scenarios.
Conditional Probability
Conditional probability is a helpful way to determine the probability of an event, given that another event has already occurred. It is like narrowing down the possible outcomes by using known information to make the probability more specific. In our exercise, we are tasked with finding out the probability that a farm will have at least 6 successful crop years, given that they already believe they will have at least 4. This is expressed mathematically as \( P(6 \leq r | 4 \leq r) \), where \( r \) represents the number of good crop years. The formula for conditional probability is: \[ P(A | B) = \frac{P(A \cap B)}{P(B)} \] In the problem, \( P(6 \leq r | 4 \leq r) \) requires us to find the ratio of two probabilities: the probability of having between 6 and 8 good years \( P(6 \leq r \leq 8) \) and the probability of having at least 4 good years \( P(r \geq 4) \). This allows us to focus only on the subset of scenarios where the pre-existing condition (at least 4 good years) holds.
Cumulative Distribution Function
The cumulative distribution function (CDF) is a fundamental tool in statistics that helps us find the probability that a random variable takes on a value less than or equal to a certain point. In the context of a binomial distribution, like the one in our exercise, it allows us to compute probabilities for ranges of values easily. For instance, to find \( P(r \geq 4) \), we actually calculate \( 1 - P(r \leq 3) \), where \( P(r \leq 3) \) is derived from the CDF. The CDF provides a cumulative probability up to that point, summing all probabilities of the outcomes leading up to that number. By finding the difference from 1, we effectively get the complementary probability, which is useful when we're interested in outcomes that exceed a certain threshold. The CDF is an efficient way to handle such problems since it eliminates the need to calculate each probability individually.
Random Variable
A random variable is a concept in probability and statistics used to quantify outcomes in situations involving chance. It assigns numerical values to the results of a random phenomenon. In our exercise, the random variable \( r \) represents the number of good crop years out of 8 possible years. Random variables can be discrete or continuous. Here, since \( r \) takes specific whole numbers, it is a discrete random variable. This is common in scenarios where outcomes are counted, like the number of successful crop years. Understanding the behavior of a random variable often involves analyzing its distribution, like the binomial distribution in this problem. The random variable follows this distribution because each crop year results in either success (good year) or failure (bad year), akin to a series of independent trials. Grasping the concept of a random variable helps in modelling real-world processes using statistical methods, aiding in decision-making under uncertainty.

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Most popular questions from this chapter

At State College all classes start on the hour, with the earliest start time at 7 A.M. and the latest at 8 p.M. A random sample of freshmen showed the percentages preferring the listed start times. $$\begin{array}{l|ccccc} \text { Start Time } & 7 \text { or } 8 \text { A.M. } & 9,10, \text { or } 11 \text { A.M. } & 12 \text { or } 1 \text { P.M. } & \text { 1 } \text { P.M. or later } & \text { After } 5 \text { P.M. } \\ \hline \% \text { preferring } & 10 \% & 35 \% & 28 \% & 25 \% & 15 \% \end{array}$$ Can this information be used to make a discrete probability distribution? Explain.

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Consider a binomial distribution with \(n=10\) trials and the probability of success on a single trial \(p=0.85\) (a) Is the distribution skewed left, skewed right, or symmetric? (b) Compute the expected number of successes in 10 trials. (c) Given the high probability of success \(p\) on a single trial, would you expect \(P(r \leq 3)\) to be very high or very low? Explain. (d) Given the high probability of success \(p\) on a single trial, would you expect \(P(r \geq 8)\) to be very high or very low? Explain.

In an experiment, there are \(n\) independent trials. For each trial, there are three outcomes, \(A, B\), and \(C\). For each trial, the probability of outcome \(A\) is 0.40 ; the probability of outcome \(B\) is \(0.50 ;\) and the probability of outcome \(\mathrm{C}\) is \(0.10 .\) Suppose there are 10 trials. (a) Can we use the binomial experiment model to determine the probability of four outcomes of type \(\mathrm{A},\) five of type \(\mathrm{B},\) and one of type C? Explain. (b) Can we use the binomial experiment model to determine the probability of four outcomes of type \(A\) and six outcomes that are not of type A? Explain. What is the probability of success on each trial?

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