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Consider two \(\bar{x}\) distributions corresponding to the same \(x\) distribution. The first \(\bar{x}\) distribution is based on samples of size \(n=100\) and the second is based on samples of size \(n=225\). Which \(\bar{x}\) distribution has the smaller standard error? Explain.

Short Answer

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The \\(\bar{x}\\) distribution with sample size \\(n=225\\) has a smaller standard error.

Step by step solution

01

Understanding the Problem

We are given two sample means, \(\bar{x}\), corresponding to the same population distribution. The first sample mean distribution is based on a sample size of \(n=100\) and the second on \(n=225\). We need to find which sample mean distribution has a smaller standard error.
02

Recall the Formula for Standard Error

The standard error (SE) of the sample mean is calculated using the formula: \(SE = \frac{\sigma}{\sqrt{n}}\), where \(\sigma\) is the standard deviation of the population and \(n\) is the sample size. However, in this case, \(\sigma\) is not given; yet this does not affect comparison since it's a constant in both scenarios.
03

Calculate the Standard Error for Each Distribution

For the first distribution with \(n=100\), the standard error is \(SE_1 = \frac{\sigma}{\sqrt{100}} = \frac{\sigma}{10}\). For the second distribution with \(n=225\), the standard error is \(SE_2 = \frac{\sigma}{\sqrt{225}} = \frac{\sigma}{15}\).
04

Compare the Standard Errors

Since \(SE_1 = \frac{\sigma}{10} \) and \(SE_2 = \frac{\sigma}{15} \), and knowing that both formulas have the same \(\sigma\), divide the expressions: \( \frac{\frac{\sigma}{15}}{\frac{\sigma}{10}} = \frac{10}{15} = \frac{2}{3} \), therefore \(SE_2 < SE_1\). Thus, the second distribution has a smaller standard error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean, denoted as \(\bar{x}\), is a key concept in statistics. It represents the average value of a set of observations from a sample. To compute it, sum all the sample values and divide by the number of observations in the sample. This is a fundamental measure of central tendency, providing insight into the overall trend of the data you’re analyzing.

The formula for calculating the sample mean is:
  • \(\bar{x} = \frac{\sum_{i=1}^{n} x_i}{n}\)
Here, \(x_i\) represents each value in the sample, and \(n\) is the sample size. The sample mean is useful because it serves as an estimate of the population mean, which is often unknown.

Understanding the sample mean is crucial when you analyze data because it helps in identifying the position of the dataset in terms of its average or center value. This is particularly important as it feeds into calculations such as the standard error.
Standard Error
The standard error (SE) is a crucial statistical tool that measures the precision of the sample mean. It indicates how much the sample mean would vary if you were to take multiple samples from the same population. To obtain the standard error, use the following formula:
  • \(SE = \frac{\sigma}{\sqrt{n}}\)
Here, \(\sigma\) is the population standard deviation, and \(n\) is the sample size.

The standard error plays a vital role in inferential statistics, as it helps gauge the accuracy of the sample mean as an estimate of the population mean. A smaller standard error indicates a more precise estimate. In situations where the population standard deviation is unknown, which is common, the sample standard deviation may be used instead. This approximation allows for continued analysis when exact values are not available. In practice, the standard error aids in constructing confidence intervals and hypothesis testing.
Sample Size
The sample size \(n\) refers to the number of observations or data points collected in a sample. It's a critical factor because it can significantly influence the results of statistical analyses and the reliability of conclusions drawn from a dataset.

Larger sample sizes generally yield more reliable and accurate results because they tend to be more representative of the population. This is particularly important when calculating the standard error. Since the standard error is inversely proportional to the square root of the sample size \(\sqrt{n}\), increasing \(n\) reduces the standard error, thus providing a more precise estimate of the population mean.Here are some key impacts of sample size:
  • Reduces variability in sample means: As \(n\) increases, the variability of sample mean distributions decreases.
  • Improves precision: Larger samples enable more accurate estimates due to smaller standard errors.
  • Influences statistical power: Higher sample sizes increase the chances of detecting a true effect when conducting hypothesis tests.
Selecting the appropriate sample size is vital to ensure that statistical conclusions are valid and reliable.

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Most popular questions from this chapter

How can relative frequencies be used to help us estimate probabilities occurring in sampling distributions?

Consider a binomial experiment with 20 trials and probability \(0.45\) of success on a single trial. (a) Use the binomial distribution to find the probability of exactly 10 successes. (b) Use the normal distribution to approximate the probability of exactly 10 successes. (c) Compare the results of parts (a) and (b).

Suppose an \(x\) distribution has mean \(\mu=5 .\) Consider two corresponding \(\bar{x}\) distributions, the first based on samples of size \(n=49\) and the second based on samples of size \(n=81\). (a) What is the value of the mean of each of the two \(\bar{x}\) distributions? (b) For which \(\bar{x}\) distribution is \(P(\bar{x}>6)\) smaller? Explain. (c) For which \(\bar{x}\) distribution is \(P(4<\bar{x}<6)\) greater? Explain.

It is estimated that \(3.5 \%\) of the general population will live past their 9 th birthday (Statistical Abstract of the United States, 112 th Edition). In a graduating class of 753 high school seniors, what is the probability that (a) 15 or more will live beyond their 90 th birthday? (b) 30 or more will live beyond their 90 th birthday? (c) between 25 and 35 will live beyond their 90 th birthday? (d) more than 40 will live beyond their 90 th birthday?

Suppose we have a binomial experiment with \(n=40\) trials and probability of success \(p=0.85\) (a) Is it appropriate to use a normal approximation to this binomial distribution? Why? (b) Compute \(\mu\) and \(\sigma\) of the approximating normal distribution. (c) Use a continuity correction factor to convert the statement \(r<30\) successes to a statement about the corresponding normal variable \(x\). (d) Estimate \(P(r<30)\). (e) Is it unusual for a binomial experiment with 40 trials and probability of success \(0.85\) to have fewer than 30 successes? Explain.

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