/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 With an ever-increasing world po... [FREE SOLUTION] | 91Ó°ÊÓ

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With an ever-increasing world population, grain yields are extremely important. A random sample of 16 large grain producing regions in the world gave the following information about grain production (in kg/hectare) (Reference: Handbook of International Economic Statistics, U.S. Government Documents). $$\begin{array}{|l|cccccccc} \hline \text { Region } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 \\ \hline \text { Modern Production } & 1610 & 2230 & 5270 & 6990 & 2010 & 4560 & 780 & 6510 \\ \hline \text { Historic Production } & 1590 & 2360 & 5161 & 7170 & 1920 & 4760 & 660 & 6320 \\ \hline \\ \hline \text { Region } & 9 & 10 & 11 & 12 & 13 & 14 & 15 & 16 \\ \hline \text { Modern Production } & 2850 & 3550 & 1710 & 2050 & 2750 & 2550 & 6750 & 3670 \\ \hline \text { Historic Production } & 2920 & 2440 & 1340 & 2180 & 3110 & 2070 & 7330 & 2980 \\ \hline \end{array}$$ Does this information indicate that modern grain production is higher? Use a \(5 \%\) level of significance.

Short Answer

Expert verified
Modern grain production is higher than historic production at a 5% significance level.

Step by step solution

01

Define the Hypotheses

We want to know if the modern grain production is higher than the historic production. To test this, set up the hypotheses: \( H_0: \mu_\text{modern} = \mu_\text{historic} \) (there is no difference) and \( H_a: \mu_\text{modern} > \mu_\text{historic} \) (modern production is higher).
02

Calculate the Differences

For each region, calculate the difference between modern production and historic production. This creates a list of differences: 20, -130, 109, -180, 90, -200, 120, 190, -70, 1110, 370, -130, -360, 480, -580, 690.
03

Calculate the Sample Mean and Standard Deviation

Calculate the mean of these differences. Mean of differences \( = \frac{20 - 130 + 109 - 180 + 90 - 200 + 120 + 190 -70 + 1110 + 370 - 130 - 360 + 480 - 580 + 690}{16} = 125.625 \). Next, find the standard deviation of the differences.
04

Perform a t-Test for the Mean

Since the population standard deviation is unknown and the sample size is small, use the t-distribution. The test statistic \( t \) is calculated by \( t = \frac{\text{Mean Difference}}{\frac{s}{\sqrt{n}}} \), where \( s \) is the sample standard deviation and \( n \) is the sample size, 16. Calculate \( t \).
05

Determine the Critical t-Value

Use a 5% level of significance for a one-tailed test with 15 degrees of freedom (\( n-1 = 16-1 \)) to find the critical t-value from the t-distribution table. This will tell us the threshold \( t \) must exceed to reject the null hypothesis.
06

Make a Decision

Compare the calculated t-value with the critical t-value. If the calculated t-value is greater than the critical value, reject \( H_0 \), meaning modern production is significantly higher.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
A t-test is a statistical test used to determine if there is a significant difference between the means of two groups. It's especially useful when dealing with small sample sizes and unknown population standard deviations. In our case, we're interested in comparing modern grain production to historic production to see if modern production is higher. Since we don't know the exact standard deviation of the entire population and we have a relatively small sample, we use the t-test. We calculate a t-statistic, which tells us how far our sample mean is from the null hypothesis mean, measured in standard error units. If this t-statistic is sufficiently large, it suggests that the observed data is not just due to random chance, indicating a significant difference in means. Remember, the t-test requires certain assumptions: data should be approximately normally distributed and groups should have similar variances. When these conditions are met, the t-test is a reliable tool for hypothesis testing.
mean difference
The mean difference is simply the average of the differences between paired observations in two sets of data. In this scenario, for each region, we subtract the historic production from the modern production to find the difference. Then, we average these differences to get our mean difference. This mean represents a central value indicating how much modern production exceeds (or lags behind) historic production on average. The formula to find the mean difference is:
  • Identify the differences between each pair of observations.
  • Add these differences together.
  • Divide by the number of paired observations.
In our example, the calculated mean difference of 125.625 indicates that, on average, modern grain production is higher by roughly 125.625 kg per hectare compared to historic production. This average difference is crucial in assessing whether the observed variation is statistically significant.
level of significance
The level of significance, denoted as alpha (\( \alpha \)), is a threshold set by the researcher to accept or reject the null hypothesis. It represents the probability of rejecting the null hypothesis when it is true (a Type I error). In simpler terms, it's the risk you're willing to take in concluding that a difference exists when it actually does not. In this example, we're using a 5% level of significance (\( \alpha = 0.05 \)), a common choice in hypothesis testing. This means we're willing to take a 5% chance of incorrectly stating that modern production is higher than historic production. A lower alpha level indicates more stringent criteria for rejecting the null hypothesis, reducing the probability of a Type I error. When setting the level of significance, balance is key between too lenient (higher false positives) and too strict (overlook real differences) test thresholds.
critical t-value
The critical t-value is a cutoff point derived from the t-distribution table, which helps decide whether to reject the null hypothesis. It depends on the level of significance and degrees of freedom. In a one-tailed test with a 5% significance level, we focus on whether the calculated t-value exceeds this critical value. Here, with 15 degrees of freedom (one less than the sample size), we find the critical t-value that separates the most extreme 5% in the tail of our t-distribution. If our calculated t-value is greater than this critical t-value, we can conclude that the mean difference is statistically significant; otherwise, it is not. For our problem, obtaining this critical value involves these steps:
  • Determine the desired significance level, here 5%.
  • Identify degrees of freedom (sample size minus one, so 16 - 1 = 15).
  • Use a t-distribution table or calculator to find the critical t-value.
The critical t-value is a vital component in hypothesis testing as it provides the benchmark against which we compare our calculated t-value to draw meaningful conclusions.

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Most popular questions from this chapter

Please provide the following information. (a) What is the level of significance? State the null and alternate hypotheses. (b) Compute the sample test statistic. (c) Find or estimate the \(P\) -value of the sample test statistic. (d) Conclude the test. (e) Interpret the conclusion in the context of the application. FBI Report: Child Abuse and Runaway Children Is there a relation between incidents of child abuse and number of runaway children? A random sample of 15 cities (over 10,000 population) gave the following information about the number of reported incidents of child abuse and the number of runaway children (Reference: Federal Bureau of Investigation, U.S. Department of Justice). $$\begin{array}{|l|ccccccccccccccc} \hline \text { City } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 \\ \hline \text { Abuse cases } & 49 & 74 & 87 & 10 & 26 & 119 & 35 & 13 & 89 & 45 & 53 & 22 & 65 & 38 & 29 \\ \hline \text { Runaways } & 382 & 510 & 581 & 163 & 210 & 791 & 275 & 153 & 491 & 351 & 402 & 209 & 410 & 312 & 210 \\ \hline \end{array}$$ (i) Rank-order abuse using 1 as the largest data value. Also rank-order runaways using 1 as the largest data value. Then construct a table of ranks to be used for a Spearman rank correlation test. (ii) Use a \(1 \%\) level of significance to test the claim that there is a monotoneincreasing relationship between the ranks of incidents of abuse and number of runaway children.

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