/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 47 Brain Teasers Assume \(A\) and \... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Brain Teasers Assume \(A\) and \(B\) are events such that \(0

Short Answer

Expert verified
False, independence and mutual exclusivity are distinct and cannot both occur unless one event has zero probability.

Step by step solution

01

Understanding Independence

Two events, \(A\) and \(B\), are independent if the occurrence of one event does not affect the probability of the other event. Mathematically, this is stated as \(P(A \cap B) = P(A)P(B)\). If \(A\) and \(B\) are independent, knowing about \(A\) does not provide any information about \(B\), and vice versa.
02

Understanding Mutually Exclusive

Two events are mutually exclusive (or disjoint) if they cannot occur at the same time. In probability terms, this means that \(P(A \cap B) = 0\). In simple terms, the occurrence of \(A\) means \(B\) cannot occur, and vice versa.
03

Analyzing Independence and Mutual Exclusivity

Let's consider the conditions: If \(A\) and \(B\) are independent, then \(P(A \cap B) = P(A)P(B)\). If they are also mutually exclusive, then \(P(A \cap B) = 0\). For both to be true, given \(P(A) > 0\) and \(P(B) > 0\), it would require \(P(A)P(B) = 0\), which is impossible unless either \(P(A) = 0\) or \(P(B) = 0\), contradicting the given conditions. Hence, independence and mutual exclusivity cannot both be true in this scenario.
04

Conclusion

The statement "If \(A\) and \(B\) are independent events, they must also be mutually exclusive" is false. Independence and mutual exclusivity are distinct concepts that generally cannot coincide except in trivial cases where one of the events has zero probability.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability theory, independent events are a crucial concept. It means that the occurrence of one event does not affect the probability of another. For example, say you flip a die and coin simultaneously. The die showing a "3" doesn't influence the coin landing on "heads."
Mathematically, for events \(A\) and \(B\), independence is expressed as:
  • \(P(A \cap B) = P(A) P(B)\)
This means the probability of both events \(A\) and \(B\) happening together is simply the product of their individual probabilities.
When events are independent, knowing the outcome of one does not give any information about the other. Independent events simplify probability assessments in many scenarios, as they allow you to calculate joint probabilities more easily.
Mutually Exclusive Events
Mutually exclusive events, also known as disjoint events, cannot happen at the same time. Imagine a single die roll; if one event is rolling a "2," the event of rolling a "3" is mutually exclusive. Only one outcome is possible in a single trial.
In probability terms, mutual exclusivity is represented as:
  • \(P(A \cap B) = 0\)
This indicates that there's no overlap between the events \(A\) and \(B\) occurring simultaneously.
Another example could be drawing a card from a deck: if one event is drawing a heart, an exclusive event could be drawing a club. Mutually exclusive events are fundamental when evaluating scenarios where only one outcome can result, assisting in planning and risk assessments.
Probability Rules
Understanding probability requires following specific rules. These rules help in calculating the likelihood of events.One of the key rules is the rule of total probability, which requires summing the probabilities of mutually exclusive events to find a total probability.For independent events, the multiplication rule is used:
  • To find the probability of both events, multiply their probabilities: \(P(A \cap B) = P(A)P(B)\)
For mutually exclusive events, their combined probability is simply the sum:
  • \(P(A \text{ or } B) = P(A) + P(B)\)
The misconception that independent events could also be mutually exclusive often arises, but the probability rules show they are distinct.
These rules form the backbone of solving probability problems efficiently. Mastering them allows for a clear understanding of different probability scenarios and helps in making logical and mathematical predictions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose two events \(A\) and \(B\) are independent, with \(P(A) \neq 0\) and \(P(B) \neq 0 .\) By working through the following steps, you'll see why two independent events are not mutually exclusive. (a) What formula is used to compute \(P(A \text { and } B) ?\) Is \(P(A \text { and } B) \neq 0 ?\) Explain. (b) Using the information from part (a), can you conclude that events \(A\) and \(B\) are not mutually exclusive?

A botanist has developed a new hybrid cotton plant that can withstand insects better than other cotton plants. However, there is some concern about the germination of seeds from the new plant. To estimate the probability that a seed from the new plant will germinate, a random sample of 3000 seeds was planted in warm, moist soil. Of these seeds, 2430 germinated. (a) Use relative frequencies to estimate the probability that a seed will germinate. What is your estimate? (b) Use relative frequencies to estimate the probability that a seed will not germinate. What is your estimate? (c) Either a seed germinates or it does not. What is the sample space in this problem? Do the probabilities assigned to the sample space add up to \(1 ?\) Should they add up to \(1 ?\) Explain. (d) Are the outcomes in the sample space of part (c) equally likely?

What is the law of large numbers? If you were using the relative frequency of an event to estimate the probability of the event, would it be better to use 100 trials or 500 trials? Explain.

Environmental: Land Formations Arches National Park is located in southern Utah. The park is famous for its beautiful desert landscape and its many natural sandstone arches. Park Ranger Edward McCarrick started an inventory (not yet complete) of natural arches within the park that have an opening of at least 3 feet. The following table is based on information taken from the book Canyon Country Arches and Bridges by F. A. Barnes. The height of the arch opening is rounded to the nearest foot. $$\begin{array}{l|ccccc} \hline \text { Height of arch, feet } & 3-9 & 10-29 & 30-49 & 50-74 & 75 \text { and higher } \\ \hline \begin{array}{l} \text { Number of arches } \\ \text { in park } \end{array} & 111 & 96 & 30 & 33 & 18 \\ \hline \end{array}$$ For an arch chosen at random in Arches National Park, use the preceding information to estimate the probability that the height of the arch opening is (a) 3 to 9 feet tall (b) 30 feet or taller (c) 3 to 49 feet tall (d) 10 to 74 feet tall (e) 75 feet or taller

Brain Teasers Assume \(A\) and \(B\) are events such that \(0

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.