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You roll two fair dice, a green one and a red one. (a) What is the probability of getting a sum of \(7 ?\) (b) What is the probability of getting a sum of \(11 ?\) (c) What is the probability of getting a sum of 7 or \(11 ?\) Are these outcomes mutually exclusive?

Short Answer

Expert verified
(a) \(\frac{1}{6}\), (b) \(\frac{1}{18}\), (c) \(\frac{2}{9}\), Yes, they are mutually exclusive.

Step by step solution

01

Calculate Total Number of Outcomes

Each die has 6 faces, and since you roll two dice, the total number of outcomes is calculated by multiplying the outcomes of one die with the other. So, the total number of outcomes is \(6 \times 6 = 36\).
02

Calculate Outcomes for Sum of 7

We list the pairs of dice that add up to 7: \((1,6), (2,5), (3,4), (4,3), (5,2), (6,1)\). There are 6 outcomes that satisfy this condition.
03

Probability of Sum of 7

The probability of getting a sum of 7 is the number of favorable outcomes (sum of 7) divided by the total number of outcomes:\[P( ext{sum = 7}) = \frac{6}{36} = \frac{1}{6}\]
04

Calculate Outcomes for Sum of 11

We list the pairs of dice that add up to 11: \((5,6), (6,5)\). There are 2 outcomes that satisfy this condition.
05

Probability of Sum of 11

The probability of getting a sum of 11 is the number of favorable outcomes (sum of 11) divided by the total number of outcomes:\[P( ext{sum = 11}) = \frac{2}{36} = \frac{1}{18}\]
06

Calculate Probability of Sum 7 or 11

Since sums of 7 and 11 are mutually exclusive (they can't happen at the same time), we can add the probabilities together: \[P( ext{sum = 7 or sum = 11}) = P( ext{sum = 7}) + P( ext{sum = 11}) = \frac{1}{6} + \frac{1}{18} = \frac{3}{18} + \frac{1}{18} = \frac{4}{18} = \frac{2}{9}\]
07

Conclusion on Mutually Exclusive Events

Two events are mutually exclusive if the occurrence of one event means the other cannot occur at the same time. Since a roll cannot simultaneously sum to both 7 and 11, these outcomes are mutually exclusive.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutually Exclusive Events
Mutually exclusive events are a fundamental concept in probability, which helps in understanding whether two events can happen at the same time or not. An event is a specific outcome that you are interested in when observing a situation, like rolling a dice. Two events are called mutually exclusive when the occurrence of one event rules out the occurrence of the other.

For example, when rolling two dice, a sum of 7 and a sum of 11 cannot be achieved at the same time. This is simply because each roll will result in only one pair of numbers; hence, one sum. Therefore, the events "sum of 7" and "sum of 11" in dice rolling are mutually exclusive events. This means you roll the dice and it sums to either 7 or 11, but not both at once.

It’s like having two doors: you can choose one door to open at a time. If two events are mutually exclusive, you simply add their probabilities to find the probability of either event occurring.
  • If Event A and Event B are mutually exclusive, then the probability of either A or B occurring is: \( P(A \text{ or } B) = P(A) + P(B) \).
Probability of Dice Rolls
Understanding the probability of dice rolls involves knowing how likely certain outcomes are when rolling a fair die. A fair die has an equal chance for each face, meaning each number from 1 to 6 is equally likely to land face up.

When rolling two dice, you are dealing with more outcomes, as each die has 6 sides. The total possible results come from every combination of the numbers on the first die with the numbers on the second die, resulting in a total of 36 outcomes. This is because you have 6 options from the green die and 6 from the red die, leading to: \( 6 \times 6 = 36 \).

For specific sums, such as 7 or 11, you look at all the different pairs of numbers on the dice that add up to the target sum. For instance, the pairs \((3,4)\) and \((5,2)\) both add up to a sum of 7. These pairs are considered favorable outcomes. The probability of a sum occurring is given by dividing the number of favorable outcomes by the total number of possible outcomes (36 in this case).
  • Probability of a specific sum: \( P(\text{sum}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \).
Total Number of Outcomes
The total number of outcomes is an essential factor in probability as it refers to all possible results of an experiment. To calculate the probability of an event, knowing the total number of outcomes is crucial.

When discussing dice rolls, the calculation involves multiplying the number of sides each die has. Since each die has 6 sides, rolling two dice involves multiplying the outcomes from one die with the other. Hence, you have \( 6 \times 6 = 36 \) possible outcomes.

This approach is based on the fundamental principle of counting, which helps in determining the sample space: the complete set of possible outcomes. Once you know the sample space, you can then find out the probability for any given acceptable outcome by comparing the number of ways this outcome can occur to the total number of outcomes.
  • For two dice, each having 6 faces, total outcomes are calculated as: \(6 \times 6\).

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