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Brain Teasers Assume \(A\) and \(B\) are events such that \(0

Short Answer

Expert verified
False, \( P(A \text{ or } A^c) = 1 \), not 0.

Step by step solution

01

Identify the Events

The problem involves two events, denoted as \( A \) and \( A^c \). Here, \( A^c \) is the complement of \( A \). This means \( A^c \) includes all the outcomes that are not in event \( A \).
02

Apply the Complement Rule

The complement of an event \( A \), denoted \( A^c \), consists of all outcomes not in \( A \). According to probability rules, the probability of \( A \) or \( A^c \) is 1. This is represented as \( P(A) + P(A^c) = 1 \), because the events \( A \) and \( A^c \) together account for all possible outcomes.
03

Evaluate the Expression

Given the expression \( P(A \text{ or } A^c) \), this evaluates to the whole sample space. Since \( P(A) + P(A^c) = 1 \), it demonstrates certainty that either \( A \) or its complement will occur, as they encompass all possibilities.
04

Conclusion about the Statement

Therefore, the statement \( P(A \text{ or } A^c) = 0 \) is false. The correct value for \( P(A \text{ or } A^c) \) should be 1, not 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complement Rule
When we talk about probability, the complement rule is an invaluable concept. It addresses the scenario where we want to know the probability that an event does not happen. Suppose we have an event \( A \). The complement of event \( A \), which we denote as \( A^c \), covers all possibilities where \( A \) does not occur.
This means \( A^c \) includes every outcome not in \( A \). A crucial probability rule tells us that the probability of an event and its complement always adds up to 1. This is represented by the equation \( P(A) + P(A^c) = 1 \).
Why is this the case? Between an event happening or not, all possibilities in a situation are covered. Therefore, when we calculate the probability of an event's occurrence together with its non-occurrence (complement), it should encompass the entire probability spectrum of 1. This rule is part of what allows us to solve probability problems efficiently and correctly.
Sample Space
The sample space is a fundamental concept in probability, representing all possible outcomes of a random experiment. Imagine flipping a coin. The sample space includes outcomes like heads and tails. Whenever you assess probability-question scenarios, understanding the sample space is crucial, as it lays the groundwork for determining probabilities.
In probability, the sample space is typically denoted by \( S \). All events, including single events and combinations of events, occur as subsets of this sample space. Knowing the sample space allows us to calculate the likelihood of various events by determining how many of those outcomes satisfy the event's condition.
The clarity offered by defining a sample space simplifies the probability analysis. It ensures that when we apply probability rules, we are considering the full range of possible scenarios, ensuring comprehensive calculations.
Basic Probability Rules
Basic probability rules form the backbone of understanding any probability problem. They consist of fundamental principles that guide how we approach calculating the likelihood of different events. Here are key rules to remember:
  • The probability of any event \( A \) is between 0 and 1: \( 0 \leq P(A) \leq 1 \).
  • The sum of probabilities of all potential outcomes in a sample space is always 1, ensuring that every possible outcome is accounted for.
  • The probability of an event's complement can be calculated with \( P(A^c) = 1 - P(A) \).
  • When considering the union of two events \( A \) and \( B \), if they are mutually exclusive, then \( P(A \cup B) = P(A) + P(B) \). If not, adjustments need to be made to account for overlap.
These rules are essential for both beginners and experts in probability, acting as the basic tools with which we can analyze a broad spectrum of problems. Understanding these rules helps in determining answers that accurately reflect the underlying mathematics of probability scenarios.

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Most popular questions from this chapter

In this problem, you are asked to solve part of the Focus Problem at the beginning of this chapter. In his book Chances: Risk and Odds in Everyday Life, James Burke says that there is a \(72 \%\) chance a polygraph test (lie detector test) will catch a person who is, in fact, lying. Furthermore, there is approximately a \(7 \%\) chance that the polygraph will falsely accuse someone of lying. (a) Suppose a person answers \(90 \%\) of a long battery of questions truthfully. What percentage of the answers will the polygraph wrongly indicate are lies? (b) Suppose a person answers \(10 \%\) of a long battery of questions with lies. What percentage of the answers will the polygraph correctly indicate are lies? (c) Repeat parts (a) and (b) if \(50 \%\) of the questions are answered truthfully and \(50 \%\) are answered with lies. (d) Repeat parts (a) and (b) if \(15 \%\) of the questions are answered truthfully and the rest are answered with lies.

Counting Four wires (red, green, blue, and yellow) need to be attached to a circuit board. A robotic device will attach the wires. The wires can be attached in any order, and the production manager wishes to determine which order would be fastest for the robot to use. Use the multiplication rule of counting to determine the number of possible sequences of assembly that must be tested. Hint: There are four choices for the first wire, three for the second, two for the third, and only one for the fourth.

A sample space consists of 4 simple events: \(A, B, C, D\) Which events comprise the complement of \(A ?\) Can the sample space be viewed as having two events, \(A\) and \(A^{\text {c }}\) ? Explain.

Suppose the newspaper states that the probability of rain today is \(30 \% .\) What is the complement of the event "rain today"? What is the probability of the complement?

(a) Draw a tree diagram to display all the possible outcomes that can occur when you flip a coin and then toss a die. (b) How many outcomes contain a head and a number greater than \(4 ?\) (c) Probability Extension Assuming the outcomes displayed in the tree diagram are all equally likely, what is the probability that you will get a head and a number greater than 4 when you flip a coin and toss a die?

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