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Basic Computation: Rules of Probability Given \(P\left(A^{c}\right)=0.8, P(B)=0.3\) \(P(B | A)=0.2:\) (a) Compute \(P(A \text { and } B).\) (b) Compute \(P(A \text { or } B).\)

Short Answer

Expert verified
(a) \( P(A \text{ and } B) = 0.04 \), (b) \( P(A \text{ or } B) = 0.46 \).

Step by step solution

01

Find P(A)

To find the probability of event A, we need to find the complement of the probability given. We know that the probability of the complement of A, denoted as \( P(A^c) \), is 0.8. Since \( P(A) + P(A^c) = 1 \), we can calculate \( P(A) \) as follows:\[ P(A) = 1 - P(A^c) = 1 - 0.8 = 0.2 \].
02

Compute P(A and B)

We use the rule for conditional probability, where \( P(B | A) = \frac{P(A ext{ and } B)}{P(A)} \). We have \( P(B | A) = 0.2 \) and we just calculated \( P(A) = 0.2 \). Thus,\[ P(A ext{ and } B) = P(B | A) \times P(A) = 0.2 \times 0.2 = 0.04 \].
03

Compute P(A or B)

To find the probability of either event A or event B occurring, use the formula: \( P(A ext{ or } B) = P(A) + P(B) - P(A ext{ and } B) \). Now substitute the known values:\[ P(A ext{ or } B) = 0.2 + 0.3 - 0.04 = 0.46 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conditional Probability
Conditional probability helps us understand how the probability of one event can change based on the occurrence of another event. Here, it shows the likelihood of event B occurring given that A has already happened. This is expressed as \( P(B | A) \). In general, the formula for conditional probability is:
  • \( P(B | A) = \frac{P(A \text{ and } B)}{P(A)} \)
The conditional probability \( P(B | A) \) is 0.2 in our exercise, meaning that once event A occurs, event B has a 20% chance of occurring as well. We used this concept to determine \( P(A \text{ and } B) \), the probability of both A and B happening together by rearranging the conditional probability formula:
  • \( P(A \text{ and } B) = P(B | A) \times P(A) = 0.2 \times 0.2 = 0.04 \)
Understanding conditional probability is key to finding how related events impact one another in terms of their probabilities.
Complementary Events
In probability theory, each event has a complementary event, which is everything that is not part of the original event. If you know the probability of an event's complement, you can easily find the probability of the event itself.
  • The relationship is simple: \( P(A) + P(A^c) = 1 \).
Given \( P(A^c) = 0.8 \) in the exercise, we calculated the probability of event A by subtracting the probability of its complement from 1:
  • \( P(A) = 1 - P(A^c) = 1 - 0.8 = 0.2 \)
Complementary events cover all possible outcomes of a situation. They are useful because they often make it easier to calculate rather than dealing with the main event directly, especially if you have the information on the complement probability readily available.
Addition Rule in Probability
The addition rule is a fundamental principle used to compute the probability of either one of two events occurring. It helps us find \( P(A \text{ or } B) \), which is the probability that either event A occurs, or event B occurs, or both occur together.
  • The formula is: \( P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \).
In the exercise, we had:
  • \( P(A) = 0.2 \)
  • \( P(B) = 0.3 \)
  • \( P(A \text{ and } B) = 0.04 \)
Using these values, the calculation was:
  • \( P(A \text{ or } B) = 0.2 + 0.3 - 0.04 = 0.46 \)
This rule is pivotal in understanding how probabilities of multiple events intertwine, ensuring you're not overcounting the probability where both events occur.

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Most popular questions from this chapter

Probability Estimate: Wiggle Your Ears Can you wiggle your ears? Use the students in your statistics class (or a group of friends) to estimate the percentage of people who can wiggle their ears. How can your result be thought of as an estimate for the probability that a person chosen at random can wiggle his or her ears? Comment: National statistics indicate that about \(13 \%\) of Americans can wiggle their ears (Source: Bernice Kanner, Are You Normal?, St. Martin's Press, New York).

Critical Thinking Suppose two events \(A\) and \(B\) are mutually exclusive, with \(P(A) \neq 0\) and \(P(B) \neq 0 .\) By working through the following steps, you'll see why two mutually exclusive events are not independent. (a) For mutually exclusive events, can event \(A\) occur if event \(B\) has occurred? What is the value of \(P(A | B) ?\) (b) Using the information from part (a), can you conclude that events \(A\) and \(B\) are not independent if they are mutually exclusive? Explain.

Critical Thinking Consider the following events for a driver selected at random from the general population: \(A=\) driver is under 25 years old \(B=\) driver has received a speeding ticket Translate each of the following phrases into symbols. (a) The probability the driver has received a speeding ticket and is under 25 years old (b) The probability a driver who is under 25 years old has received a speeding ticket (c) The probability a driver who has received a speeding ticket is 25 years old or older (d) The probability the driver is under 25 years old or has received a speeding ticket (e) The probability the driver has not received a speeding ticket or is under 25 years old

You roll two fair dice, a green one and a red one. (a) What is the probability of getting a sum of \(7 ?\) (b) What is the probability of getting a sum of \(11 ?\) (c) What is the probability of getting a sum of 7 or \(11 ?\) Are these outcomes mutually exclusive?

Consider the following events for a college student selected at random: \(A=\) student is female \(B=\) student is majoring in business Translate each of the following phrases into symbols. (a) The probability the student is male or is majoring in business (b) The probability a female student is majoring in business (c) The probability a business major is female (d) The probability the student is female and is not majoring in business (e) The probability the student is female and is majoring in business

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