/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Let \(x\) be a random variable t... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(x\) be a random variable that represents the \(\mathrm{pH}\) of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the \(x\) distribution is \(\mu=7.4\) (Reference: Merck Manual, a commonly used reference in medical schools and nursing programs). A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 31 patients with arthritis took the drug for 3 months. Blood tests showed that \(\bar{x}=8.1\) with sample standard deviation \(s=1.9 .\) Use a \(5 \%\) level of significance to test the claim that the drug has changed (either way) the mean \(\mathrm{pH}\) level of the blood.

Short Answer

Expert verified
Reject the null hypothesis; the drug changes the mean blood pH.

Step by step solution

01

Define the Hypotheses

We need to test if the drug changes the mean pH. The hypotheses are: the null hypothesis (H0) that suggests no change, and the alternative hypothesis (H1) that suggests a change. Thus, we set up the hypotheses as: \[ H_0: \mu = 7.4 \quad \text{(the mean pH is 7.4)} \] \[ H_1: \mu eq 7.4 \quad \text{(the mean pH is changed)} \]
02

Choose the Significance Level

The problem states to use a 5% significance level, which means \( \alpha = 0.05 \). This level of significance determines the threshold for rejecting the null hypothesis.
03

Calculate the Test Statistic

We will use a t-test for a sample mean because the sample size is small (less than 30). The formula for the t statistic is: \[ t = \frac{\bar{x} - \mu}{s / \sqrt{n}} \] Substituting the given values, \( \bar{x} = 8.1 \), \( \mu = 7.4 \), \( s = 1.9 \), \( n = 31 \):\[ t = \frac{8.1 - 7.4}{1.9 / \sqrt{31}} = \frac{0.7}{1.9 / \sqrt{31}} \approx 2.05 \]
04

Determine the Critical Value and Decision Rule

Since we are performing a two-tailed test (because \( \mu eq 7.4 \)), we will find the critical t-value for \( \alpha/2 = 0.025 \) in each tail with \( df = n - 1 = 30 \) degrees of freedom. Using a t-table, the critical t-values are approximately \( \pm 2.042 \). If the calculated t-value is beyond this range, we reject the null hypothesis.
05

Make a Decision

The calculated t-value (\( t \approx 2.05 \)) is greater than the critical value (\( 2.042 \)). Therefore, it falls in the rejection region of the null hypothesis. Thus, we reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Level of Significance
In hypothesis testing, the **Level of Significance** plays a crucial role in determining whether the null hypothesis will be rejected. It is often set at a standard threshold, such as 5%, to minimize the chances of incorrectly rejecting a true null hypothesis. This level helps us control the Type I error rate, which is the probability of wrongly concluding there is an effect or difference when in reality, there isn't one.

When you see a level of significance expressed as 0.05, it means that there is a 5% risk of rejecting the null hypothesis incorrectly. This accepted risk is a trade-off; by setting a lower threshold, we can be more confident in the results, though it might also mean needing stronger evidence to justify rejecting the null hypothesis. During a test, such as in the given exercise, when the significance level is 5%, the decision rule is determined using this threshold to draw conclusions after calculating the test statistic.
Null Hypothesis
The **Null Hypothesis** is the cornerstone of statistical hypothesis testing. Designated as \(H_0\), it represents the default or status quo assumption. Typically, it asserts that there is no effect or no difference. For the pH blood level example, \(H_0\) posits that the mean pH level is equal to 7.4.

This hypothesis is set up to be tested and possibly rejected by the data gathered. By assuming no change, researchers maintain a baseline expectation as they look to uncover significant evidence to suggest the contrary. It is imperative to understand the null hypothesis as a "starting point," which allows for a logical method to test against, using available sample data.

In hypothesis testing, the null hypothesis provides a framework for analysis and helps delineate whether any observed effects in the data are due to randomness or actual influence, like the new drug in our scenario.
Alternative Hypothesis
When conducting a hypothesis test, the **Alternative Hypothesis** (\(H_1\)) suggests a different state of nature than what is stated in the null hypothesis. It's the statement researchers aim to prove, and it showcases the possibility of an effect or a difference. Taking from the exercise: if \(H_0\) claims \(\mu = 7.4\), then \(H_1\) proposes \(\mu eq 7.4\).

It indicates that the blood pH is not equal to the benchmark level, due to the drug's effect, if evidence supports it.

In testing contexts, \(H_1\) is what you believe might be true or are researching. When evidence discredits \(H_0\), the alternative hypothesis becomes viable. Its formulation depends on the direction of the research, whether a two-tailed test, as with our exercise, or a one-tailed test, where the interest might be in a specific direction of change. Understanding and accurately framing \(H_1\) is critical to properly analyzing the test results.
t-Distribution
The **t-Distribution** is a valuable tool especially when working with small sample sizes or unknown population variances. It resembles the normal distribution but is more spread out, with heavier tails, which accomodates the extra variability expected from smaller samples.

In the context of hypothesis testing, the t-distribution applies when calculating the t-statistic for small sample sizes, typically below 30, as in the exercise. It helps determine how far away the sample mean is from the population mean, in units of standard error, under the assumption that \(H_0\) is true. This comparison between calculated t-values and the t-distribution allows us to determine whether to reject the null hypothesis.

Key parameters involve the degree of freedom, which is often calculated as \(n - 1\) for a single sample test, where \(n\) is the sample size. Understanding the role of the t-distribution is crucial in effectively evaluating statistical arguments, particularly when standard methods relying on large sample approximations aren't adequate.

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Most popular questions from this chapter

Alisha is conducting a paired differences test for a "before \(\left(B\right.\) score) and after \((A \text { score })^{n}\) situation. She is interested in testing whether the average of the "before" scores is higher than that of the "after" scores. (a) To use a right-tailed test, how should Alisha construct the differences between the "before" and "after" scores? (b) To use a left-tailed test, how should she construct the differences between the "before" and "after" scores?

Consumer Reports stated that the mean time for a Chrysler Concorde to go from 0 to 60 miles per hour is \(8.7\) seconds. (a) If you want to set up a statistical test to challenge the claim of \(8.7\) seconds, what would you use for the null hypothesis? (b) The town of Leadville, Colorado, has an elevation over 10,000 feet. Suppose you wanted to test the claim that the average time to accelerate from 0 to 60 miles per hour is longer in Leadville (because of less oxygen). What would you use for the alternate hypothesis? (c) Suppose you made an engine modification and you think the average time to accelerate from 0 to 60 miles per hour is reduced. What would you use for the alternate hypothesis? (d) For each of the tests in parts (b) and (c), would the \(P\) -value area be on the left, on the right, or on both sides of the mean? Explain your answer in each case. For Problems \(19-24\), please provide the following information. (a) What is the level of significance? State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? (b) What sampling distribution will you use? Explain the rationale for your choice of sampling distribution. Compute the value of the sample test statistic. (c) Find (or estimate) the \(P\) -value. Sketch the sampling distribution and show the area corresponding to the \(P\) -value. (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level \(\alpha\) ? (e) Your conclusion in the context of the application.

Weatherwise magazine is published in association with the American Meteorological Society. Volume 46 , Number 6 has a rating system to classify Nor'easter storms that frequently hit New England states and can cause much damage near the ocean coast. A severe storm has an average peak wave height of \(16.4\) feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating. (a) Let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. What would be the null hypothesis regarding average wave height? (b) If you wanted to test the hypothesis that the storm is getting worse, what would you use for the alternate hypothesis? (c) If you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis? (d) Suppose you do not know whether the storm is getting worse or dying out. You just want to test the hypothesis that the average wave height is different (either higher or lower) from the severe storm class rating. What would you use for the alternate hypothesis? (e) For each of the tests in parts (b), (c), and (d), would the area corresponding to the \(P\) -value be on the left, on the right, or on both sides of the mean? Explain your answer in each case.

What terminology do we use for the probability of rejecting the null hypothesis when it is, in fact, false?

Weatherwise is a magazine published by the American Meteorological Society. One issue gives a rating system used to classify Nor'easter storms that frequently hit New England and can cause much damage near the ocean. A severe storm has an average peak wave height of \(\mu=16.4\) feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating. Peak wave heights are usually measured from land (using binoculars) off fixed cement piers. Suppose that a reading of 36 waves showed an average wave height of \(\bar{x}=17.3\) feet. Previous studies of severe storms indicate that \(\sigma=3.5\) feet. Does this information suggest that the storm is (perhaps temporarily) increasing above the severe rating? Use \(\alpha=0.01\).

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